Getal & Ruimte (12e editie) - vwo wiskunde A
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({3 \over 2 a} + {4 \over 2 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({3 \over 2 a} + {4 \over 2 a} = {7 \over 2 a}\) 1p 1p b \({2 \over x} - {3 \over 8 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({2 \over x} - {3 \over 8 x} = {16 \over 8 x} - {3 \over 8 x} = {13 \over 8 x}\) 1p 1p c \({7 \over 5 p} + {3 \over 2 q}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({7 \over 5 p} + {3 \over 2 q} = {14 q \over 10 p q} + {15 p \over 10 p q} = {14 q + 15 p \over 10 p q}\) 1p 1p d \(2 + {7 \over 5 x}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(2 + {7 \over 5 x} = {2 \over 1} + {7 \over 5 x} = {10 x \over 5 x} + {7 \over 5 x} = {10 x + 7 \over 5 x}\) 1p opgave 2Herleid tot één breuk. 1p \({7 a \over b} + {4 \over 9 b}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({7 a \over b} + {4 \over 9 b} = {63 a \over 9 b} + {4 \over 9 b} = {63 a + 4 \over 9 b}\) 1p opgave 3Herleid. 1p a \({2 x \over x}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({2 x \over x} = {2 \over 1} = 2\) 1p 1p b \({a \over 8 a}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({a \over 8 a} = {1 \over 8}\) 1p 1p c \({-12 a \over -28 a}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({-12 a \over -28 a} = \frac{3}{7}\) 1p 1p d \({-12 p \over -3 p}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-12 p \over -3 p} = 4\) 1p opgave 4Herleid. 1p a \({4 x y \over 18 x z}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({4 x y \over 18 x z} = {2 y \over 9 z}\) 1p 1p b \({4 b \over -14 a b}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({4 b \over -14 a b} = -{2 \over 7 a}\) 1p 1p c \({-8 p q r \over 2 q r}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({-8 p q r \over 2 q r} = -4 p\) 1p 1p d \({7 a b \over b} - {4 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({7 a b \over b} - {4 a c \over c} = 7 a - 4 a = 3 a\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(8 x - {2 \over 9 x}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(8 x - {2 \over 9 x} = {8 x \over 1} ⋅ {9 x \over 9 x} - {2 \over 9 x} = {72 x^{2} \over 9 x} - {2 \over 9 x} = {72 x^{2} - 2 \over 9 x}\) 1p 1p b \({3 b \over 7 a} - {6 a \over 9 b}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({3 b \over 7 a} - {6 a \over 9 b} = {27 b^{2} \over 63 a b} - {42 a^{2} \over 63 a b} = {-42 a^{2} + 27 b^{2} \over 63 a b} = {-14 a^{2} + 9 b^{2} \over 21 a b}\) 1p 1p c \({2 \over a} ⋅ {7 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({2 \over a} ⋅ {7 \over b} = {14 \over a b}\) 1p 1p d \({p \over 3} ⋅ {5 \over q}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({p \over 3} ⋅ {5 \over q} = {5 p \over 3 q}\) 1p opgave 2Herleid tot één breuk. 1p a \(-{9 \over 7} ⋅ x\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{9 \over 7} ⋅ x = -{9 x \over 7}\) 1p 1p b \({9 q \over p} ⋅ {p + 3 \over 5}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({9 q \over p} ⋅ {p + 3 \over 5} = {9 q (p + 3) \over 5 p} = {9 p q + 27 q \over 5 p}\) 1p 1p c \({5 \over x} : {4 \over y}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({5 \over x} : {4 \over y} = {5 \over x} ⋅ {y \over 4} = {5 y \over 4 x}\) 1p 1p d \({1 \over 3} : a\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \({1 \over 3} : a = {1 \over 3} : {a \over 1} = {1 \over 3} ⋅ {1 \over a} = {1 \over 3 a}\) 1p opgave 3Herleid tot één breuk. 1p a \(-{2 \over 5} : {a + b \over b}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{2 \over 5} : {a + b \over b} = -{2 \over 5} ⋅ {b \over a + b} = -{2 b \over 5 (a + b)} = -{2 b \over 5 a + 5 b}\) 1p 1p b \({x \over 3} + {x + 4 \over 2}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 3} + {x + 4 \over 2} = {2 x \over 6} + {3 (x + 4) \over 6} = {2 x + 3 (x + 4) \over 6} = {5 x + 12 \over 6}\) 1p |
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| 3 vwo | 5.3 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({9 x + 6 \over 3 x + 5} + 4\) Optellen (9) 00eh - Breuken herleiden - basis - 1ms - dynamic variables ○ \({9 x + 6 \over 3 x + 5} + 4 = {9 x + 6 \over 3 x + 5} + {4 (3 x + 5) \over 3 x + 5} = {9 x + 6 + 4 (3 x + 5) \over 3 x + 5} = {9 x + 6 + 12 x + 20 \over 3 x + 5} = {21 x + 26 \over 3 x + 5}\) 1p |
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| vwo wiskunde A | 13.3 Formules herschrijven |
opgave 1Deel uit. 1p \({2 a^{2} + 4 a - 9 \over 3 a^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables ○ \({2 a^{2} + 4 a - 9 \over 3 a^{2}} = {2 a^{2} \over 3 a^{2}} + {4 a \over 3 a^{2}} - {9 \over 3 a^{2}} = \frac{2}{3} + {4 \over 3 a} - {3 \over a^{2}}\) 1p |