\({9 \over 7 p} + {2 \over 7 p} = {11 \over 7 p}\)

\({5 \over a} - {4 \over 2 a} = {10 \over 2 a} - {4 \over 2 a} = {6 \over 2 a} = {3 \over a}\)

\({6 \over 9 x} - {8 \over 4 y} = {24 y \over 36 x y} - {72 x \over 36 x y} = {24 y - 72 x \over 36 x y} = {2 y - 6 x \over 3 x y}\)

\(8 - {5 \over 2 a} = {8 \over 1} - {5 \over 2 a} = {16 a \over 2 a} - {5 \over 2 a} = {16 a - 5 \over 2 a}\)

\({9 x \over y} - {6 \over 4 y} = {36 x \over 4 y} - {6 \over 4 y} = {36 x - 6 \over 4 y} = {18 x - 3 \over 2 y}\)

\({6 a \over a} = {6 \over 1} = 6\)

\({a \over 5 a} = {1 \over 5}\)

\({21 x \over 24 x} = \frac{7}{8}\)

\({30 p \over -5 p} = -6\)

\({14 x y \over 16 x z} = {7 y \over 8 z}\)

\({12 y \over -28 x y} = -{3 \over 7 x}\)

\({35 a b c \over 5 b c} = 7 a\)

\({2 x y \over y} + {5 x z \over z} = 2 x + 5 x = 7 x\)

\(5 a + {8 \over 3 a} = {5 a \over 1} ⋅ {3 a \over 3 a} + {8 \over 3 a} = {15 a^{2} \over 3 a} + {8 \over 3 a} = {15 a^{2} + 8 \over 3 a}\)

\({9 b \over 5 a} - {4 a \over 6 b} = {54 b^{2} \over 30 a b} - {20 a^{2} \over 30 a b} = {-20 a^{2} + 54 b^{2} \over 30 a b} = {-10 a^{2} + 27 b^{2} \over 15 a b}\)

\({6 \over x} ⋅ -{4 \over y} = -{24 \over x y}\)

\({x \over 8} ⋅ {7 \over y} = {7 x \over 8 y}\)

\({3 \over 8} ⋅ p = {3 p \over 8}\)

\({4 b \over a} ⋅ {a - 7 \over 6} = {4 b (a - 7) \over 6 a} = {2 b (a - 7) \over 3 a} = {2 a b - 14 b \over 3 a}\)

\({3 \over a} : {8 \over b} = {3 \over a} ⋅ {b \over 8} = {3 b \over 8 a}\)

\(-{6 \over 5} : x = -{6 \over 5} : {x \over 1} = -{6 \over 5} ⋅ {1 \over x} = -{6 \over 5 x}\)

\({5 \over 2} : {x - 6 y \over y} = {5 \over 2} ⋅ {y \over x - 6 y} = {5 y \over 2 (x - 6 y)} = {5 y \over 2 x - 12 y}\)

\({7 p \over 6} + {p + 4 \over 5} = {35 p \over 30} + {6 (p + 4) \over 30} = {35 p + 6 (p + 4) \over 30} = {41 p + 24 \over 30}\)