\({9 \over 8 x} + {7 \over 8 x} = {16 \over 8 x} = {2 \over x}\)

\({9 \over x} - {3 \over 8 x} = {72 \over 8 x} - {3 \over 8 x} = {69 \over 8 x}\)

\({3 \over 6 p} + {8 \over 2 q} = {3 q \over 6 p q} + {24 p \over 6 p q} = {3 q + 24 p \over 6 p q} = {q + 8 p \over 2 p q}\)

\(6 - {8 \over 3 a} = {6 \over 1} - {8 \over 3 a} = {18 a \over 3 a} - {8 \over 3 a} = {18 a - 8 \over 3 a}\)

\(3 a - {9 \over 8 a} = {3 a \over 1} ⋅ {8 a \over 8 a} - {9 \over 8 a} = {24 a^{2} \over 8 a} - {9 \over 8 a} = {24 a^{2} - 9 \over 8 a}\)

\({6 x \over y} - {4 \over 8 y} = {48 x \over 8 y} - {4 \over 8 y} = {48 x - 4 \over 8 y} = {12 x - 1 \over 2 y}\)

\({5 y \over 3 x} - {2 x \over 8 y} = {40 y^{2} \over 24 x y} - {6 x^{2} \over 24 x y} = {-6 x^{2} + 40 y^{2} \over 24 x y} = {-3 x^{2} + 20 y^{2} \over 12 x y}\)

\({5 p \over p} = {5 \over 1} = 5\)

\({a \over 8 a} = {1 \over 8}\)

\({-8 a \over 20 a} = -\frac{2}{5}\)

\({-16 a \over 2 a} = -8\)

\({-25 x y \over -40 x z} = {5 y \over 8 z}\)

\({14 q \over 18 p q} = {7 \over 9 p}\)

\({16 a b c \over -4 b c} = -4 a\)

\({6 x y \over y} + {4 x z \over z} = 6 x + 4 x = 10 x\)

\({3 \over p} ⋅ -{8 \over q} = -{24 \over p q}\)

\({x \over 2} ⋅ -{3 \over y} = -{3 x \over 2 y}\)

\({7 \over 9} ⋅ a = {7 a \over 9}\)

\({4 \over a} : {8 \over b} = {4 \over a} ⋅ {b \over 8} = {4 b \over 8 a} = {b \over 2 a}\)

\(-{8 \over 7} : x = -{8 \over 7} : {x \over 1} = -{8 \over 7} ⋅ {1 \over x} = -{8 \over 7 x}\)