\({9 \over 8 x} - {5 \over 8 x} = {4 \over 8 x} = {1 \over 2 x}\)

\({9 \over x} - {2 \over 4 x} = {36 \over 4 x} - {2 \over 4 x} = {34 \over 4 x} = {17 \over 2 x}\)

\({3 \over 5 a} + {2 \over 6 b} = {18 b \over 30 a b} + {10 a \over 30 a b} = {18 b + 10 a \over 30 a b} = {9 b + 5 a \over 15 a b}\)

\(7 + {4 \over 3 p} = {7 \over 1} + {4 \over 3 p} = {21 p \over 3 p} + {4 \over 3 p} = {21 p + 4 \over 3 p}\)

\({9 a \over b} + {4 \over 6 b} = {54 a \over 6 b} + {4 \over 6 b} = {54 a + 4 \over 6 b} = {27 a + 2 \over 3 b}\)

\({8 x \over x} = {8 \over 1} = 8\)

\({a \over 6 a} = {1 \over 6}\)

\({15 x \over 18 x} = \frac{5}{6}\)

\({16 p \over 4 p} = 4\)

\({-4 a b \over -10 a c} = {2 b \over 5 c}\)

\({10 b \over -18 a b} = -{5 \over 9 a}\)

\({-24 p q r \over 4 q r} = -6 p\)

\({6 x y \over y} + {4 x z \over z} = 6 x + 4 x = 10 x\)

\(5 x - {7 \over 6 x} = {5 x \over 1} ⋅ {6 x \over 6 x} - {7 \over 6 x} = {30 x^{2} \over 6 x} - {7 \over 6 x} = {30 x^{2} - 7 \over 6 x}\)

\({5 b \over 8 a} - {4 a \over 6 b} = {15 b^{2} \over 24 a b} - {16 a^{2} \over 24 a b} = {-16 a^{2} + 15 b^{2} \over 24 a b}\)

\({8 \over x} ⋅ -{4 \over y} = -{32 \over x y}\)

\({p \over 8} ⋅ -{5 \over q} = -{5 p \over 8 q}\)

\(-{8 \over 7} ⋅ a = -{8 a \over 7}\)

\({7 b \over a} ⋅ {a + 9 \over 8} = {7 b (a + 9) \over 8 a} = {7 a b + 63 b \over 8 a}\)

\({7 \over x} : {6 \over y} = {7 \over x} ⋅ {y \over 6} = {7 y \over 6 x}\)

\(-{7 \over 5} : x = -{7 \over 5} : {x \over 1} = -{7 \over 5} ⋅ {1 \over x} = -{7 \over 5 x}\)

\(-{3 \over 5} : {p - 2 q \over q} = -{3 \over 5} ⋅ {q \over p - 2 q} = -{3 q \over 5 (p - 2 q)} = -{3 q \over 5 p - 10 q}\)

\({2 a \over 5} + {a - 6 \over 9} = {18 a \over 45} + {5 (a - 6) \over 45} = {18 a + 5 (a - 6) \over 45} = {23 a - 30 \over 45}\)

\({-6 p - 8 \over -3 p + 9} + 2 = {-6 p - 8 \over -3 p + 9} - {-2 (-3 p + 9) \over -3 p + 9} = {-6 p - 8 + 2 (-3 p + 9) \over -3 p + 9} = {-6 p - 8 - 6 p + 18 \over -3 p + 9} = {-12 p + 10 \over -3 p + 9}\)

\({9 x^{2} - 4 x - 6 \over 5 x^{2}} = {9 x^{2} \over 5 x^{2}} - {4 x \over 5 x^{2}} - {6 \over 5 x^{2}} = 1\frac{4}{5} - {4 \over 5 x} - {6 \over 5 x^{2}}\)