Getal & Ruimte (12e editie) - havo wiskunde B

'Wortels vereenvoudigen'.

2 havo/vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (2)

opgave 1

Herleid.

1p

a

\(\sqrt{20}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{20}=\sqrt{4}⋅\sqrt{5}=2\sqrt{5}\text{.}\)

1p

1p

b

\(-5\sqrt{200}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 0ms

b

\(-5\sqrt{200}=-5⋅\sqrt{100}⋅\sqrt{2}=-5⋅10⋅\sqrt{2}=-50\sqrt{2}\text{.}\)

1p

3 havo 5.4 Wortels herleiden

Wortels vereenvoudigen (2)

opgave 1

Herleid.

1p

a

\(\sqrt{\frac{9}{64}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 56ms

a

\(\sqrt{\frac{9}{64}}={\sqrt{9} \over \sqrt{64}}=\frac{3}{8}\text{.}\)

1p

1p

b

\(\sqrt{16\frac{1}{4}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{16\frac{1}{4}}=\sqrt{\frac{65}{4}}={\sqrt{65} \over \sqrt{4}}={\sqrt{65} \over 2}=\frac{1}{2}\sqrt{65}\text{.}\)

1p

havo wiskunde B 3.3 Vergelijkingen in de meetkunde

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{18}+\sqrt{32}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{18}+\sqrt{32}=\sqrt{9}⋅\sqrt{2}+\sqrt{16}⋅\sqrt{2}=3\sqrt{2}+4\sqrt{2}\text{.}\)

1p

\(3\sqrt{2}+4\sqrt{2}=7\sqrt{2}\text{.}\)

1p

2p

b

\(7\sqrt{27}+6\sqrt{300}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 0ms

b

\(7\sqrt{27}+6\sqrt{300}=7⋅\sqrt{9}⋅\sqrt{3}+6⋅\sqrt{100}⋅\sqrt{3}\text{.}\)

1p

\(7⋅3⋅\sqrt{3}+6⋅10⋅\sqrt{3}=21\sqrt{3}+60\sqrt{3}=81\sqrt{3}\text{.}\)

1p

1p

c

\({7 \over 2\sqrt{2}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

c

\({7 \over 2\sqrt{2}}={7 \over 2\sqrt{2}}⋅{\sqrt{2} \over \sqrt{2}}={7\sqrt{2} \over 2⋅2}=1\frac{3}{4}\sqrt{2}\text{.}\)

1p

1p

d

\(\sqrt{1\frac{1}{80}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{1\frac{1}{80}}=\sqrt{\frac{81}{80}}={\sqrt{81} \over \sqrt{80}}={9 \over \sqrt{80}}⋅{\sqrt{80} \over \sqrt{80}}={9\sqrt{80} \over 80}=\frac{9}{80}\sqrt{80}=\frac{9}{80}⋅4⋅\sqrt{5}=\frac{9}{20}\sqrt{5}\text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{\frac{2}{43}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

\(\sqrt{\frac{2}{43}}={\sqrt{2} \over \sqrt{43}}⋅{\sqrt{43} \over \sqrt{43}}={\sqrt{86} \over 43}=\frac{1}{43}\sqrt{86}\text{.}\)

1p

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