Getal & Ruimte (12e editie) - havo wiskunde B

'Wortels vereenvoudigen'.

2 havo/vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (4)

opgave 1

Herleid.

1p

a

\(\sqrt{75}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{75}=\sqrt{25}⋅\sqrt{3}=5\sqrt{3}\text{.}\)

1p

1p

b

\(-5\sqrt{8}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 1ms

b

\(-5\sqrt{8}=-5⋅\sqrt{4}⋅\sqrt{2}=-5⋅2⋅\sqrt{2}=-10\sqrt{2}\text{.}\)

1p

1p

c

\(\sqrt{2\frac{14}{25}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 103ms

c

\(\sqrt{2\frac{14}{25}}=\sqrt{\frac{64}{25}}={\sqrt{64} \over \sqrt{25}}=\frac{8}{5}=1\frac{3}{5}\text{.}\)

1p

1p

d

\({24\sqrt{320} \over 3\sqrt{8}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 16ms

d

\({24\sqrt{320} \over 3\sqrt{8}}={24 \over 3}⋅{\sqrt{320} \over \sqrt{8}}=8\sqrt{40}=8⋅\sqrt{4}⋅\sqrt{10}=8⋅2⋅\sqrt{10}=16\sqrt{10}\)

1p

3 havo 5.4 Wortels herleiden

Wortels vereenvoudigen (1)

opgave 1

Herleid.

1p

\(\sqrt{\frac{48}{49}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

\(\sqrt{\frac{48}{49}}={\sqrt{48} \over \sqrt{49}}={\sqrt{48} \over 7}=\frac{1}{7}\sqrt{48}=\frac{1}{7}⋅4⋅\sqrt{3}=\frac{4}{7}\sqrt{3}\text{.}\)

1p

havo wiskunde B 3.3 Vergelijkingen in de meetkunde

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{500}+\sqrt{45}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{500}+\sqrt{45}=\sqrt{100}⋅\sqrt{5}+\sqrt{9}⋅\sqrt{5}=10\sqrt{5}+3\sqrt{5}\text{.}\)

1p

\(10\sqrt{5}+3\sqrt{5}=13\sqrt{5}\text{.}\)

1p

2p

b

\(2\sqrt{500}-4\sqrt{125}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 1ms

b

\(2\sqrt{500}-4\sqrt{125}=2⋅\sqrt{100}⋅\sqrt{5}-4⋅\sqrt{25}⋅\sqrt{5}\text{.}\)

1p

\(2⋅10⋅\sqrt{5}-4⋅5⋅\sqrt{5}=20\sqrt{5}-20\sqrt{5}=0\sqrt{5}\text{.}\)

1p

1p

c

\({5 \over 8\sqrt{2}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

c

\({5 \over 8\sqrt{2}}={5 \over 8\sqrt{2}}⋅{\sqrt{2} \over \sqrt{2}}={5\sqrt{2} \over 8⋅2}=\frac{5}{16}\sqrt{2}\text{.}\)

1p

1p

d

\(\sqrt{\frac{1}{84}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{\frac{1}{84}}={\sqrt{1} \over \sqrt{84}}={1 \over \sqrt{84}}⋅{\sqrt{84} \over \sqrt{84}}={\sqrt{84} \over 84}=\frac{1}{84}\sqrt{84}=\frac{1}{84}⋅2⋅\sqrt{21}=\frac{1}{42}\sqrt{21}\text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{2}{75}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

\(\sqrt{\frac{2}{75}}={\sqrt{2} \over \sqrt{75}}⋅{\sqrt{75} \over \sqrt{75}}={\sqrt{150} \over 75}=\frac{1}{75}\sqrt{150}=\frac{1}{75}⋅5⋅\sqrt{6}=\frac{1}{15}\sqrt{6}\text{.}\)

1p

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