Getal & Ruimte (13e editie) - 2 vwo
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({8 \over 9 a} + {7 \over 9 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({8 \over 9 a} + {7 \over 9 a} = {15 \over 9 a} = {5 \over 3 a}\) 1p 1p b \({4 \over x} + {5 \over 3 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({4 \over x} + {5 \over 3 x} = {12 \over 3 x} + {5 \over 3 x} = {17 \over 3 x}\) 1p 1p c \({3 \over 9 x} - {8 \over 2 y}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({3 \over 9 x} - {8 \over 2 y} = {6 y \over 18 x y} - {72 x \over 18 x y} = {6 y - 72 x \over 18 x y} = {y - 12 x \over 3 x y}\) 1p 1p d \(5 + {3 \over 2 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(5 + {3 \over 2 a} = {5 \over 1} + {3 \over 2 a} = {10 a \over 2 a} + {3 \over 2 a} = {10 a + 3 \over 2 a}\) 1p opgave 2Herleid tot één breuk. 1p \({4 p \over q} - {3 \over 9 q}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({4 p \over q} - {3 \over 9 q} = {36 p \over 9 q} - {3 \over 9 q} = {36 p - 3 \over 9 q} = {12 p - 1 \over 3 q}\) 1p opgave 3Herleid. 1p a \({7 a \over a}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({7 a \over a} = {7 \over 1} = 7\) 1p 1p b \({p \over 7 p}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({p \over 7 p} = {1 \over 7}\) 1p 1p c \({32 x \over 36 x}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({32 x \over 36 x} = \frac{8}{9}\) 1p 1p d \({-10 a \over -5 a}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-10 a \over -5 a} = 2\) 1p opgave 4Herleid. 1p a \({10 x y \over 12 x z}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({10 x y \over 12 x z} = {5 y \over 6 z}\) 1p 1p b \({15 b \over -27 a b}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({15 b \over -27 a b} = -{5 \over 9 a}\) 1p 1p c \({25 p q r \over 5 q r}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({25 p q r \over 5 q r} = 5 p\) 1p 1p d \({5 x y \over y} + {4 x z \over z}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({5 x y \over y} + {4 x z \over z} = 5 x + 4 x = 9 x\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(9 x + {6 \over 5 x}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(9 x + {6 \over 5 x} = {9 x \over 1} ⋅ {5 x \over 5 x} + {6 \over 5 x} = {45 x^{2} \over 5 x} + {6 \over 5 x} = {45 x^{2} + 6 \over 5 x}\) 1p 1p b \({4 y \over 7 x} + {6 x \over 5 y}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({4 y \over 7 x} + {6 x \over 5 y} = {20 y^{2} \over 35 x y} + {42 x^{2} \over 35 x y} = {42 x^{2} + 20 y^{2} \over 35 x y}\) 1p 1p c \({3 \over a} ⋅ {2 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({3 \over a} ⋅ {2 \over b} = {6 \over a b}\) 1p 1p d \({p \over 8} ⋅ {2 \over q}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({p \over 8} ⋅ {2 \over q} = {2 p \over 8 q} = {p \over 4 q}\) 1p opgave 2Herleid tot één breuk. 1p a \({1 \over 4} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \({1 \over 4} ⋅ a = {a \over 4}\) 1p 1p b \({3 y \over x} ⋅ {x - 5 \over 2}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({3 y \over x} ⋅ {x - 5 \over 2} = {3 y (x - 5) \over 2 x} = {3 x y - 15 y \over 2 x}\) 1p 1p c \({6 \over p} : {3 \over q}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({6 \over p} : {3 \over q} = {6 \over p} ⋅ {q \over 3} = {6 q \over 3 p} = {2 q \over p}\) 1p 1p d \(-{3 \over 4} : x\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \(-{3 \over 4} : x = -{3 \over 4} : {x \over 1} = -{3 \over 4} ⋅ {1 \over x} = -{3 \over 4 x}\) 1p opgave 3Herleid tot één breuk. 1p a \({9 \over 5} : {a - 7 b \over b}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \({9 \over 5} : {a - 7 b \over b} = {9 \over 5} ⋅ {b \over a - 7 b} = {9 b \over 5 (a - 7 b)} = {9 b \over 5 a - 35 b}\) 1p 1p b \({5 a \over 4} + {a + 3 \over 7}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables b \({5 a \over 4} + {a + 3 \over 7} = {35 a \over 28} + {4 (a + 3) \over 28} = {35 a + 4 (a + 3) \over 28} = {39 a + 12 \over 28}\) 1p |