\({8 \over 6 a} - {9 \over 6 a} = -{1 \over 6 a}\)

\({4 \over a} + {6 \over 7 a} = {28 \over 7 a} + {6 \over 7 a} = {34 \over 7 a}\)

\({5 \over 8 x} + {3 \over 4 y} = {5 y \over 8 x y} + {6 x \over 8 x y} = {5 y + 6 x \over 8 x y}\)

\(3 - {7 \over 4 p} = {3 \over 1} - {7 \over 4 p} = {12 p \over 4 p} - {7 \over 4 p} = {12 p - 7 \over 4 p}\)

\({3 x \over y} + {5 \over 6 y} = {18 x \over 6 y} + {5 \over 6 y} = {18 x + 5 \over 6 y}\)

\({7 a \over a} = {7 \over 1} = 7\)

\({x \over 5 x} = {1 \over 5}\)

\({-20 a \over 32 a} = -\frac{5}{8}\)

\({20 x \over -4 x} = -5\)

\({-15 p q \over -24 p r} = {5 q \over 8 r}\)

\({-25 b \over -35 a b} = {5 \over 7 a}\)

\({25 a b c \over -5 b c} = -5 a\)

\({6 x y \over y} + {2 x z \over z} = 6 x + 2 x = 8 x\)

\(4 a - {6 \over 7 a} = {4 a \over 1} ⋅ {7 a \over 7 a} - {6 \over 7 a} = {28 a^{2} \over 7 a} - {6 \over 7 a} = {28 a^{2} - 6 \over 7 a}\)

\({2 q \over 4 p} - {5 p \over 6 q} = {6 q^{2} \over 12 p q} - {10 p^{2} \over 12 p q} = {-10 p^{2} + 6 q^{2} \over 12 p q} = {-5 p^{2} + 3 q^{2} \over 6 p q}\)

\({6 \over a} ⋅ -{5 \over b} = -{30 \over a b}\)

\({x \over 6} ⋅ {3 \over y} = {3 x \over 6 y} = {x \over 2 y}\)

\(-{9 \over 4} ⋅ x = -{9 x \over 4}\)

\({9 b \over a} ⋅ {a - 7 \over 8} = {9 b (a - 7) \over 8 a} = {9 a b - 63 b \over 8 a}\)

\({8 \over x} : {7 \over y} = {8 \over x} ⋅ {y \over 7} = {8 y \over 7 x}\)

\(-{2 \over 5} : p = -{2 \over 5} : {p \over 1} = -{2 \over 5} ⋅ {1 \over p} = -{2 \over 5 p}\)

\({8 \over 9} : {x - 3 y \over y} = {8 \over 9} ⋅ {y \over x - 3 y} = {8 y \over 9 (x - 3 y)} = {8 y \over 9 x - 27 y}\)

\({2 a \over 9} + {a - 1 \over 8} = {16 a \over 72} + {9 (a - 1) \over 72} = {16 a + 9 (a - 1) \over 72} = {25 a - 9 \over 72}\)

\({-5 p - 7 \over 3 p + 2} - 8 = {-5 p - 7 \over 3 p + 2} - {8 (3 p + 2) \over 3 p + 2} = {-5 p - 7 - 8 (3 p + 2) \over 3 p + 2} = {-5 p - 7 - 24 p - 16 \over 3 p + 2} = {-29 p - 23 \over 3 p + 2}\)

\({9 a^{2} - 6 a + 30 \over 3 a} = {9 a^{2} \over 3 a} - {6 a \over 3 a} + {30 \over 3 a} = 3 a - 2 + {10 \over a}\)

\({5 x^{2} - 9 x + 6 \over 3 x^{2}} = {5 x^{2} \over 3 x^{2}} - {9 x \over 3 x^{2}} + {6 \over 3 x^{2}} = 1\frac{2}{3} - {3 \over x} + {2 \over x^{2}}\)