Getal & Ruimte (13e editie) - 2 havo/vwo
'Rekenen met breuken'.
| 2 havo/vwo | 1.3 Breuken vermenigvuldigen en delen |
opgave 1Bereken. 1p a \(-\frac{1}{2} ⋅ -\frac{2}{7}\) Vermenigvuldigen (1) 00du - Rekenen met breuken - basis - 108ms - data pool: #33020 (107ms) a \(-\frac{1}{2} ⋅ -\frac{2}{7} = \frac{2}{14} = \frac{1}{7}\) 1p 1p b \(-8\frac{1}{2} ⋅ -\frac{1}{9}\) Vermenigvuldigen (2) 00dv - Rekenen met breuken - basis - 1ms - data pool: #33020 (107ms) b \(-8\frac{1}{2} ⋅ -\frac{1}{9} = -\frac{17}{2} ⋅ -\frac{1}{9} = \frac{17}{18}\) 1p 1p c \(-1\frac{1}{4} ⋅ 2\frac{1}{2}\) Vermenigvuldigen (3) 00dw - Rekenen met breuken - basis - 0ms - data pool: #33020 (107ms) c \(-1\frac{1}{4} ⋅ 2\frac{1}{2} = -\frac{5}{4} ⋅ \frac{5}{2} = -\frac{25}{8} = -3\frac{1}{8}\) 1p 1p d \(1\frac{1}{2} ⋅ -3\) Vermenigvuldigen (4) 00dx - Rekenen met breuken - basis - 0ms - data pool: #33020 (107ms) d \(1\frac{1}{2} ⋅ -3 = \frac{3}{2} ⋅ -\frac{3}{1} = -\frac{9}{2} = -4\frac{1}{2}\) 1p opgave 2Bereken. 1p a \(\frac{1}{4} : \frac{1}{3}\) Delen (1) 00dy - Rekenen met breuken - basis - 140ms - data pool: #43684 (140ms) a \(\frac{1}{4} : \frac{1}{3} = \frac{1}{4} ⋅ \frac{3}{1} = \frac{3}{4}\) 1p 1p b \(2\frac{1}{5} : -\frac{7}{8}\) Delen (2) 00dz - Rekenen met breuken - basis - 1ms - data pool: #43684 (140ms) b \(2\frac{1}{5} : -\frac{7}{8} = \frac{11}{5} : -\frac{7}{8} = \frac{11}{5} ⋅ -\frac{8}{7} = -\frac{88}{35} = -2\frac{18}{35}\) 1p 1p c \(-1\frac{1}{3} : -3\frac{3}{5}\) Delen (3) 00e0 - Rekenen met breuken - basis - 0ms - data pool: #43684 (140ms) c \(-1\frac{1}{3} : -3\frac{3}{5} = -\frac{4}{3} : -\frac{18}{5} = -\frac{4}{3} ⋅ -\frac{5}{18} = \frac{20}{54} = \frac{10}{27}\) 1p 1p d \(-\frac{4}{9} : 4\) Delen (4) 00e1 - Rekenen met breuken - basis - 0ms - data pool: #43684 (140ms) d \(-\frac{4}{9} : 4 = -\frac{4}{9} : \frac{4}{1} = -\frac{4}{9} ⋅ \frac{1}{4} = -\frac{4}{36} = -\frac{1}{9}\) 1p |