Getal & Ruimte (12e editie) - havo wiskunde B
'Wortels vereenvoudigen'.
| 2 havo/vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{20}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{20}=\sqrt{4}⋅\sqrt{5}=2\sqrt{5}\text{.}\) 1p 1p b \(-5\sqrt{200}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms b \(-5\sqrt{200}=-5⋅\sqrt{100}⋅\sqrt{2}=-5⋅10⋅\sqrt{2}=-50\sqrt{2}\text{.}\) 1p |
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| 3 havo | 5.4 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{\frac{9}{64}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 56ms a \(\sqrt{\frac{9}{64}}={\sqrt{9} \over \sqrt{64}}=\frac{3}{8}\text{.}\) 1p 1p b \(\sqrt{16\frac{1}{4}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{16\frac{1}{4}}=\sqrt{\frac{65}{4}}={\sqrt{65} \over \sqrt{4}}={\sqrt{65} \over 2}=\frac{1}{2}\sqrt{65}\text{.}\) 1p |
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| havo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 2p a \(\sqrt{18}+\sqrt{32}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{18}+\sqrt{32}=\sqrt{9}⋅\sqrt{2}+\sqrt{16}⋅\sqrt{2}=3\sqrt{2}+4\sqrt{2}\text{.}\) 1p ○ \(3\sqrt{2}+4\sqrt{2}=7\sqrt{2}\text{.}\) 1p 2p b \(7\sqrt{27}+6\sqrt{300}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 0ms b \(7\sqrt{27}+6\sqrt{300}=7⋅\sqrt{9}⋅\sqrt{3}+6⋅\sqrt{100}⋅\sqrt{3}\text{.}\) 1p ○ \(7⋅3⋅\sqrt{3}+6⋅10⋅\sqrt{3}=21\sqrt{3}+60\sqrt{3}=81\sqrt{3}\text{.}\) 1p 1p c \({7 \over 2\sqrt{2}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms c \({7 \over 2\sqrt{2}}={7 \over 2\sqrt{2}}⋅{\sqrt{2} \over \sqrt{2}}={7\sqrt{2} \over 2⋅2}=1\frac{3}{4}\sqrt{2}\text{.}\) 1p 1p d \(\sqrt{1\frac{1}{80}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{1\frac{1}{80}}=\sqrt{\frac{81}{80}}={\sqrt{81} \over \sqrt{80}}={9 \over \sqrt{80}}⋅{\sqrt{80} \over \sqrt{80}}={9\sqrt{80} \over 80}=\frac{9}{80}\sqrt{80}=\frac{9}{80}⋅4⋅\sqrt{5}=\frac{9}{20}\sqrt{5}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{2}{43}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{\frac{2}{43}}={\sqrt{2} \over \sqrt{43}}⋅{\sqrt{43} \over \sqrt{43}}={\sqrt{86} \over 43}=\frac{1}{43}\sqrt{86}\text{.}\) 1p |