Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(x^{2} + 4 x\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} + 4 x = x (x + 4)\) 1p 1p b \(12 a^{2} - 32 a\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 a^{2} - 32 a = 4 a (3 a - 8)\) 1p 1p c \(20 x y + 36 x\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(20 x y + 36 x = 4 x (5 y + 9)\) 1p 1p d \(25 p q + 30 p r\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(25 p q + 30 p r = 5 p (5 q + 6 r)\) 1p opgave 2Ontbind in factoren. 1p a \(32 a b c + 36 a b\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(32 a b c + 36 a b = 4 a b (8 c + 9)\) 1p 1p b \(15 x^{4} + 35 x^{3}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(15 x^{4} + 35 x^{3} = 5 x^{3} (3 x + 7)\) 1p 1p c \(7 p^{3} - 9 p^{5} + p^{6}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(7 p^{3} - 9 p^{5} + p^{6} = p^{3} (7 - 9 p^{2} + p^{3})\) 1p 1p d \(16 x y^{2} + 36 x^{4} y^{5}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(16 x y^{2} + 36 x^{4} y^{5} = 4 x y^{2} (4 + 9 x^{3} y^{3})\) 1p opgave 3Ontbind in factoren. 1p a \(a^{2} - 144\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} - 144 = (a - 12) (a + 12)\) 1p 1p b \(16 a^{2} - 1\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 1ms - dynamic variables b \(16 a^{2} - 1 = (4 a - 1) (4 a + 1)\) 1p 1p c \(49 - 9 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 1ms - dynamic variables c \(49 - 9 x^{2} = (7 - 3 x) (7 + 3 x)\) 1p 1p d \(100 a^{14} - 121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 1ms - dynamic variables d \(100 a^{14} - 121 = (10 a^{7} - 11) (10 a^{7} + 11)\) 1p opgave 4Ontbind in factoren. 1p a \(5 x^{2} - 20\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 1ms - dynamic variables a \(5 x^{2} - 20 = 5 (x^{2} - 4) = 5 (x - 2) (x + 2)\) 1p 1p b \(45 p^{3} - 20 p\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 1ms - dynamic variables b \(45 p^{3} - 20 p = 5 p (9 p^{2} - 4) = 5 p (3 p - 2) (3 p + 2)\) 1p 1p c \(a^{8} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{8} - 16 = (a^{4} - 4) (a^{4} + 4) = (a^{2} - 2) (a^{2} + 2) (a^{4} + 4)\) 1p 1p d \(a^{10} - 81 a^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 1ms - dynamic variables d \(a^{10} - 81 a^{2} = a^{2} (a^{8} - 81) = a^{2} (a^{4} - 9) (a^{4} + 9) = a^{2} (a^{2} - 3) (a^{2} + 3) (a^{4} + 9)\) 1p opgave 5Ontbind in factoren. 1p \(x^{4} y^{4} - 64 z^{2}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(x^{4} y^{4} - 64 z^{2} = (x^{2} y^{2} - 8 z) (x^{2} y^{2} + 8 z)\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(p^{2} + 10 p + 9\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^{2} + 10 p + 9 = (p + 1) (p + 9)\) 1p 1p b \(a^{2} - 4 a - 32\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(a^{2} - 4 a - 32 = (a - 8) (a + 4)\) 1p 1p c \(x^{2} - 15 x + 56\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{2} - 15 x + 56 = (x - 8) (x - 7)\) 1p 1p d \(x^{2} - 2 x + 1\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} - 2 x + 1 = (x - 1) (x - 1)\) 1p opgave 2Ontbind in factoren. 1p a \(3 a^{3} + 9 a^{2} - 84 a\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 1ms - dynamic variables a \(3 a^{3} + 9 a^{2} - 84 a = 3 a (a^{2} + 3 a - 28) = 3 a (a - 4) (a + 7)\) 1p 1p b \(x^{10} + 4 x^{5} + 3\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{10} + 4 x^{5} + 3 = (x^{5} + 3) (x^{5} + 1)\) 1p |