Getal & Ruimte (12e editie) - havo wiskunde B

'Logaritmische formules herleiden'.

havo wiskunde B 9.2 Werken met logaritmen

Logaritmische formules herleiden (1)

opgave 1

Druk \(x\) uit in \(y \text{.}\)

3p

\(y = 20 + 4 ⋅ {}^{7}\!\log(8 x - 9)\)

Vrijmaken
00kn - Logaritmische formules herleiden - basis - 0ms - dynamic variables

○

\(y = 20 + 4 ⋅ {}^{7}\!\log(8 x - 9)\)
\(4 ⋅ {}^{7}\!\log(8 x - 9) = y - 20\)
\({}^{7}\!\log(8 x - 9) = \frac{1}{4} y - 5\)

1p

○

\(8 x - 9 = 7^{\frac{1}{4} y - 5}\)

1p

○

\(8 x = 7^{\frac{1}{4} y - 5} + 9\)
\(x = \frac{1}{8} ⋅ 7^{\frac{1}{4} y - 5} + 1\frac{1}{8}\)

1p

havo wiskunde B 9.3 Rekenregels voor logaritmen

Logaritmische formules herleiden (4)

opgave 1

Herleid tot de gevraagde vorm.

3p

a

Schrijf de formule \(y = 3{,}52 ⋅ {}^{3}\!\log(x) + 1{,}76\) in de vorm \(y = {}^{3}\!\log(a x^{b}) \text{.}\)
Geef \(a\) en \(b\) in twee decimalen.

Herleiden (4)
00l0 - Logaritmische formules herleiden - basis - 0ms - dynamic variables

a

\(y = 3{,}52 ⋅ {}^{3}\!\log(x) + 1{,}76\)
\(\text{ } = {}^{3}\!\log(x^{3{,}52}) + 1{,}76\)

1p

○

\(\text{ } = {}^{3}\!\log(x^{3{,}52}) + {}^{3}\!\log(3^{1{,}76})\)
\(\text{ } = {}^{3}\!\log(x^{3{,}52} ⋅ 3^{1{,}76})\)

1p

○

\(\text{ } = {}^{3}\!\log(x^{3{,}52} ⋅ 6{,}914...)\)
Dus \(y = {}^{3}\!\log(6{,}91 ⋅ x^{3{,}52}) \text{.}\)

1p

3p

b

Schrijf de formule \(y = {}^{5}\!\log({59 \over x^{3}})\) in de vorm \(y = a + b ⋅ {}^{5}\!\log(x) \text{.}\)
Geef \(a\) in twee decimalen.

Herleiden (5)
00l1 - Logaritmische formules herleiden - basis - 0ms - dynamic variables

b

\(y = {}^{5}\!\log({59 \over x^{3}})\)
\(\text{ } = {}^{5}\!\log(59 x^{-3})\)

1p

○

\(\text{ } = {}^{5}\!\log(59) + {}^{5}\!\log(x^{-3})\)
\(\text{ } = {}^{5}\!\log(59) - 3 ⋅ {}^{5}\!\log(x)\)

1p

○

\(\text{ } = 2{,}533... - 3 ⋅ {}^{5}\!\log(x)\)
Dus \(y = 2{,}53 - 3 ⋅ {}^{5}\!\log(x) \text{.}\)

1p

3p

c

Schrijf de formule \(y = {}^{4}\!\log(1{,}7 x) + 1{,}2\) in de vorm \(y = a + b ⋅ {}^{3}\!\log(x) \text{.}\)
Geef \(a\) en \(b\) in twee decimalen.

Herleiden (6)
00l2 - Logaritmische formules herleiden - basis - 0ms - dynamic variables

c

\(y = {}^{4}\!\log(1{,}7 x) + 1{,}2\)
\(\text{ } = {}^{4}\!\log(1{,}7) + {}^{4}\!\log(x) + 1{,}2\)

1p

○

\(\text{ } = {}^{4}\!\log(1{,}7) + 1{,}2 + {{}^{3}\!\log(x) \over {}^{3}\!\log(4)}\)
\(\text{ } = {}^{4}\!\log(1{,}7) + 1{,}2 + {1 \over {}^{3}\!\log(4)} ⋅ {}^{3}\!\log(x)\)

1p

○

\(\text{ } = 0{,}382... + 1{,}2 + {1 \over 1{,}261...} ⋅ {}^{3}\!\log(x)\)
\(\text{ } = 1{,}582... + 0{,}792... ⋅ {}^{3}\!\log(x)\)
Dus \(y = 1{,}58 + 0{,}79 ⋅ {}^{3}\!\log(x) \text{.}\)

1p

3p

d

Schrijf de formule \(y = 7 ⋅ \log(30\,000 x) + 5\) in de vorm \(y = a + b ⋅ \log(3 x) \text{.}\)

Herleiden (7)
00l3 - Logaritmische formules herleiden - basis - 0ms - dynamic variables

d

\(y = 7 ⋅ \log(30\,000 x) + 5\)
\(\text{ } = 7 ⋅ (\log(10\,000) + \log(3 x)) + 5\)

1p

○

\(\text{ } = 7 ⋅ (4 + \log(3 x)) + 5\)

1p

○

\(\text{ } = 28 + 7 ⋅ \log(3 x) + 5\)
\(\text{ } = 33 + 7 ⋅ \log(3 x)\)

1p

havo wiskunde B 9.4 Formules omwerken

Logaritmische formules herleiden (6)

opgave 1

Herleid tot de gevraagde vorm.

