\(\sqrt{112}=\sqrt{16}⋅\sqrt{7}=4\sqrt{7}\text{.}\)

\(-2\sqrt{48}=-2⋅\sqrt{16}⋅\sqrt{3}=-2⋅4⋅\sqrt{3}=-8\sqrt{3}\text{.}\)

\(\sqrt{\frac{4}{49}}={\sqrt{4} \over \sqrt{49}}=\frac{2}{7}\text{.}\)

\(\sqrt{1\frac{8}{25}}=\sqrt{\frac{33}{25}}={\sqrt{33} \over \sqrt{25}}={\sqrt{33} \over 5}=\frac{1}{5}\sqrt{33}\text{.}\)