\({4 \over 7 x} - {6 \over 7 x} = -{2 \over 7 x}\)

\({6 \over a} + {4 \over 8 a} = {48 \over 8 a} + {4 \over 8 a} = {52 \over 8 a} = {13 \over 2 a}\)

\({8 \over 6 x} + {5 \over 7 y} = {56 y \over 42 x y} + {30 x \over 42 x y} = {56 y + 30 x \over 42 x y} = {28 y + 15 x \over 21 x y}\)

\(4 - {8 \over 3 a} = {4 \over 1} - {8 \over 3 a} = {12 a \over 3 a} - {8 \over 3 a} = {12 a - 8 \over 3 a}\)

\(7 p - {9 \over 5 p} = {7 p \over 1} ⋅ {5 p \over 5 p} - {9 \over 5 p} = {35 p^{2} \over 5 p} - {9 \over 5 p} = {35 p^{2} - 9 \over 5 p}\)

\({6 a \over b} + {9 \over 3 b} = {18 a \over 3 b} + {9 \over 3 b} = {18 a + 9 \over 3 b} = {6 a + 3 \over b}\)

\({3 q \over 9 p} + {7 p \over 6 q} = {6 q^{2} \over 18 p q} + {21 p^{2} \over 18 p q} = {21 p^{2} + 6 q^{2} \over 18 p q} = {7 p^{2} + 2 q^{2} \over 6 p q}\)

\({6 x \over x} = {6 \over 1} = 6\)

\({a \over 8 a} = {1 \over 8}\)

\({-4 x \over 18 x} = -\frac{2}{9}\)

\({-27 x \over -3 x} = 9\)

\({10 x y \over -18 x z} = -{5 y \over 9 z}\)

\({16 b \over 18 a b} = {8 \over 9 a}\)

\({10 a b c \over -5 b c} = -2 a\)

\({2 p q \over q} + {7 p r \over r} = 2 p + 7 p = 9 p\)

\({6 \over p} ⋅ {7 \over q} = {42 \over p q}\)

\({x \over 3} ⋅ {9 \over y} = {9 x \over 3 y} = {3 x \over y}\)

\(-{8 \over 9} ⋅ a = -{8 a \over 9}\)

\({2 \over x} : {7 \over y} = {2 \over x} ⋅ {y \over 7} = {2 y \over 7 x}\)

\({3 \over 4} : a = {3 \over 4} : {a \over 1} = {3 \over 4} ⋅ {1 \over a} = {3 \over 4 a}\)

\({9 x \over 2} + {x + 1 \over 5} = {45 x \over 10} + {2 (x + 1) \over 10} = {45 x + 2 (x + 1) \over 10} = {47 x + 2 \over 10}\)

\({5 y \over x} ⋅ {x + 2 \over 3} = {5 y (x + 2) \over 3 x} = {5 x y + 10 y \over 3 x}\)

\({6 \over 5} : {a + 2 b \over b} = {6 \over 5} ⋅ {b \over a + 2 b} = {6 b \over 5 (a + 2 b)} = {6 b \over 5 a + 10 b}\)

\({4 a^{2} + 6 a - 20 \over 2 a} = {4 a^{2} \over 2 a} + {6 a \over 2 a} - {20 \over 2 a} = 2 a + 3 - {10 \over a}\)

\({2 p^{2} - 4 p - 9 \over p^{2}} = {2 p^{2} \over p^{2}} - {4 p \over p^{2}} - {9 \over p^{2}} = 2 - {4 \over p} - {9 \over p^{2}}\)