\({2 \over 9 p} + {7 \over 9 p} = {9 \over 9 p} = {1 \over p}\)

\({3 \over a} - {7 \over 2 a} = {6 \over 2 a} - {7 \over 2 a} = -{1 \over 2 a}\)

\({8 \over 6 a} + {3 \over 5 b} = {40 b \over 30 a b} + {18 a \over 30 a b} = {40 b + 18 a \over 30 a b} = {20 b + 9 a \over 15 a b}\)

\(9 - {7 \over 8 x} = {9 \over 1} - {7 \over 8 x} = {72 x \over 8 x} - {7 \over 8 x} = {72 x - 7 \over 8 x}\)

\(5 x + {2 \over 7 x} = {5 x \over 1} ⋅ {7 x \over 7 x} + {2 \over 7 x} = {35 x^{2} \over 7 x} + {2 \over 7 x} = {35 x^{2} + 2 \over 7 x}\)

\({3 a \over b} - {2 \over 9 b} = {27 a \over 9 b} - {2 \over 9 b} = {27 a - 2 \over 9 b}\)

\({6 b \over 8 a} - {2 a \over 4 b} = {6 b^{2} \over 8 a b} - {4 a^{2} \over 8 a b} = {-4 a^{2} + 6 b^{2} \over 8 a b} = {-2 a^{2} + 3 b^{2} \over 4 a b}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({x \over 4 x} = {1 \over 4}\)

\({6 p \over -16 p} = -\frac{3}{8}\)

\({-24 a \over 4 a} = -6\)

\({15 x y \over -20 x z} = -{3 y \over 4 z}\)

\({12 y \over -20 x y} = -{3 \over 5 x}\)

\({-12 a b c \over 2 b c} = -6 a\)

\({2 p q \over q} - {7 p r \over r} = 2 p - 7 p = -5 p\)

\({8 \over p} ⋅ {2 \over q} = {16 \over p q}\)

\({x \over 6} ⋅ {2 \over y} = {2 x \over 6 y} = {x \over 3 y}\)

\(-{2 \over 7} ⋅ x = -{2 x \over 7}\)

\({2 \over a} : {4 \over b} = {2 \over a} ⋅ {b \over 4} = {2 b \over 4 a} = {b \over 2 a}\)

\({5 \over 2} : a = {5 \over 2} : {a \over 1} = {5 \over 2} ⋅ {1 \over a} = {5 \over 2 a}\)

\({8 x \over 9} + {x + 4 \over 7} = {56 x \over 63} + {9 (x + 4) \over 63} = {56 x + 9 (x + 4) \over 63} = {65 x + 36 \over 63}\)

\({6 p - 1 \over -5 p - 8} + 3 = {6 p - 1 \over -5 p - 8} - {-3 (-5 p - 8) \over -5 p - 8} = {6 p - 1 + 3 (-5 p - 8) \over -5 p - 8} = {6 p - 1 - 15 p - 24 \over -5 p - 8} = {-9 p - 25 \over -5 p - 8}\)

\({2 x^{2} - 3 x + 10 \over x} = {2 x^{2} \over x} - {3 x \over x} + {10 \over x} = 2 x - 3 + {10 \over x}\)

\({8 x^{2} + 9 x - 3 \over 2 x^{2}} = {8 x^{2} \over 2 x^{2}} + {9 x \over 2 x^{2}} - {3 \over 2 x^{2}} = 4 + {9 \over 2 x} - {3 \over 2 x^{2}}\)