\({2 \over 6 p} + {7 \over 6 p} = {9 \over 6 p} = {3 \over 2 p}\)

\({9 \over x} + {8 \over 7 x} = {63 \over 7 x} + {8 \over 7 x} = {71 \over 7 x}\)

\({4 \over 3 a} - {5 \over 8 b} = {32 b \over 24 a b} - {15 a \over 24 a b} = {32 b - 15 a \over 24 a b}\)

\(6 + {5 \over 3 x} = {6 \over 1} + {5 \over 3 x} = {18 x \over 3 x} + {5 \over 3 x} = {18 x + 5 \over 3 x}\)

\({9 a \over b} - {3 \over 7 b} = {63 a \over 7 b} - {3 \over 7 b} = {63 a - 3 \over 7 b}\)

\({7 a \over a} = {7 \over 1} = 7\)

\({x \over 3 x} = {1 \over 3}\)

\({-14 a \over -16 a} = \frac{7}{8}\)

\({28 p \over -4 p} = -7\)

\({12 x y \over 20 x z} = {3 y \over 5 z}\)

\({-12 q \over -21 p q} = {4 \over 7 p}\)

\({-45 a b c \over 5 b c} = -9 a\)

\({6 x y \over y} + {2 x z \over z} = 6 x + 2 x = 8 x\)

\(9 x - {2 \over 5 x} = {9 x \over 1} ⋅ {5 x \over 5 x} - {2 \over 5 x} = {45 x^{2} \over 5 x} - {2 \over 5 x} = {45 x^{2} - 2 \over 5 x}\)

\({7 b \over 9 a} - {6 a \over 4 b} = {28 b^{2} \over 36 a b} - {54 a^{2} \over 36 a b} = {-54 a^{2} + 28 b^{2} \over 36 a b} = {-27 a^{2} + 14 b^{2} \over 18 a b}\)

\({9 \over x} ⋅ -{7 \over y} = -{63 \over x y}\)

\({p \over 9} ⋅ {3 \over q} = {3 p \over 9 q} = {p \over 3 q}\)

\({1 \over 3} ⋅ a = {a \over 3}\)

\({7 b \over a} ⋅ {a - 2 \over 8} = {7 b (a - 2) \over 8 a} = {7 a b - 14 b \over 8 a}\)

\({8 \over a} : {9 \over b} = {8 \over a} ⋅ {b \over 9} = {8 b \over 9 a}\)

\({6 \over 7} : p = {6 \over 7} : {p \over 1} = {6 \over 7} ⋅ {1 \over p} = {6 \over 7 p}\)

\(-{1 \over 3} : {x + 8 y \over y} = -{1 \over 3} ⋅ {y \over x + 8 y} = -{y \over 3 (x + 8 y)} = -{y \over 3 x + 24 y}\)

\({9 x \over 4} + {x - 2 \over 3} = {27 x \over 12} + {4 (x - 2) \over 12} = {27 x + 4 (x - 2) \over 12} = {31 x - 8 \over 12}\)

\({4 a - 3 \over 2 a + 5} - 8 = {4 a - 3 \over 2 a + 5} - {8 (2 a + 5) \over 2 a + 5} = {4 a - 3 - 8 (2 a + 5) \over 2 a + 5} = {4 a - 3 - 16 a - 40 \over 2 a + 5} = {-12 a - 43 \over 2 a + 5}\)

\({p^{2} + 3 p - 20 \over p} = {p^{2} \over p} + {3 p \over p} - {20 \over p} = p + 3 - {20 \over p}\)

\({2 x^{2} - 3 x + 5 \over 6 x^{2}} = {2 x^{2} \over 6 x^{2}} - {3 x \over 6 x^{2}} + {5 \over 6 x^{2}} = \frac{1}{3} - {1 \over 2 x} + {5 \over 6 x^{2}}\)