Getal & Ruimte (12e editie) - vwo wiskunde B
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{80}+\sqrt{500}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{80}+\sqrt{500}=\sqrt{16}⋅\sqrt{5}+\sqrt{100}⋅\sqrt{5}=4\sqrt{5}+10\sqrt{5}\text{.}\) 1p ○ \(4\sqrt{5}+10\sqrt{5}=14\sqrt{5}\text{.}\) 1p 1p b \(\sqrt{18}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{18}=\sqrt{9}⋅\sqrt{2}=3\sqrt{2}\text{.}\) 1p 1p c \(5\sqrt{300}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 1ms c \(5\sqrt{300}=5⋅\sqrt{100}⋅\sqrt{3}=5⋅10⋅\sqrt{3}=50\sqrt{3}\text{.}\) 1p 2p d \(2\sqrt{12}-4\sqrt{300}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms d \(2\sqrt{12}-4\sqrt{300}=2⋅\sqrt{4}⋅\sqrt{3}-4⋅\sqrt{100}⋅\sqrt{3}\text{.}\) 1p ○ \(2⋅2⋅\sqrt{3}-4⋅10⋅\sqrt{3}=4\sqrt{3}-40\sqrt{3}=-36\sqrt{3}\text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{1\frac{11}{25}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 103ms ○ \(\sqrt{1\frac{11}{25}}=\sqrt{\frac{36}{25}}={\sqrt{36} \over \sqrt{25}}=\frac{6}{5}=1\frac{1}{5}\text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({3 \over 4\sqrt{7}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms a \({3 \over 4\sqrt{7}}={3 \over 4\sqrt{7}}⋅{\sqrt{7} \over \sqrt{7}}={3\sqrt{7} \over 4⋅7}=\frac{3}{28}\sqrt{7}\text{.}\) 1p 1p b \(\sqrt{\frac{19}{100}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{\frac{19}{100}}={\sqrt{19} \over \sqrt{100}}={\sqrt{19} \over 10}=\frac{1}{10}\sqrt{19}\text{.}\) 1p 1p c \(\sqrt{2\frac{17}{32}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms c \(\sqrt{2\frac{17}{32}}=\sqrt{\frac{81}{32}}={\sqrt{81} \over \sqrt{32}}={9 \over \sqrt{32}}⋅{\sqrt{32} \over \sqrt{32}}={9\sqrt{32} \over 32}=\frac{9}{32}\sqrt{32}=\frac{9}{32}⋅4⋅\sqrt{2}=1\frac{1}{8}\sqrt{2}\text{.}\) 1p 1p d \(\sqrt{\frac{3}{28}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{\frac{3}{28}}={\sqrt{3} \over \sqrt{28}}⋅{\sqrt{28} \over \sqrt{28}}={\sqrt{84} \over 28}=\frac{1}{28}\sqrt{84}=\frac{1}{28}⋅2⋅\sqrt{21}=\frac{1}{14}\sqrt{21}\text{.}\) 1p opgave 2Herleid. 1p a \({36\sqrt{48} \over 4\sqrt{6}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 16ms a \({36\sqrt{48} \over 4\sqrt{6}}={36 \over 4}⋅{\sqrt{48} \over \sqrt{6}}=9\sqrt{8}=9⋅\sqrt{4}⋅\sqrt{2}=9⋅2⋅\sqrt{2}=18\sqrt{2}\) 1p 1p b \(4\sqrt{6}⋅5\sqrt{3}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 6ms - data pool: #22 (5ms) b \(4\sqrt{6}⋅5\sqrt{3}=20\sqrt{18}=20⋅\sqrt{9}⋅\sqrt{2}=20⋅3⋅\sqrt{2}=60\sqrt{2}\) 1p |