Getal & Ruimte (12e editie) - havo wiskunde B
'Breuken herleiden'.
| 2 havo/vwo | 1.2 Breuken optellen |
opgave 1Herleid tot één breuk. 1p a \({6 \over 9 a} + {7 \over 9 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({6 \over 9 a} + {7 \over 9 a} = {13 \over 9 a}\) 1p 1p b \({7 \over p} + {5 \over 6 p}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({7 \over p} + {5 \over 6 p} = {42 \over 6 p} + {5 \over 6 p} = {47 \over 6 p}\) 1p 1p c \({4 \over 8 x} - {9 \over 6 y}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({4 \over 8 x} - {9 \over 6 y} = {12 y \over 24 x y} - {36 x \over 24 x y} = {12 y - 36 x \over 24 x y} = {y - 3 x \over 2 x y}\) 1p 1p d \(7 + {5 \over 3 x}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(7 + {5 \over 3 x} = {7 \over 1} + {5 \over 3 x} = {21 x \over 3 x} + {5 \over 3 x} = {21 x + 5 \over 3 x}\) 1p opgave 2Herleid tot één breuk. 1p a \(6 a + {3 \over 8 a}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(6 a + {3 \over 8 a} = {6 a \over 1} ⋅ {8 a \over 8 a} + {3 \over 8 a} = {48 a^{2} \over 8 a} + {3 \over 8 a} = {48 a^{2} + 3 \over 8 a}\) 1p 1p b \({8 a \over b} + {6 \over 7 b}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables b \({8 a \over b} + {6 \over 7 b} = {56 a \over 7 b} + {6 \over 7 b} = {56 a + 6 \over 7 b}\) 1p 1p c \({3 b \over 2 a} + {4 a \over 8 b}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables c \({3 b \over 2 a} + {4 a \over 8 b} = {12 b^{2} \over 8 a b} + {4 a^{2} \over 8 a b} = {4 a^{2} + 12 b^{2} \over 8 a b} = {a^{2} + 3 b^{2} \over 2 a b}\) 1p opgave 3Herleid. 1p a \({6 p \over p}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({6 p \over p} = {6 \over 1} = 6\) 1p 1p b \({x \over 9 x}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 9 x} = {1 \over 9}\) 1p 1p c \({-9 x \over 21 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({-9 x \over 21 x} = -\frac{3}{7}\) 1p 1p d \({-36 p \over 4 p}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-36 p \over 4 p} = -9\) 1p opgave 4Herleid. 1p a \({40 x y \over 45 x z}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({40 x y \over 45 x z} = {8 y \over 9 z}\) 1p 1p b \({8 y \over -28 x y}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({8 y \over -28 x y} = -{2 \over 7 x}\) 1p 1p c \({14 a b c \over 2 b c}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({14 a b c \over 2 b c} = 7 a\) 1p 1p d \({3 a b \over b} + {7 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({3 a b \over b} + {7 a c \over c} = 3 a + 7 a = 10 a\) 1p |
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| 2 havo/vwo | 1.3 Breuken vermenigvuldigen en delen |
opgave 1Herleid tot één breuk. 1p a \({7 \over a} ⋅ {8 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables a \({7 \over a} ⋅ {8 \over b} = {56 \over a b}\) 1p 1p b \({x \over 3} ⋅ -{6 \over y}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 3} ⋅ -{6 \over y} = -{6 x \over 3 y} = -{2 x \over y}\) 1p 1p c \(-{1 \over 4} ⋅ p\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables c \(-{1 \over 4} ⋅ p = -{p \over 4}\) 1p 1p d \({3 \over x} : {5 \over y}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables d \({3 \over x} : {5 \over y} = {3 \over x} ⋅ {y \over 5} = {3 y \over 5 x}\) 1p opgave 2Herleid tot één breuk. 1p \({8 \over 7} : a\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({8 \over 7} : a = {8 \over 7} : {a \over 1} = {8 \over 7} ⋅ {1 \over a} = {8 \over 7 a}\) 1p |
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| 3 havo | 5.2 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({4 x \over 5} + {x + 6 \over 7}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables ○ \({4 x \over 5} + {x + 6 \over 7} = {28 x \over 35} + {5 (x + 6) \over 35} = {28 x + 5 (x + 6) \over 35} = {33 x + 30 \over 35}\) 1p |
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| havo wiskunde B | 11.5 Gebroken functies |
opgave 1Herleid tot één breuk. 1p \({-9 p - 2 \over -8 p - 1} + 7\) Optellen (9) 00eh - Breuken herleiden - basis - 0ms - dynamic variables ○ \({-9 p - 2 \over -8 p - 1} + 7 = {-9 p - 2 \over -8 p - 1} - {-7 (-8 p - 1) \over -8 p - 1} = {-9 p - 2 + 7 (-8 p - 1) \over -8 p - 1} = {-9 p - 2 - 56 p - 7 \over -8 p - 1} = {-65 p - 9 \over -8 p - 1}\) 1p opgave 2Deel uit. 1p a \({3 x^{2} - 9 x + 60 \over 3 x}\) Uitdelen (1) 00ei - Breuken herleiden - basis - 0ms - dynamic variables a \({3 x^{2} - 9 x + 60 \over 3 x} = {3 x^{2} \over 3 x} - {9 x \over 3 x} + {60 \over 3 x} = x - 3 + {20 \over x}\) 1p 1p b \({7 x^{2} + x + 5 \over 4 x^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables b \({7 x^{2} + x + 5 \over 4 x^{2}} = {7 x^{2} \over 4 x^{2}} + {x \over 4 x^{2}} + {5 \over 4 x^{2}} = 1\frac{3}{4} + {1 \over 4 x} + {5 \over 4 x^{2}}\) 1p |