Getal & Ruimte (12e editie) - vwo wiskunde B
'Sinus, cosinus en tangens'.
| 3 vwo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 53 \text{,}\) \(\angle Q = 52\degree\) en \(\angle R = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle Q) = {P\kern{-.8pt}R \over Q\kern{-.8pt}R}\) ofwel \(\tan(52\degree) = {P\kern{-.8pt}R \over 53} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R = 53 ⋅ \tan(52\degree) \text{.}\) 1p ○ Dus \(P\kern{-.8pt}R ≈ 67{,}8 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 20 \text{,}\) \(\angle A = 32\degree\) en \(\angle B = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\tan(32\degree) = {20 \over A\kern{-.8pt}B} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = {20 \over \tan(32\degree)} \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 32{,}0 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 29 \text{,}\) \(P\kern{-.8pt}Q = 43\) en \(\angle P = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(\angle R) = {43 \over 29} \text{.}\) 1p ○ Hieruit volgt \(\angle R = \tan^{-1}({43 \over 29}) \text{.}\) 1p ○ Dus \(\angle R ≈ 56{,}0\degree \text{.}\) 1p |
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| 3 vwo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 58 \text{,}\) \(\angle M = 44\degree\) en \(\angle K = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle M) = {K\kern{-.8pt}L \over L\kern{-.8pt}M}\) ofwel \(\sin(44\degree) = {K\kern{-.8pt}L \over 58} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L = 58 ⋅ \sin(44\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}L ≈ 40{,}3 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 56 \text{,}\) \(\angle A = 40\degree\) en \(\angle B = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}C}\) ofwel \(\sin(40\degree) = {56 \over A\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C = {56 \over \sin(40\degree)} \text{.}\) 1p ○ Dus \(A\kern{-.8pt}C ≈ 87{,}1 \text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 52 \text{,}\) \(A\kern{-.8pt}C = 56\) en \(\angle B = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}C}\) ofwel \(\sin(\angle A) = {52 \over 56} \text{.}\) 1p ○ Hieruit volgt \(\angle A = \sin^{-1}({52 \over 56}) \text{.}\) 1p ○ Dus \(\angle A ≈ 68{,}2\degree \text{.}\) 1p 3p d Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 57 \text{,}\) \(\angle A = 40\degree\) en \(\angle B = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(40\degree) = {A\kern{-.8pt}B \over 57} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = 57 ⋅ \cos(40\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 43{,}7 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 32 \text{,}\) \(\angle K = 44\degree\) en \(\angle L = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(44\degree) = {32 \over K\kern{-.8pt}M} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = {32 \over \cos(44\degree)} \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 44{,}5 \text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 26 \text{,}\) \(K\kern{-.8pt}M = 38\) en \(\angle L = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(\angle K) = {26 \over 38} \text{.}\) 1p ○ Hieruit volgt \(\angle K = \cos^{-1}({26 \over 38}) \text{.}\) 1p ○ Dus \(\angle K ≈ 46{,}8\degree \text{.}\) 1p |