\({1 \over p^3}=p^{-3}\)

\({a^5 \over a^{-4}}=a^{5--4}=a^9\)

\(x^4⋅x^{-7}=x^{4+-7}=x^{-3}\)

\((a^4)^{-5}=a^{4⋅-5}=a^{-20}\)

\(x^6⋅{1 \over x^8}=x^6⋅x^{-8}=x^{6+-8}=x^{-2}\)

\({({1 \over x^9}) \over x^5}={x^{-9} \over x^5}=x^{-9-5}=x^{-14}\)

\({x^3 \over x^0}=x^{3-0}=x^3\)

\({4 \over a^7}\)

\({5x^3 \over 8x^4}={5 \over 8}⋅{x^3 \over x^4}={5 \over 8}⋅x^{3-4}={5 \over 8}x^{-1}\)

\({x^2 \over ({1 \over x^7})}={x^2 \over x^{-7}}=x^{2--7}=x^9\)

\({7a^4b \over 6a^3b^5}={7 \over 6}⋅{a^4 \over a^3}⋅{b^1 \over b^5}={7 \over 6}⋅a^{4-3}⋅a^{1-5}=1\frac{1}{6}ab^{-4}\)

\(x^2⋅\sqrt[6]{x}=x^2⋅x^{\frac{1}{6}}=x^{2+\frac{1}{6}}=x^{2\frac{1}{6}}\)

\(a^3⋅\sqrt[9]{a^2}=a^3⋅a^{\frac{2}{9}}=a^{3+\frac{2}{9}}=a^{3\frac{2}{9}}\)

\({p^6 \over \sqrt[4]{p^3}}={p^6 \over p^{\frac{3}{4}}}=p^{6-\frac{3}{4}}=p^{5\frac{1}{4}}\)

\({1 \over x^6}⋅\sqrt[9]{x^2}=x^{-6}⋅x^{\frac{2}{9}}=x^{-6+\frac{2}{9}}=x^{-5\frac{7}{9}}\)

\({\sqrt[9]{a^5} \over \sqrt[9]{a^4}}={a^{\frac{5}{9}} \over a^{\frac{4}{9}}}=a^{\frac{5}{9}-\frac{4}{9}}=a^{\frac{1}{9}}\)

\(\sqrt[7]{{1 \over x^6}}=\sqrt[7]{x^{-6}}=x^{-\frac{6}{7}}\)

\(\sqrt[5]{p^{10}}=p^{\frac{10}{5}}=p^2\)

\({x^4 \over x^2⋅\sqrt[4]{x^3}}={x^4 \over x^2⋅x^{\frac{3}{4}}}={x^4 \over x^{2\frac{3}{4}}}=x^{4-2\frac{3}{4}}=x^{1\frac{1}{4}}\)

\({6b^4 \over 7a^9}\)

\((5a)^{-4}=5^{-4}⋅a^{-4}={1 \over 5^4}⋅{1 \over a^4}={1 \over 625a^4}\)

\(({1 \over 4}p)^{-3}=(4^{-1}⋅p)^{-3}=(4^{-1})^{-3}⋅p^{-3}=4^3⋅p^{-3}={64 \over p^3}\)

\(6a^{4\frac{5}{8}}=6⋅a^4⋅a^{\frac{5}{8}}=6a^4⋅\sqrt[8]{a^5}\)

\(\frac{4}{9}x^{-\frac{7}{8}}y^{\frac{1}{9}}=\frac{4}{9}⋅{1 \over x^{\frac{7}{8}}}⋅y^{\frac{1}{9}}={4⋅\sqrt[9]{y} \over 9⋅\sqrt[8]{x^7}}\)