Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(p^{2} + 3 p\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} + 3 p = p (p + 3)\) 1p 1p b \(5 x^{2} + 8 x\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(5 x^{2} + 8 x = x (5 x + 8)\) 1p 1p c \(32 a b + 36 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(32 a b + 36 a = 4 a (8 b + 9)\) 1p 1p d \(30 a b + 35 a c\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(30 a b + 35 a c = 5 a (6 b + 7 c)\) 1p opgave 2Ontbind in factoren. 1p a \(4 x y z + 10 x y\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(4 x y z + 10 x y = 2 x y (2 z + 5)\) 1p 1p b \(4 p^{5} + 10 p^{3}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(4 p^{5} + 10 p^{3} = 2 p^{3} (2 p^{2} + 5)\) 1p 1p c \(4 x^{8} - 7 x^{7} + x^{6}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(4 x^{8} - 7 x^{7} + x^{6} = x^{6} (4 x^{2} - 7 x + 1)\) 1p 1p d \(28 a^{2} b^{3} + 36 a^{4} b\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(28 a^{2} b^{3} + 36 a^{4} b = 4 a^{2} b (7 b^{2} + 9 a^{2})\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 4\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 4 = (a - 2) (a + 2)\) 1p 1p b \(16 x^{2} - 9\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(16 x^{2} - 9 = (4 x - 3) (4 x + 3)\) 1p 1p c \(121 - 16 p^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(121 - 16 p^{2} = (11 - 4 p) (11 + 4 p)\) 1p 1p d \(25 a^{10} - 64\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(25 a^{10} - 64 = (5 a^{5} - 8) (5 a^{5} + 8)\) 1p opgave 4Ontbind in factoren. 1p a \(50 x^{2} - 18\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(50 x^{2} - 18 = 2 (25 x^{2} - 9) = 2 (5 x - 3) (5 x + 3)\) 1p 1p b \(20 x^{3} - 45 x\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(20 x^{3} - 45 x = 5 x (4 x^{2} - 9) = 5 x (2 x - 3) (2 x + 3)\) 1p 1p c \(a^{8} - 81\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{8} - 81 = (a^{4} - 9) (a^{4} + 9) = (a^{2} - 3) (a^{2} + 3) (a^{4} + 9)\) 1p 1p d \(a^{10} - 81 a^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^{10} - 81 a^{2} = a^{2} (a^{8} - 81) = a^{2} (a^{4} - 9) (a^{4} + 9) = a^{2} (a^{2} - 3) (a^{2} + 3) (a^{4} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(p^{10} q^{8} - 144 r^{12}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(p^{10} q^{8} - 144 r^{12} = (p^{5} q^{4} - 12 r^{6}) (p^{5} q^{4} + 12 r^{6})\) 1p |
|
| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 14 a + 45\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 14 a + 45 = (a + 5) (a + 9)\) 1p 1p b \(x^{2} + x - 6\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{2} + x - 6 = (x + 3) (x - 2)\) 1p 1p c \(x^{2} - 9 x + 20\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 9 x + 20 = (x - 5) (x - 4)\) 1p 1p d \(p^{2} - 8 p + 16\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(p^{2} - 8 p + 16 = (p - 4) (p - 4)\) 1p opgave 2Ontbind in factoren. 1p a \(5 a^{3} + 10 a^{2} - 315 a\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(5 a^{3} + 10 a^{2} - 315 a = 5 a (a^{2} + 2 a - 63) = 5 a (a + 9) (a - 7)\) 1p 1p b \(a^{12} + 5 a^{6} + 6\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{12} + 5 a^{6} + 6 = (a^{6} + 2) (a^{6} + 3)\) 1p |