\({2 \over 8 a} - {3 \over 8 a} = -{1 \over 8 a}\)

\({9 \over x} - {8 \over 7 x} = {63 \over 7 x} - {8 \over 7 x} = {55 \over 7 x}\)

\({8 \over 2 x} + {7 \over 3 y} = {24 y \over 6 x y} + {14 x \over 6 x y} = {24 y + 14 x \over 6 x y} = {12 y + 7 x \over 3 x y}\)

\(9 - {7 \over 6 a} = {9 \over 1} - {7 \over 6 a} = {54 a \over 6 a} - {7 \over 6 a} = {54 a - 7 \over 6 a}\)

\({2 p \over q} + {4 \over 5 q} = {10 p \over 5 q} + {4 \over 5 q} = {10 p + 4 \over 5 q}\)

\({7 x \over x} = {7 \over 1} = 7\)

\({a \over 7 a} = {1 \over 7}\)

\({12 a \over 14 a} = \frac{6}{7}\)

\({32 p \over 4 p} = 8\)

\({25 x y \over 35 x z} = {5 y \over 7 z}\)

\({9 y \over 12 x y} = {3 \over 4 x}\)

\({8 p q r \over -2 q r} = -4 p\)

\({2 a b \over b} - {6 a c \over c} = 2 a - 6 a = -4 a\)

\(3 x + {9 \over 8 x} = {3 x \over 1} ⋅ {8 x \over 8 x} + {9 \over 8 x} = {24 x^{2} \over 8 x} + {9 \over 8 x} = {24 x^{2} + 9 \over 8 x}\)

\({8 b \over 4 a} + {3 a \over 9 b} = {72 b^{2} \over 36 a b} + {12 a^{2} \over 36 a b} = {12 a^{2} + 72 b^{2} \over 36 a b} = {a^{2} + 6 b^{2} \over 3 a b}\)

\({9 \over x} ⋅ {3 \over y} = {27 \over x y}\)

\({a \over 2} ⋅ -{3 \over b} = -{3 a \over 2 b}\)

\({3 \over 2} ⋅ p = {3 p \over 2}\)

\({8 y \over x} ⋅ {x + 2 \over 5} = {8 y (x + 2) \over 5 x} = {8 x y + 16 y \over 5 x}\)

\({5 \over a} : {9 \over b} = {5 \over a} ⋅ {b \over 9} = {5 b \over 9 a}\)

\({9 \over 7} : x = {9 \over 7} : {x \over 1} = {9 \over 7} ⋅ {1 \over x} = {9 \over 7 x}\)

\(-{8 \over 9} : {a + 7 b \over b} = -{8 \over 9} ⋅ {b \over a + 7 b} = -{8 b \over 9 (a + 7 b)} = -{8 b \over 9 a + 63 b}\)

\({p \over 8} + {p + 6 \over 3} = {3 p \over 24} + {8 (p + 6) \over 24} = {3 p + 8 (p + 6) \over 24} = {11 p + 48 \over 24}\)

\({-8 a + 7 \over 6 a - 3} - 4 = {-8 a + 7 \over 6 a - 3} - {4 (6 a - 3) \over 6 a - 3} = {-8 a + 7 - 4 (6 a - 3) \over 6 a - 3} = {-8 a + 7 - 24 a + 12 \over 6 a - 3} = {-32 a + 19 \over 6 a - 3}\)