Getal & Ruimte (12e editie) - havo wiskunde B
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 39 \text{,}\) \(\angle R = 43\degree\) en \(\angle P = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(43\degree) = {P\kern{-.8pt}Q \over 39} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}Q = 39 ⋅ \tan(43\degree) \text{.}\) 1p ○ Dus \(P\kern{-.8pt}Q ≈ 36{,}4 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 52 \text{,}\) \(\angle P = 52\degree\) en \(\angle Q = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\tan(52\degree) = {52 \over P\kern{-.8pt}Q} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}Q = {52 \over \tan(52\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}Q ≈ 40{,}6 \text{.}\) 1p 3p c Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 25 \text{,}\) \(K\kern{-.8pt}M = 54\) en \(\angle M = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle L) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\tan(\angle L) = {54 \over 25} \text{.}\) 1p ○ Hieruit volgt \(\angle L = \tan^{-1}({54 \over 25}) \text{.}\) 1p ○ Dus \(\angle L ≈ 65{,}2\degree \text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 45 \text{,}\) \(\angle L = 47\degree\) en \(\angle M = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle L) = {K\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\sin(47\degree) = {K\kern{-.8pt}M \over 45} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = 45 ⋅ \sin(47\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 32{,}9 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 32 \text{,}\) \(\angle B = 38\degree\) en \(\angle C = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle B) = {A\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\sin(38\degree) = {32 \over A\kern{-.8pt}B} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = {32 \over \sin(38\degree)} \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 52{,}0 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 57 \text{,}\) \(P\kern{-.8pt}Q = 62\) en \(\angle R = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle Q) = {P\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\sin(\angle Q) = {57 \over 62} \text{.}\) 1p ○ Hieruit volgt \(\angle Q = \sin^{-1}({57 \over 62}) \text{.}\) 1p ○ Dus \(\angle Q ≈ 66{,}8\degree \text{.}\) 1p 3p d Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 43 \text{,}\) \(\angle Q = 43\degree\) en \(\angle R = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle Q) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\cos(43\degree) = {Q\kern{-.8pt}R \over 43} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = 43 ⋅ \cos(43\degree) \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 31{,}4 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 55 \text{,}\) \(\angle P = 48\degree\) en \(\angle Q = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle P) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\cos(48\degree) = {55 \over P\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R = {55 \over \cos(48\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}R ≈ 82{,}2 \text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M = 42 \text{,}\) \(L\kern{-.8pt}M = 52\) en \(\angle K = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle M) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\cos(\angle M) = {42 \over 52} \text{.}\) 1p ○ Hieruit volgt \(\angle M = \cos^{-1}({42 \over 52}) \text{.}\) 1p ○ Dus \(\angle M ≈ 36{,}1\degree \text{.}\) 1p |