Getal & Ruimte (12e editie) - havo wiskunde B
'Wortels vereenvoudigen'.
| 2 havo/vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{18}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{18} = \sqrt{9} ⋅ \sqrt{2} = 3 \sqrt{2} \text{.}\) 1p 1p b \(2 \sqrt{63}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms b \(2 \sqrt{63} = 2 ⋅ \sqrt{9} ⋅ \sqrt{7} = 2 ⋅ 3 ⋅ \sqrt{7} = 6 \sqrt{7} \text{.}\) 1p 1p c \(\sqrt{\frac{9}{64}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 25ms c \(\sqrt{\frac{9}{64}} = {\sqrt{9} \over \sqrt{64}} = \frac{3}{8} \text{.}\) 1p 1p d \({54 \sqrt{192} \over 9 \sqrt{8}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 1ms d \({54 \sqrt{192} \over 9 \sqrt{8}} = {54 \over 9} ⋅ {\sqrt{192} \over \sqrt{8}} = 6 \sqrt{24} = 6 ⋅ \sqrt{4} ⋅ \sqrt{6} = 6 ⋅ 2 ⋅ \sqrt{6} = 12 \sqrt{6}\) 1p |
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| 3 havo | 5.4 Wortels herleiden |
opgave 1Herleid. 1p \(\sqrt{\frac{13}{64}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{\frac{13}{64}} = {\sqrt{13} \over \sqrt{64}} = {\sqrt{13} \over 8} = \frac{1}{8} \sqrt{13} \text{.}\) 1p |
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| havo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 2p a \(\sqrt{80} + \sqrt{500}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{80} + \sqrt{500} = \sqrt{16} ⋅ \sqrt{5} + \sqrt{100} ⋅ \sqrt{5} = 4 \sqrt{5} + 10 \sqrt{5} \text{.}\) 1p ○ \(4 \sqrt{5} + 10 \sqrt{5} = 14 \sqrt{5} \text{.}\) 1p 2p b \(7 \sqrt{27} - 3 \sqrt{75}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 0ms b \(7 \sqrt{27} - 3 \sqrt{75} = 7 ⋅ \sqrt{9} ⋅ \sqrt{3} - 3 ⋅ \sqrt{25} ⋅ \sqrt{3} \text{.}\) 1p ○ \(7 ⋅ 3 ⋅ \sqrt{3} - 3 ⋅ 5 ⋅ \sqrt{3} = 21 \sqrt{3} - 15 \sqrt{3} = 6 \sqrt{3} \text{.}\) 1p 1p c \({3 \over 8 \sqrt{3}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 0ms c \({3 \over 8 \sqrt{3}} = {3 \over 8 \sqrt{3}} ⋅ {\sqrt{3} \over \sqrt{3}} = {3 \sqrt{3} \over 8 ⋅ 3} = \frac{1}{8} \sqrt{3} \text{.}\) 1p 1p d \(\sqrt{\frac{9}{13}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 0ms d \(\sqrt{\frac{9}{13}} = {\sqrt{9} \over \sqrt{13}} = {3 \over \sqrt{13}} ⋅ {\sqrt{13} \over \sqrt{13}} = {3 \sqrt{13} \over 13} = \frac{3}{13} \sqrt{13} \text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{\frac{5}{14}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 0ms ○ \(\sqrt{\frac{5}{14}} = {\sqrt{5} \over \sqrt{14}} ⋅ {\sqrt{14} \over \sqrt{14}} = {\sqrt{70} \over 14} = \frac{1}{14} \sqrt{70} \text{.}\) 1p |