\({5 \over 7 x} + {9 \over 7 x} = {14 \over 7 x} = {2 \over x}\)

\({5 \over p} - {9 \over 7 p} = {35 \over 7 p} - {9 \over 7 p} = {26 \over 7 p}\)

\({7 \over 8 a} - {4 \over 2 b} = {7 b \over 8 a b} - {16 a \over 8 a b} = {7 b - 16 a \over 8 a b}\)

\(5 - {3 \over 7 a} = {5 \over 1} - {3 \over 7 a} = {35 a \over 7 a} - {3 \over 7 a} = {35 a - 3 \over 7 a}\)

\({9 x \over y} - {8 \over 5 y} = {45 x \over 5 y} - {8 \over 5 y} = {45 x - 8 \over 5 y}\)

\({5 a \over a} = {5 \over 1} = 5\)

\({x \over 9 x} = {1 \over 9}\)

\({21 x \over 27 x} = \frac{7}{9}\)

\({30 a \over -5 a} = -6\)

\({-9 p q \over 15 p r} = -{3 q \over 5 r}\)

\({10 q \over 16 p q} = {5 \over 8 p}\)

\({-15 a b c \over 5 b c} = -3 a\)

\({7 x y \over y} - {5 x z \over z} = 7 x - 5 x = 2 x\)

\(3 a - {4 \over 5 a} = {3 a \over 1} ⋅ {5 a \over 5 a} - {4 \over 5 a} = {15 a^{2} \over 5 a} - {4 \over 5 a} = {15 a^{2} - 4 \over 5 a}\)

\({6 b \over 3 a} - {7 a \over 9 b} = {18 b^{2} \over 9 a b} - {7 a^{2} \over 9 a b} = {-7 a^{2} + 18 b^{2} \over 9 a b}\)

\({6 \over x} ⋅ {4 \over y} = {24 \over x y}\)

\({p \over 5} ⋅ -{4 \over q} = -{4 p \over 5 q}\)

\(-{3 \over 4} ⋅ x = -{3 x \over 4}\)

\({5 y \over x} ⋅ {x + 8 \over 3} = {5 y (x + 8) \over 3 x} = {5 x y + 40 y \over 3 x}\)

\({4 \over x} : {8 \over y} = {4 \over x} ⋅ {y \over 8} = {4 y \over 8 x} = {y \over 2 x}\)

\(-{6 \over 5} : p = -{6 \over 5} : {p \over 1} = -{6 \over 5} ⋅ {1 \over p} = -{6 \over 5 p}\)

\(-{5 \over 2} : {a - 8 b \over b} = -{5 \over 2} ⋅ {b \over a - 8 b} = -{5 b \over 2 (a - 8 b)} = -{5 b \over 2 a - 16 b}\)

\({6 a \over 5} + {a + 3 \over 7} = {42 a \over 35} + {5 (a + 3) \over 35} = {42 a + 5 (a + 3) \over 35} = {47 a + 15 \over 35}\)

\({9 x - 3 \over -5 x + 2} - 7 = {9 x - 3 \over -5 x + 2} + {-7 (-5 x + 2) \over -5 x + 2} = {9 x - 3 - 7 (-5 x + 2) \over -5 x + 2} = {9 x - 3 + 35 x - 14 \over -5 x + 2} = {44 x - 17 \over -5 x + 2}\)