\(\sqrt{50} = \sqrt{25} ⋅ \sqrt{2} = 5 \sqrt{2} \text{.}\)

\(2 \sqrt{28} = 2 ⋅ \sqrt{4} ⋅ \sqrt{7} = 2 ⋅ 2 ⋅ \sqrt{7} = 4 \sqrt{7} \text{.}\)

\(\sqrt{\frac{4}{25}} = {\sqrt{4} \over \sqrt{25}} = \frac{2}{5} \text{.}\)

\({54 \sqrt{64} \over 9 \sqrt{8}} = {54 \over 9} ⋅ {\sqrt{64} \over \sqrt{8}} = 6 \sqrt{8} = 6 ⋅ \sqrt{4} ⋅ \sqrt{2} = 6 ⋅ 2 ⋅ \sqrt{2} = 12 \sqrt{2}\)

\(\sqrt{9\frac{3}{4}} = \sqrt{\frac{39}{4}} = {\sqrt{39} \over \sqrt{4}} = {\sqrt{39} \over 2} = \frac{1}{2} \sqrt{39} \text{.}\)

\(\sqrt{12} + \sqrt{48} = \sqrt{4} ⋅ \sqrt{3} + \sqrt{16} ⋅ \sqrt{3} = 2 \sqrt{3} + 4 \sqrt{3} \text{.}\)

\(2 \sqrt{3} + 4 \sqrt{3} = 6 \sqrt{3} \text{.}\)

\(7 \sqrt{300} - 5 \sqrt{48} = 7 ⋅ \sqrt{100} ⋅ \sqrt{3} - 5 ⋅ \sqrt{16} ⋅ \sqrt{3} \text{.}\)

\(7 ⋅ 10 ⋅ \sqrt{3} - 5 ⋅ 4 ⋅ \sqrt{3} = 70 \sqrt{3} - 20 \sqrt{3} = 50 \sqrt{3} \text{.}\)

\({9 \over 8 \sqrt{7}} = {9 \over 8 \sqrt{7}} ⋅ {\sqrt{7} \over \sqrt{7}} = {9 \sqrt{7} \over 8 ⋅ 7} = \frac{9}{56} \sqrt{7} \text{.}\)

\(\sqrt{\frac{1}{95}} = {\sqrt{1} \over \sqrt{95}} = {1 \over \sqrt{95}} ⋅ {\sqrt{95} \over \sqrt{95}} = {\sqrt{95} \over 95} = \frac{1}{95} \sqrt{95} \text{.}\)

\(\sqrt{\frac{3}{32}} = {\sqrt{3} \over \sqrt{32}} ⋅ {\sqrt{32} \over \sqrt{32}} = {\sqrt{96} \over 32} = \frac{1}{32} \sqrt{96} = \frac{1}{32} ⋅ 4 ⋅ \sqrt{6} = \frac{1}{8} \sqrt{6} \text{.}\)