\({5 \over 2p}+{8 \over 2p}={13 \over 2p}\)

\({4 \over a}+{6 \over 7a}={28 \over 7a}+{6 \over 7a}={34 \over 7a}\)

\({9 \over 8x}-{7 \over 3y}={27y \over 24xy}-{56x \over 24xy}={27y-56x \over 24xy}\)

\(5+{3 \over 8x}={5 \over 1}+{3 \over 8x}={40x \over 8x}+{3 \over 8x}={40x+3 \over 8x}\)

\({9a \over b}+{5 \over 7b}={63a \over 7b}+{5 \over 7b}={63a+5 \over 7b}\)

\({9x \over x}={9 \over 1}=9\)

\({p \over 3p}={1 \over 3}\)

\({-20x \over 24x}=-\frac{5}{6}\)

\({15a \over -3a}=-5\)

\({-10ab \over -15ac}={2b \over 3c}\)

\({20b \over -35ab}=-{4 \over 7a}\)

\({-15abc \over 3bc}=-5a\)

\({4xy \over y}-{3xz \over z}=4x-3x=x\)

\(9a+{4 \over 3a}={9a \over 1}⋅{3a \over 3a}+{4 \over 3a}={27a^2 \over 3a}+{4 \over 3a}={27a^2+4 \over 3a}\)

\({5b \over 6a}+{8a \over 7b}={35b^2 \over 42ab}+{48a^2 \over 42ab}={48a^2+35b^2 \over 42ab}\)

\({3 \over p}⋅-{5 \over q}=-{15 \over pq}\)

\({x \over 4}⋅-{2 \over y}=-{2x \over 4y}=-{x \over 2y}\)

\(-{3 \over 2}⋅x=-{3x \over 2}\)

\({4b \over a}⋅{a+9 \over 7}={4b(a+9) \over 7a}={4ab+36b \over 7a}\)

\({5 \over p}:{6 \over q}={5 \over p}⋅{q \over 6}={5q \over 6p}\)

\(-{9 \over 2}:x=-{9 \over 2}:{x \over 1}=-{9 \over 2}⋅{1 \over x}=-{9 \over 2x}\)

\({7 \over 5}:{x+4y \over y}={7 \over 5}⋅{y \over x+4y}={7y \over 5(x+4y)}={7y \over 5x+20y}\)

\({a \over 6}+{a-4 \over 5}={5a \over 30}+{6(a-4) \over 30}={5a+6(a-4) \over 30}={11a-24 \over 30}\)

\({a^2+3a+6 \over 5a^2}={a^2 \over 5a^2}+{3a \over 5a^2}+{6 \over 5a^2}=\frac{1}{5}+{3 \over 5a}+{6 \over 5a^2}\)