Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(64 : 4 : 2\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(64 : 4 : 2 = 16 : 2 = 8 \text{.}\) 1p 1p b \(9 + 2 ⋅ 3\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(9 + 2 ⋅ 3 = 9 + 6 = 15 \text{.}\) 1p 1p c \((5 + 8) ⋅ 3\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((5 + 8) ⋅ 3 = 13 ⋅ 3 = 39 \text{.}\) 1p 1p d \(18 : 3 ⋅ 8\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(18 : 3 ⋅ 8 = 6 ⋅ 8 = 48 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 14 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 14 : 2 = 9 - 7 = 2 \text{.}\) 1p 1p b \(3 + 2 ⋅ (6 + 4)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(3 + 2 ⋅ (6 + 4) = 3 + 2 ⋅ 10 = 3 + 20 = 23 \text{.}\) 1p 1p c \((7 + 5) ⋅ (9 + 2)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((7 + 5) ⋅ (9 + 2) = 12 ⋅ 11 = 132 \text{.}\) 1p 1p d \(38 - 4 ⋅ 9 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(38 - 4 ⋅ 9 + 7 = 38 - 36 + 7 = 2 + 7 = 9 \text{.}\) 1p opgave 3Bereken. 1p \((16 - (5 + 3)) ⋅ 7\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((16 - (5 + 3)) ⋅ 7 = (16 - 8) ⋅ 7 = 8 ⋅ 7 = 56 \text{.}\) 1p |