Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 5 a\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 5 a = a (a + 5)\) 1p 1p b \(24 x^{2} - 27 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(24 x^{2} - 27 x = 3 x (8 x - 9)\) 1p 1p c \(25 x y + 35 x\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(25 x y + 35 x = 5 x (5 y + 7)\) 1p 1p d \(24 p q + 27 p r\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(24 p q + 27 p r = 3 p (8 q + 9 r)\) 1p opgave 2Ontbind in factoren. 1p a \(15 a b c + 25 a b\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(15 a b c + 25 a b = 5 a b (3 c + 5)\) 1p 1p b \(28 x^{2} + 32 x^{5}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(28 x^{2} + 32 x^{5} = 4 x^{2} (7 + 8 x^{3})\) 1p 1p c \(2 a^{3} - 7 a^{6} + a^{4}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(2 a^{3} - 7 a^{6} + a^{4} = a^{3} (2 - 7 a^{3} + a)\) 1p 1p d \(9 p^{3} q^{2} - 12 p q^{3}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(9 p^{3} q^{2} - 12 p q^{3} = 3 p q^{2} (3 p^{2} - 4 q)\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 25\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 25 = (a - 5) (a + 5)\) 1p 1p b \(144 x^{2} - 121\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(144 x^{2} - 121 = (12 x - 11) (12 x + 11)\) 1p 1p c \(9 - 16 a^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(9 - 16 a^{2} = (3 - 4 a) (3 + 4 a)\) 1p 1p d \(64 p^{10} - 121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(64 p^{10} - 121 = (8 p^{5} - 11) (8 p^{5} + 11)\) 1p opgave 4Ontbind in factoren. 1p a \(50 a^{2} - 18\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(50 a^{2} - 18 = 2 (25 a^{2} - 9) = 2 (5 a - 3) (5 a + 3)\) 1p 1p b \(2 x^{3} - 50 x\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(2 x^{3} - 50 x = 2 x (x^{2} - 25) = 2 x (x - 5) (x + 5)\) 1p 1p c \(x^{12} - 81\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{12} - 81 = (x^{6} - 9) (x^{6} + 9) = (x^{3} - 3) (x^{3} + 3) (x^{6} + 9)\) 1p 1p d \(2 a^{9} - 162 a\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(2 a^{9} - 162 a = 2 a (a^{8} - 81) = 2 a (a^{4} - 9) (a^{4} + 9) = 2 a (a^{2} - 3) (a^{2} + 3) (a^{4} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(x^{8} y^{4} - 25 z^{10}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(x^{8} y^{4} - 25 z^{10} = (x^{4} y^{2} - 5 z^{5}) (x^{4} y^{2} + 5 z^{5})\) 1p |
|
| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 17 a + 72\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 17 a + 72 = (a + 9) (a + 8)\) 1p 1p b \(p^{2} - p - 30\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^{2} - p - 30 = (p - 6) (p + 5)\) 1p 1p c \(x^{2} - 7 x + 10\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 7 x + 10 = (x - 5) (x - 2)\) 1p 1p d \(x^{2} - 12 x + 36\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} - 12 x + 36 = (x - 6) (x - 6)\) 1p opgave 2Ontbind in factoren. 1p a \(2 a^{3} - 2 a^{2} - 60 a\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(2 a^{3} - 2 a^{2} - 60 a = 2 a (a^{2} - a - 30) = 2 a (a + 5) (a - 6)\) 1p 1p b \(a^{8} + 6 a^{4} + 5\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{8} + 6 a^{4} + 5 = (a^{4} + 5) (a^{4} + 1)\) 1p |