Aftrekken geeft \(a = 3 \text{.}\)

\(\begin{rcases}6 a - 4 b = -2 \\ a = 3\end{rcases} \begin{matrix}6 ⋅ 3 - 4 b = -2 \\ -4 b = -20 \\ b = 5\end{matrix}\)

De oplossing is \((a , b) = (3 , 5) \text{.}\)

\(\begin{cases}2 a - 6 b = 4 \\ 5 a + 3 b = 1\end{cases}\) \(\begin{vmatrix}1 \\ 2\end{vmatrix}\) geeft \(\begin{cases}2 a - 6 b = 4 \\ 10 a + 6 b = 2\end{cases}\)

Optellen geeft \(12 a = 6 \text{,}\) dus \(a = \frac{1}{2} \text{.}\)

\(\begin{rcases}2 a - 6 b = 4 \\ a = \frac{1}{2}\end{rcases} \begin{matrix}2 ⋅ \frac{1}{2} - 6 b = 4 \\ -6 b = 3 \\ b = -\frac{1}{2}\end{matrix}\)

De oplossing is \((a , b) = (\frac{1}{2} , -\frac{1}{2}) \text{.}\)

\(\begin{cases}6 x + 4 y = -2 \\ 5 x + 3 y = 1\end{cases}\) \(\begin{vmatrix}3 \\ 4\end{vmatrix}\) geeft \(\begin{cases}18 x + 12 y = -6 \\ 20 x + 12 y = 4\end{cases}\)

Aftrekken geeft \(-2 x = -10 \text{,}\) dus \(x = 5 \text{.}\)

\(\begin{rcases}6 x + 4 y = -2 \\ x = 5\end{rcases} \begin{matrix}6 ⋅ 5 + 4 y = -2 \\ 4 y = -32 \\ y = -8\end{matrix}\)

De oplossing is \((x , y) = (5 , -8) \text{.}\)