Getal & Ruimte (13e editie) - 1 havo/vwo
'Rekenvolgorde'.
| 1 havo/vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(30 : 5 : 3\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(30 : 5 : 3 = 6 : 3 = 2 \text{.}\) 1p 1p b \(5 + 4 ⋅ 2\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(5 + 4 ⋅ 2 = 5 + 8 = 13 \text{.}\) 1p 1p c \((8 + 2) ⋅ 6\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((8 + 2) ⋅ 6 = 10 ⋅ 6 = 60 \text{.}\) 1p 1p d \(21 : 3 ⋅ 9\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(21 : 3 ⋅ 9 = 7 ⋅ 9 = 63 \text{.}\) 1p opgave 2Bereken. 1p a \(8 - 35 : 5\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(8 - 35 : 5 = 8 - 7 = 1 \text{.}\) 1p 1p b \(6 + 8 ⋅ (3 + 2)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(6 + 8 ⋅ (3 + 2) = 6 + 8 ⋅ 5 = 6 + 40 = 46 \text{.}\) 1p 1p c \((3 + 2) ⋅ (5 + 7)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((3 + 2) ⋅ (5 + 7) = 5 ⋅ 12 = 60 \text{.}\) 1p 1p d \(43 - 8 ⋅ 5 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(43 - 8 ⋅ 5 + 7 = 43 - 40 + 7 = 3 + 7 = 10 \text{.}\) 1p opgave 3Bereken. 1p \((11 - (5 + 2)) ⋅ 6\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((11 - (5 + 2)) ⋅ 6 = (11 - 7) ⋅ 6 = 4 ⋅ 6 = 24 \text{.}\) 1p |