Getal & Ruimte (13e editie) - 1 havo/vwo

'Rekenvolgorde'.

1 havo/vwo 2.1 Bewerkingen

Rekenvolgorde (9)

opgave 1

Bereken.

1p

a

\(24 : 4 : 3\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(24 : 4 : 3 = 6 : 3 = 2 \text{.}\)

1p

1p

b

\(3 + 5 ⋅ 4\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(3 + 5 ⋅ 4 = 3 + 20 = 23 \text{.}\)

1p

1p

c

\((3 + 9) ⋅ 2\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((3 + 9) ⋅ 2 = 12 ⋅ 2 = 24 \text{.}\)

1p

1p

d

\(24 : 6 ⋅ 3\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(24 : 6 ⋅ 3 = 4 ⋅ 3 = 12 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(9 - 16 : 2\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(9 - 16 : 2 = 9 - 8 = 1 \text{.}\)

1p

1p

b

\(6 + 2 ⋅ (9 + 3)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(6 + 2 ⋅ (9 + 3) = 6 + 2 ⋅ 12 = 6 + 24 = 30 \text{.}\)

1p

1p

c

\((7 + 6) ⋅ (5 + 3)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((7 + 6) ⋅ (5 + 3) = 13 ⋅ 8 = 104 \text{.}\)

1p

1p

d

\(10 - 2 ⋅ 3 + 8\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(10 - 2 ⋅ 3 + 8 = 10 - 6 + 8 = 4 + 8 = 12 \text{.}\)

1p

opgave 3

Bereken.

1p

\((16 - (9 + 5)) ⋅ 3\)

PositiefVierDelen (4)
00ap - Rekenvolgorde - basis - 0ms

○

\((16 - (9 + 5)) ⋅ 3 = (16 - 14) ⋅ 3 = 2 ⋅ 3 = 6 \text{.}\)

1p

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