\({3 \over 7 x} + {8 \over 7 x} = {11 \over 7 x}\)

\({8 \over a} - {6 \over 4 a} = {32 \over 4 a} - {6 \over 4 a} = {26 \over 4 a} = {13 \over 2 a}\)

\({3 \over 9 a} + {2 \over 6 b} = {6 b \over 18 a b} + {6 a \over 18 a b} = {6 b + 6 a \over 18 a b} = {b + a \over 3 a b}\)

\(7 + {9 \over 4 p} = {7 \over 1} + {9 \over 4 p} = {28 p \over 4 p} + {9 \over 4 p} = {28 p + 9 \over 4 p}\)

\(2 x + {5 \over 6 x} = {2 x \over 1} ⋅ {6 x \over 6 x} + {5 \over 6 x} = {12 x^{2} \over 6 x} + {5 \over 6 x} = {12 x^{2} + 5 \over 6 x}\)

\({8 a \over b} - {4 \over 2 b} = {16 a \over 2 b} - {4 \over 2 b} = {16 a - 4 \over 2 b} = {8 a - 2 \over b}\)

\({8 q \over 6 p} - {9 p \over 4 q} = {16 q^{2} \over 12 p q} - {27 p^{2} \over 12 p q} = {-27 p^{2} + 16 q^{2} \over 12 p q}\)

\({5 a \over a} = {5 \over 1} = 5\)

\({x \over 8 x} = {1 \over 8}\)

\({-12 x \over 14 x} = -\frac{6}{7}\)

\({-28 a \over 4 a} = -7\)

\({12 x y \over -27 x z} = -{4 y \over 9 z}\)

\({16 b \over -18 a b} = -{8 \over 9 a}\)

\({15 p q r \over 5 q r} = 3 p\)

\({5 x y \over y} - {7 x z \over z} = 5 x - 7 x = -2 x\)

\({2 \over a} ⋅ -{9 \over b} = -{18 \over a b}\)

\({x \over 3} ⋅ {6 \over y} = {6 x \over 3 y} = {2 x \over y}\)

\(-{2 \over 9} ⋅ a = -{2 a \over 9}\)

\({3 \over x} : {8 \over y} = {3 \over x} ⋅ {y \over 8} = {3 y \over 8 x}\)

\({1 \over 4} : p = {1 \over 4} : {p \over 1} = {1 \over 4} ⋅ {1 \over p} = {1 \over 4 p}\)

\({9 p \over 4} + {p + 6 \over 5} = {45 p \over 20} + {4 (p + 6) \over 20} = {45 p + 4 (p + 6) \over 20} = {49 p + 24 \over 20}\)

\({4 a + 6 \over -9 a - 8} - 1 = {4 a + 6 \over -9 a - 8} + {-1 (-9 a - 8) \over -9 a - 8} = {4 a + 6 - 1 (-9 a - 8) \over -9 a - 8} = {4 a + 6 + 9 a + 8 \over -9 a - 8} = {13 a + 14 \over -9 a - 8}\)

\({2 p^{2} + p - 30 \over p} = {2 p^{2} \over p} + {p \over p} - {30 \over p} = 2 p + 1 - {30 \over p}\)

\({6 a^{2} - 7 a - 8 \over 2 a^{2}} = {6 a^{2} \over 2 a^{2}} - {7 a \over 2 a^{2}} - {8 \over 2 a^{2}} = 3 - {7 \over 2 a} - {4 \over a^{2}}\)