\({8 \over 4p}+{3 \over 4p}={11 \over 4p}\)

\({6 \over x}-{8 \over 5x}={30 \over 5x}-{8 \over 5x}={22 \over 5x}\)

\({7 \over 3a}-{8 \over 4b}={28b \over 12ab}-{24a \over 12ab}={28b-24a \over 12ab}={7b-6a \over 3ab}\)

\(8-{7 \over 3a}={8 \over 1}-{7 \over 3a}={24a \over 3a}-{7 \over 3a}={24a-7 \over 3a}\)

\({5x \over y}-{3 \over 9y}={45x \over 9y}-{3 \over 9y}={45x-3 \over 9y}={15x-1 \over 3y}\)

\({3x \over x}={3 \over 1}=3\)

\({a \over 4a}={1 \over 4}\)

\({-8p \over 12p}=-\frac{2}{3}\)

\({30x \over -5x}=-6\)

\({-10ab \over -18ac}={5b \over 9c}\)

\({10y \over -35xy}=-{2 \over 7x}\)

\({30abc \over 5bc}=6a\)

\({4ab \over b}-{7ac \over c}=4a-7a=-3a\)

\(5x-{7 \over 4x}={5x \over 1}⋅{4x \over 4x}-{7 \over 4x}={20x^2 \over 4x}-{7 \over 4x}={20x^2-7 \over 4x}\)

\({4b \over 8a}+{3a \over 6b}={12b^2 \over 24ab}+{12a^2 \over 24ab}={12a^2+12b^2 \over 24ab}={a^2+b^2 \over 2ab}\)

\({7 \over a}⋅-{6 \over b}=-{42 \over ab}\)

\({p \over 9}⋅-{8 \over q}=-{8p \over 9q}\)

\(-{5 \over 7}⋅x=-{5x \over 7}\)

\({2y \over x}⋅{x+4 \over 3}={2y(x+4) \over 3x}={2xy+8y \over 3x}\)

\({2 \over a}:{7 \over b}={2 \over a}⋅{b \over 7}={2b \over 7a}\)

\({9 \over 5}:x={9 \over 5}:{x \over 1}={9 \over 5}⋅{1 \over x}={9 \over 5x}\)

\(-{2 \over 7}:{a+6b \over b}=-{2 \over 7}⋅{b \over a+6b}=-{2b \over 7(a+6b)}=-{2b \over 7a+42b}\)

\({8p \over 3}+{p+5 \over 2}={16p \over 6}+{3(p+5) \over 6}={16p+3(p+5) \over 6}={19p+15 \over 6}\)

\({8a-5 \over -7a-9}-4={8a-5 \over -7a-9}+{-4(-7a-9) \over -7a-9}={8a-5-4(-7a-9) \over -7a-9}={8a-5+28a+36 \over -7a-9}={36a+31 \over -7a-9}\)

\({2x^2+6x+40 \over 2x}={2x^2 \over 2x}+{6x \over 2x}+{40 \over 2x}=x+3+{20 \over x}\)

\({x^2-5x+8 \over 7x^2}={x^2 \over 7x^2}-{5x \over 7x^2}+{8 \over 7x^2}=\frac{1}{7}-{5 \over 7x}+{8 \over 7x^2}\)