Getal & Ruimte (13e editie) - 1 havo/vwo
'Som hoeken is 180 graden'.
| 1 havo/vwo | 5.6 Hoekensom driehoek |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(\angle A=55\degree\) en \(\angle B=60\degree\text{.}\) Som180GradenScherp 007e - Som hoeken is 180 graden - basis - 0ms a De som van de hoeken in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\angle A+\angle B+\angle C=180\degree\text{.}\) 1p ○ Dus \(\angle C=180\degree-\angle A-\angle B\text{.}\) 1p ○ \(\angle C=180\degree-55\degree-60\degree=65\degree\text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(\angle P=31\degree\) en \(\angle Q=34\degree\text{.}\) Som180GradenStomp 007f - Som hoeken is 180 graden - basis - 2ms b De som van de hoeken in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\angle P+\angle Q+\angle R=180\degree\text{.}\) 1p ○ Dus \(\angle R=180\degree-\angle P-\angle Q\text{.}\) 1p ○ \(\angle R=180\degree-31\degree-34\degree=115\degree\text{.}\) 1p |