3p

a

Schrijf de formule \(y = 7\,300 ⋅ 0{,}92^{x}\) in de vorm \(\log(y) = a x + b \text{.}\)
Geef \(a\) in vier decimalen en \(b\) in twee decimalen.

Herleiden (1)
00ko - Logaritmische formules herleiden - basis - 0ms - dynamic variables

a

\(y = 7\,300 ⋅ 0{,}92^{x}\)
\(\log(y) = \log(7\,300 ⋅ 0{,}92^{x})\)
\(\log(y) = \log(7\,300) + \log(0{,}92^{x})\)

1p

○

\(\log(y) = \log(7\,300) + x ⋅ \log(0{,}92)\)

1p

○

\(\log(y) = 3{,}863... + x ⋅ -0{,}03621...\)
Dus \(\log(y) = -0{,}0362 x + 3{,}86\)

1p

3p

b

Schrijf de formule \(y = 5\,900 ⋅ 0{,}94^{3 x + 2}\) in de vorm \(\log(y) = a x + b \text{.}\)
Geef \(a\) in vier decimalen en \(b\) in twee decimalen.

Herleiden (2)
00kp - Logaritmische formules herleiden - basis - 0ms - dynamic variables

b

\(y = 5\,900 ⋅ 0{,}94^{3 x + 2}\)
\(\log(y) = \log(5\,900 ⋅ 0{,}94^{3 x + 2})\)
\(\log(y) = \log(5\,900) + \log(0{,}94^{3 x + 2})\)

1p

○

\(\log(y) = \log(5\,900) + (3 x + 2) ⋅ \log(0{,}94)\)
\(\log(y) = \log(5\,900) + 3 x ⋅ \log(0{,}94) + 2 ⋅ \log(0{,}94)\)

1p

○

\(\log(y) = 3{,}770... + 3 x ⋅ -0{,}02687... + 2 ⋅ -0{,}02687...\)
\(\log(y) = 3{,}770... - 0{,}08061... ⋅ x - 0{,}05374...\)
Dus \(\log(y) = -0{,}0806 x + 3{,}72\)

1p

3p

c

Schrijf de formule \(\log(y) = 0{,}1205 x + 3{,}79\) in de vorm \(y = b ⋅ g^{x} \text{.}\)
Geef \(b\) in gehelen en \(g\) in twee decimalen.

Herleiden (3)
00kq - Logaritmische formules herleiden - basis - 0ms - dynamic variables

c

\(\log(y) = 0{,}1205 x + 3{,}79\)
\(y = 10^{0{,}1205 x + 3{,}79}\)

1p

○

\(y = 10^{0{,}1205 x} ⋅ 10^{3{,}79}\)
\(y = (10^{0{,}1205})^{x} ⋅ 10^{3{,}79}\)

1p

○

\(y = 1{,}319...^{x} ⋅ 6165{,}950...\)
Dus \(y = 6\,166 ⋅ 1{,}32^{x} \text{.}\)

1p

3p

d

Schrijf de formule \(\log(y) = 1{,}12 + 1{,}16 ⋅ \log(x)\) in de vorm \(y = a x^{b} \text{.}\)
Geef \(a\) in gehelen.

Dubbel (3)
00kr - Logaritmische formules herleiden - basis - 0ms - dynamic variables

d

\(\log(y) = 1{,}12 + 1{,}16 ⋅ \log(x)\)
\(\log(y) = \log(10^{1{,}12}) + \log(x^{1{,}16})\)
\(\log(y) = \log(10^{1{,}12} ⋅ x^{1{,}16})\)

1p

○

\(y = 10^{1{,}12} ⋅ x^{1{,}16}\)

1p

○

\(y = 13{,}182... ⋅ x^{1{,}16}\)
Dus \(y = 13 ⋅ x^{1{,}16} \text{.}\)

1p

opgave 2

Herleid tot de gevraagde vorm.

3p

a

Schrijf de formule \(y = 700 x^{1{,}34}\) in de vorm \(\log(y) = a + b ⋅ \log(x) \text{.}\)
Geef \(a\) in twee decimalen.

Dubbel (1)
00ks - Logaritmische formules herleiden - basis - 0ms - dynamic variables

a

\(y = 700 x^{1{,}34}\)
\(\log(y) = \log(700 x^{1{,}34})\)

1p

○

\(\log(y) = \log(700) + \log(x^{1{,}34})\)
\(\log(y) = \log(700) + 1{,}34 ⋅ \log(x)\)

1p

○

\(\log(y) = 2{,}845... + 1{,}34 ⋅ \log(x)\)
Dus \(y = 2{,}85 + 1{,}34 ⋅ \log(x) \text{.}\)

1p

3p

b

Schrijf de formule \(y = {180 \over x^{5}}\) in de vorm \(\log(y) = a + b ⋅ \log(x) \text{.}\)
Geef \(a\) in twee decimalen.

Dubbel (2)
00kt - Logaritmische formules herleiden - basis - 0ms - dynamic variables

b

\(y = {180 \over x^{5}} = 180 x^{-5}\)
\(\log(y) = \log(180 x^{-5})\)

1p

○

\(\log(y) = \log(180) + \log(x^{-5})\)
\(\log(y) = \log(180) - 5 ⋅ \log(x)\)

1p

○

\(\log(y) = 2{,}255... - 5 ⋅ \log(x)\)
Dus \(y = 2{,}26 - 5 ⋅ \log(x) \text{.}\)

1p

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