Getal & Ruimte (12e editie) - havo wiskunde A
'Breuken herleiden'.
| 2 havo/vwo | 1.2 Breuken optellen |
opgave 1Herleid tot één breuk. 1p a \({8 \over 7 a} + {9 \over 7 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({8 \over 7 a} + {9 \over 7 a} = {17 \over 7 a}\) 1p 1p b \({4 \over x} + {5 \over 9 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({4 \over x} + {5 \over 9 x} = {36 \over 9 x} + {5 \over 9 x} = {41 \over 9 x}\) 1p 1p c \({2 \over 8 p} - {5 \over 7 q}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({2 \over 8 p} - {5 \over 7 q} = {14 q \over 56 p q} - {40 p \over 56 p q} = {14 q - 40 p \over 56 p q} = {7 q - 20 p \over 28 p q}\) 1p 1p d \(7 - {8 \over 9 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(7 - {8 \over 9 a} = {7 \over 1} - {8 \over 9 a} = {63 a \over 9 a} - {8 \over 9 a} = {63 a - 8 \over 9 a}\) 1p opgave 2Herleid tot één breuk. 1p a \(6 x - {5 \over 2 x}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(6 x - {5 \over 2 x} = {6 x \over 1} ⋅ {2 x \over 2 x} - {5 \over 2 x} = {12 x^{2} \over 2 x} - {5 \over 2 x} = {12 x^{2} - 5 \over 2 x}\) 1p 1p b \({8 x \over y} - {7 \over 5 y}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables b \({8 x \over y} - {7 \over 5 y} = {40 x \over 5 y} - {7 \over 5 y} = {40 x - 7 \over 5 y}\) 1p 1p c \({9 y \over 3 x} - {2 x \over 8 y}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables c \({9 y \over 3 x} - {2 x \over 8 y} = {72 y^{2} \over 24 x y} - {6 x^{2} \over 24 x y} = {-6 x^{2} + 72 y^{2} \over 24 x y} = {-x^{2} + 12 y^{2} \over 4 x y}\) 1p opgave 3Herleid. 1p a \({8 a \over a}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({8 a \over a} = {8 \over 1} = 8\) 1p 1p b \({p \over 8 p}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({p \over 8 p} = {1 \over 8}\) 1p 1p c \({6 a \over -9 a}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({6 a \over -9 a} = -\frac{2}{3}\) 1p 1p d \({12 a \over 2 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({12 a \over 2 a} = 6\) 1p opgave 4Herleid. 1p a \({12 p q \over -16 p r}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({12 p q \over -16 p r} = -{3 q \over 4 r}\) 1p 1p b \({25 y \over -45 x y}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({25 y \over -45 x y} = -{5 \over 9 x}\) 1p 1p c \({-25 x y z \over -5 y z}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({-25 x y z \over -5 y z} = 5 x\) 1p 1p d \({2 a b \over b} - {5 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({2 a b \over b} - {5 a c \over c} = 2 a - 5 a = -3 a\) 1p |
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| 2 havo/vwo | 1.3 Breuken vermenigvuldigen en delen |
opgave 1Herleid tot één breuk. 1p a \({9 \over a} ⋅ -{7 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables a \({9 \over a} ⋅ -{7 \over b} = -{63 \over a b}\) 1p 1p b \({x \over 9} ⋅ -{8 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 9} ⋅ -{8 \over y} = -{8 x \over 9 y}\) 1p 1p c \(-{5 \over 6} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables c \(-{5 \over 6} ⋅ a = -{5 a \over 6}\) 1p 1p d \({9 \over x} : {5 \over y}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables d \({9 \over x} : {5 \over y} = {9 \over x} ⋅ {y \over 5} = {9 y \over 5 x}\) 1p opgave 2Herleid tot één breuk. 1p \(-{8 \over 3} : p\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables ○ \(-{8 \over 3} : p = -{8 \over 3} : {p \over 1} = -{8 \over 3} ⋅ {1 \over p} = -{8 \over 3 p}\) 1p |
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| 3 havo | 5.2 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({8 p \over 9} + {p + 6 \over 4}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({8 p \over 9} + {p + 6 \over 4} = {32 p \over 36} + {9 (p + 6) \over 36} = {32 p + 9 (p + 6) \over 36} = {41 p + 54 \over 36}\) 1p |
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| havo wiskunde A | 6.3 Formules met breuken |
opgave 1Herleid tot één breuk. 1p a \({9 y \over x} ⋅ {x + 7 \over 8}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables a \({9 y \over x} ⋅ {x + 7 \over 8} = {9 y (x + 7) \over 8 x} = {9 x y + 63 y \over 8 x}\) 1p 1p b \({2 \over 9} : {p - 4 q \over q}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables b \({2 \over 9} : {p - 4 q \over q} = {2 \over 9} ⋅ {q \over p - 4 q} = {2 q \over 9 (p - 4 q)} = {2 q \over 9 p - 36 q}\) 1p |
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| havo wiskunde A | 11.2 Herleiden en combineren van formules |
opgave 1Deel uit. 1p a \({6 x^{2} + 2 x + 40 \over 2 x}\) Uitdelen (1) 00ei - Breuken herleiden - basis - 0ms - dynamic variables a \({6 x^{2} + 2 x + 40 \over 2 x} = {6 x^{2} \over 2 x} + {2 x \over 2 x} + {40 \over 2 x} = 3 x + 1 + {20 \over x}\) 1p 1p b \({3 a^{2} + a + 6 \over 8 a^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables b \({3 a^{2} + a + 6 \over 8 a^{2}} = {3 a^{2} \over 8 a^{2}} + {a \over 8 a^{2}} + {6 \over 8 a^{2}} = \frac{3}{8} + {1 \over 8 a} + {3 \over 4 a^{2}}\) 1p |