Getal & Ruimte (13e editie) - 1 vwo
'Rekenvolgorde'.
| 1 vwo | 2.1 Bewerkingen |
opgave 1Bereken. 1p a \(24 : 4 : 2\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 0ms a \(24 : 4 : 2 = 6 : 2 = 3 \text{.}\) 1p 1p b \(9 + 3 ⋅ 5\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 0ms b \(9 + 3 ⋅ 5 = 9 + 15 = 24 \text{.}\) 1p 1p c \((2 + 7) ⋅ 9\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((2 + 7) ⋅ 9 = 9 ⋅ 9 = 81 \text{.}\) 1p 1p d \(32 : 4 ⋅ 5\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(32 : 4 ⋅ 5 = 8 ⋅ 5 = 40 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 14 : 2\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 14 : 2 = 9 - 7 = 2 \text{.}\) 1p 1p b \(4 + 9 ⋅ (2 + 3)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(4 + 9 ⋅ (2 + 3) = 4 + 9 ⋅ 5 = 4 + 45 = 49 \text{.}\) 1p 1p c \((8 + 5) ⋅ (4 + 2)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((8 + 5) ⋅ (4 + 2) = 13 ⋅ 6 = 78 \text{.}\) 1p 1p d \(78 - 9 ⋅ 8 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(78 - 9 ⋅ 8 + 7 = 78 - 72 + 7 = 6 + 7 = 13 \text{.}\) 1p opgave 3Bereken. 1p \((15 - (8 + 2)) ⋅ 4\) PositiefVierDelen (4) 00ap - Rekenvolgorde - basis - 0ms ○ \((15 - (8 + 2)) ⋅ 4 = (15 - 10) ⋅ 4 = 5 ⋅ 4 = 20 \text{.}\) 1p |