\({7 \over 6x}-{3 \over 6x}={4 \over 6x}={2 \over 3x}\)

\({8 \over x}+{2 \over 5x}={40 \over 5x}+{2 \over 5x}={42 \over 5x}\)

\({5 \over 6a}+{4 \over 9b}={15b \over 18ab}+{8a \over 18ab}={15b+8a \over 18ab}\)

\(2+{7 \over 8a}={2 \over 1}+{7 \over 8a}={16a \over 8a}+{7 \over 8a}={16a+7 \over 8a}\)

\({9p \over q}+{6 \over 5q}={45p \over 5q}+{6 \over 5q}={45p+6 \over 5q}\)

\({8p \over p}={8 \over 1}=8\)

\({x \over 8x}={1 \over 8}\)

\({15x \over -20x}=-\frac{3}{4}\)

\({45a \over -5a}=-9\)

\({28ab \over -36ac}=-{7b \over 9c}\)

\({6y \over -27xy}=-{2 \over 9x}\)

\({-24xyz \over 4yz}=-6x\)

\({5ab \over b}+{7ac \over c}=5a+7a=12a\)

\(8x-{5 \over 2x}={8x \over 1}⋅{2x \over 2x}-{5 \over 2x}={16x^2 \over 2x}-{5 \over 2x}={16x^2-5 \over 2x}\)

\({5q \over 3p}+{8p \over 6q}={10q^2 \over 6pq}+{8p^2 \over 6pq}={8p^2+10q^2 \over 6pq}={4p^2+5q^2 \over 3pq}\)

\({6 \over a}⋅-{4 \over b}=-{24 \over ab}\)

\({x \over 6}⋅{8 \over y}={8x \over 6y}={4x \over 3y}\)

\({5 \over 7}⋅a={5a \over 7}\)

\({6b \over a}⋅{a-3 \over 5}={6b(a-3) \over 5a}={6ab-18b \over 5a}\)

\({2 \over x}:{9 \over y}={2 \over x}⋅{y \over 9}={2y \over 9x}\)

\(-{1 \over 2}:a=-{1 \over 2}:{a \over 1}=-{1 \over 2}⋅{1 \over a}=-{1 \over 2a}\)

\(-{3 \over 2}:{p+8q \over q}=-{3 \over 2}⋅{q \over p+8q}=-{3q \over 2(p+8q)}=-{3q \over 2p+16q}\)

\({x \over 2}+{x+8 \over 5}={5x \over 10}+{2(x+8) \over 10}={5x+2(x+8) \over 10}={7x+16 \over 10}\)

\({9x^2+5x+7 \over 2x^2}={9x^2 \over 2x^2}+{5x \over 2x^2}+{7 \over 2x^2}=4\frac{1}{2}+{5 \over 2x}+{7 \over 2x^2}\)