\({8 \over 3x}-{7 \over 3x}={1 \over 3x}\)

\({3 \over a}+{5 \over 2a}={6 \over 2a}+{5 \over 2a}={11 \over 2a}\)

\({9 \over 4x}-{5 \over 6y}={27y \over 12xy}-{10x \over 12xy}={27y-10x \over 12xy}\)

\(7-{9 \over 8p}={7 \over 1}-{9 \over 8p}={56p \over 8p}-{9 \over 8p}={56p-9 \over 8p}\)

\({6a \over b}-{3 \over 5b}={30a \over 5b}-{3 \over 5b}={30a-3 \over 5b}\)

\({7p \over p}={7 \over 1}=7\)

\({a \over 8a}={1 \over 8}\)

\({-20x \over 32x}=-\frac{5}{8}\)

\({16x \over -4x}=-4\)

\({-25ab \over -40ac}={5b \over 8c}\)

\({-16b \over -18ab}={8 \over 9a}\)

\({10abc \over -5bc}=-2a\)

\({3pq \over q}-{5pr \over r}=3p-5p=-2p\)

\(3x+{7 \over 6x}={3x \over 1}⋅{6x \over 6x}+{7 \over 6x}={18x^2 \over 6x}+{7 \over 6x}={18x^2+7 \over 6x}\)

\({8b \over 4a}+{2a \over 3b}={24b^2 \over 12ab}+{8a^2 \over 12ab}={8a^2+24b^2 \over 12ab}={2a^2+6b^2 \over 3ab}\)

\({5 \over a}⋅-{4 \over b}=-{20 \over ab}\)

\({p \over 2}⋅-{9 \over q}=-{9p \over 2q}\)

\(-{5 \over 9}⋅x=-{5x \over 9}\)

\({5q \over p}⋅{p+8 \over 2}={5q(p+8) \over 2p}={5pq+40q \over 2p}\)

\({8 \over a}:{5 \over b}={8 \over a}⋅{b \over 5}={8b \over 5a}\)

\(-{1 \over 9}:x=-{1 \over 9}:{x \over 1}=-{1 \over 9}⋅{1 \over x}=-{1 \over 9x}\)

\(-{4 \over 5}:{a+b \over b}=-{4 \over 5}⋅{b \over a+b}=-{4b \over 5(a+b)}=-{4b \over 5a+5b}\)

\({5x \over 9}+{x-2 \over 8}={40x \over 72}+{9(x-2) \over 72}={40x+9(x-2) \over 72}={49x-18 \over 72}\)

\({-3p-1 \over 4p-5}+8={-3p-1 \over 4p-5}+{8(4p-5) \over 4p-5}={-3p-1+8(4p-5) \over 4p-5}={-3p-1+32p-40 \over 4p-5}={29p-41 \over 4p-5}\)