\(l{:}\,y=ax+b\) met \(a=\text{rc}_l=-9\)

Door \((0, 7)\) dus \(b=7\text{,}\) en dus \(l{:}\,y=-9x+7\)

\(l{:}\,y=ax+b\) met \(a=\text{rc}_l=\text{rc}_m=3\)

Door \((0, 6)\) dus \(b=6\text{,}\) en dus \(l{:}\,y=3x+6\)

\(l{:}\,y=ax+b\) met \(a=\text{rc}_l=\text{rc}_m=-9\)

\(\begin{rcases}y=-9x+b \\ \text{door }A(3, 4)\end{rcases}\begin{matrix}-9⋅3+b=4 \\ -27+b=4 \\ b=31\end{matrix}\)

Dus \(l{:}\,y=-9x+31\)

\(l{:}\,y=ax+b\) met \(a=\text{rc}_l=3\)

\(\begin{rcases}y=3x+b \\ \text{door }A(4, 2)\end{rcases}\begin{matrix}3⋅4+b=2 \\ 12+b=2 \\ b=-10\end{matrix}\)

Dus \(l{:}\,y=3x-10\)

\(y=ax+b\text{.}\)

Door \((0, -4)\text{,}\) dus \(b=-4\text{.}\)

\(a={\text{verticaal} \over \text{horizontaal}}={6 \over 8}=\frac{3}{4}\text{.}\)

\(y=\frac{3}{4}x-4\text{.}\)

Rasterpunten \((5, 25)\) en \((25, 10)\) aflezen.

\(y=ax+b\) met \(a={\Delta y \over \Delta x}={10-25 \over 25-5}=-0{,}75\)

\(\begin{rcases}y=-0{,}75x+b \\ \text{door }A(5, 25)\end{rcases}\begin{matrix}-0{,}75⋅5+b=25 \\ -3{,}75+b=25 \\ b=28{,}75\end{matrix}\)

Dus \(y=-0{,}75x+28{,}75\)

\(l{:}\,y=ax+b\) met \(a={\Delta y \over \Delta x}={37--11 \over 7--1}=6\)

\(\begin{rcases}y=6x+b \\ \text{door }A(-1, -11)\end{rcases}\begin{matrix}6⋅-1+b=-11 \\ -6+b=-11 \\ b=-5\end{matrix}\)

Dus \(l{:}\,y=6x-5\)

\(y=ax+b\) met \(a={\Delta y \over \Delta x}={11-31 \over -2--6}=-5\)

\(\begin{rcases}y=-5x+b \\ \text{door }A(-6, 31)\end{rcases}\begin{matrix}-5⋅-6+b=31 \\ 30+b=31 \\ b=1\end{matrix}\)

Dus \(y=-5x+1\)

\(l{:}\,y=ax+b\) met \(a={\Delta y \over \Delta x}={5-5 \over 7-3}={0 \over 4}=0\)

\(\begin{rcases}y=b \\ \text{door }A(3, 5)\end{rcases}\begin{matrix}b=5\end{matrix}\)

Dus \(l{:}\,y=5\)

Door de oorsprong betekent dat \(b=0\text{,}\) dus \(l{:}\,y=ax\)

\(\begin{rcases}y=ax \\ \text{door }A(3, 6)\end{rcases}\begin{matrix}a⋅3=6 \\ a=2\end{matrix}\)
Dus \(y=2x\text{.}\)

Evenredig betekent \(y=ax\text{.}\)

\(\begin{rcases}y=ax \\ \text{door }A(9, 54)\end{rcases}\begin{matrix}a⋅9=54 \\ a=6\end{matrix}\)
Dus \(y=6x\text{.}\)