Getal & Ruimte (13e editie) - 1 vwo
'Rekenvolgorde'.
| 1 vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(72 : 4 : 2\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(72 : 4 : 2 = 18 : 2 = 9 \text{.}\) 1p 1p b \(2 + 4 ⋅ 5\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(2 + 4 ⋅ 5 = 2 + 20 = 22 \text{.}\) 1p 1p c \((6 + 9) ⋅ 5\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((6 + 9) ⋅ 5 = 15 ⋅ 5 = 75 \text{.}\) 1p 1p d \(28 : 4 ⋅ 9\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(28 : 4 ⋅ 9 = 7 ⋅ 9 = 63 \text{.}\) 1p opgave 2Bereken. 1p a \(8 - 28 : 4\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(8 - 28 : 4 = 8 - 7 = 1 \text{.}\) 1p 1p b \(8 + 5 ⋅ (6 + 3)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(8 + 5 ⋅ (6 + 3) = 8 + 5 ⋅ 9 = 8 + 45 = 53 \text{.}\) 1p 1p c \((6 + 3) ⋅ (7 + 4)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((6 + 3) ⋅ (7 + 4) = 9 ⋅ 11 = 99 \text{.}\) 1p 1p d \(21 - 4 ⋅ 3 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(21 - 4 ⋅ 3 + 7 = 21 - 12 + 7 = 9 + 7 = 16 \text{.}\) 1p opgave 3Bereken. 1p \((13 - (3 + 6)) ⋅ 5\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((13 - (3 + 6)) ⋅ 5 = (13 - 9) ⋅ 5 = 4 ⋅ 5 = 20 \text{.}\) 1p |