Getal & Ruimte (12e editie) - havo wiskunde B
'Wortels vereenvoudigen'.
| 2 havo/vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{75}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{75}=\sqrt{25}⋅\sqrt{3}=5\sqrt{3}\text{.}\) 1p 1p b \(-5\sqrt{8}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 1ms b \(-5\sqrt{8}=-5⋅\sqrt{4}⋅\sqrt{2}=-5⋅2⋅\sqrt{2}=-10\sqrt{2}\text{.}\) 1p 1p c \(\sqrt{2\frac{14}{25}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 103ms c \(\sqrt{2\frac{14}{25}}=\sqrt{\frac{64}{25}}={\sqrt{64} \over \sqrt{25}}=\frac{8}{5}=1\frac{3}{5}\text{.}\) 1p 1p d \({24\sqrt{320} \over 3\sqrt{8}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 16ms d \({24\sqrt{320} \over 3\sqrt{8}}={24 \over 3}⋅{\sqrt{320} \over \sqrt{8}}=8\sqrt{40}=8⋅\sqrt{4}⋅\sqrt{10}=8⋅2⋅\sqrt{10}=16\sqrt{10}\) 1p |
|
| 3 havo | 5.4 Wortels herleiden |
opgave 1Herleid. 1p \(\sqrt{\frac{48}{49}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{\frac{48}{49}}={\sqrt{48} \over \sqrt{49}}={\sqrt{48} \over 7}=\frac{1}{7}\sqrt{48}=\frac{1}{7}⋅4⋅\sqrt{3}=\frac{4}{7}\sqrt{3}\text{.}\) 1p |
|
| havo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 2p a \(\sqrt{500}+\sqrt{45}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{500}+\sqrt{45}=\sqrt{100}⋅\sqrt{5}+\sqrt{9}⋅\sqrt{5}=10\sqrt{5}+3\sqrt{5}\text{.}\) 1p ○ \(10\sqrt{5}+3\sqrt{5}=13\sqrt{5}\text{.}\) 1p 2p b \(2\sqrt{500}-4\sqrt{125}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms b \(2\sqrt{500}-4\sqrt{125}=2⋅\sqrt{100}⋅\sqrt{5}-4⋅\sqrt{25}⋅\sqrt{5}\text{.}\) 1p ○ \(2⋅10⋅\sqrt{5}-4⋅5⋅\sqrt{5}=20\sqrt{5}-20\sqrt{5}=0\sqrt{5}\text{.}\) 1p 1p c \({5 \over 8\sqrt{2}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms c \({5 \over 8\sqrt{2}}={5 \over 8\sqrt{2}}⋅{\sqrt{2} \over \sqrt{2}}={5\sqrt{2} \over 8⋅2}=\frac{5}{16}\sqrt{2}\text{.}\) 1p 1p d \(\sqrt{\frac{1}{84}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{\frac{1}{84}}={\sqrt{1} \over \sqrt{84}}={1 \over \sqrt{84}}⋅{\sqrt{84} \over \sqrt{84}}={\sqrt{84} \over 84}=\frac{1}{84}\sqrt{84}=\frac{1}{84}⋅2⋅\sqrt{21}=\frac{1}{42}\sqrt{21}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{2}{75}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{\frac{2}{75}}={\sqrt{2} \over \sqrt{75}}⋅{\sqrt{75} \over \sqrt{75}}={\sqrt{150} \over 75}=\frac{1}{75}\sqrt{150}=\frac{1}{75}⋅5⋅\sqrt{6}=\frac{1}{15}\sqrt{6}\text{.}\) 1p |