\({7 \over 9p}+{8 \over 9p}={15 \over 9p}={5 \over 3p}\)

\({3 \over x}-{2 \over 6x}={18 \over 6x}-{2 \over 6x}={16 \over 6x}={8 \over 3x}\)

\({9 \over 7x}-{4 \over 5y}={45y \over 35xy}-{28x \over 35xy}={45y-28x \over 35xy}\)

\(5+{8 \over 3a}={5 \over 1}+{8 \over 3a}={15a \over 3a}+{8 \over 3a}={15a+8 \over 3a}\)

\({5a \over b}+{9 \over 2b}={10a \over 2b}+{9 \over 2b}={10a+9 \over 2b}\)

\({2x \over x}={2 \over 1}=2\)

\({a \over 6a}={1 \over 6}\)

\({21a \over -24a}=-\frac{7}{8}\)

\({-12x \over -2x}=6\)

\({12pq \over -15pr}=-{4q \over 5r}\)

\({6y \over -8xy}=-{3 \over 4x}\)

\({16xyz \over 4yz}=4x\)

\({3pq \over q}+{7pr \over r}=3p+7p=10p\)

\(4p-{5 \over 3p}={4p \over 1}⋅{3p \over 3p}-{5 \over 3p}={12p^2 \over 3p}-{5 \over 3p}={12p^2-5 \over 3p}\)

\({4b \over 8a}-{7a \over 2b}={4b^2 \over 8ab}-{28a^2 \over 8ab}={-28a^2+4b^2 \over 8ab}={-7a^2+b^2 \over 2ab}\)

\({9 \over a}⋅{6 \over b}={54 \over ab}\)

\({x \over 7}⋅{2 \over y}={2x \over 7y}\)

\(-{1 \over 5}⋅x=-{x \over 5}\)

\({4q \over p}⋅{p+2 \over 6}={4q(p+2) \over 6p}={2q(p+2) \over 3p}={2pq+4q \over 3p}\)

\({9 \over x}:{4 \over y}={9 \over x}⋅{y \over 4}={9y \over 4x}\)

\(-{3 \over 4}:x=-{3 \over 4}:{x \over 1}=-{3 \over 4}⋅{1 \over x}=-{3 \over 4x}\)

\({6 \over 7}:{a+3b \over b}={6 \over 7}⋅{b \over a+3b}={6b \over 7(a+3b)}={6b \over 7a+21b}\)

\({9a \over 5}+{a+2 \over 4}={36a \over 20}+{5(a+2) \over 20}={36a+5(a+2) \over 20}={41a+10 \over 20}\)