Getal & Ruimte (13e editie) - 2 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(x^{2} + 5 x\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} + 5 x = x (x + 5)\) 1p 1p b \(25 p^{2} + 45 p\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(25 p^{2} + 45 p = 5 p (5 p + 9)\) 1p 1p c \(9 a b + 24 a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(9 a b + 24 a = 3 a (3 b + 8)\) 1p 1p d \(15 a b + 24 a c\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(15 a b + 24 a c = 3 a (5 b + 8 c)\) 1p opgave 2Ontbind in factoren. 1p a \(12 x y z + 16 x y\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(12 x y z + 16 x y = 4 x y (3 z + 4)\) 1p 1p b \(12 x^{5} + 14 x^{2}\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(12 x^{5} + 14 x^{2} = 2 x^{2} (6 x^{3} + 7)\) 1p 1p c \(2 a + 5 a^{4} + a^{6}\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(2 a + 5 a^{4} + a^{6} = a (2 + 5 a^{3} + a^{5})\) 1p 1p d \(14 p^{4} q^{3} + 18 p^{5} q^{4}\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(14 p^{4} q^{3} + 18 p^{5} q^{4} = 2 p^{4} q^{3} (7 + 9 p q)\) 1p opgave 3Ontbind in factoren. 1p a \(x^{2} - 64\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^{2} - 64 = (x - 8) (x + 8)\) 1p 1p b \(81 a^{2} - 4\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 0ms - dynamic variables b \(81 a^{2} - 4 = (9 a - 2) (9 a + 2)\) 1p 1p c \(81 - 16 x^{2}\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 0ms - dynamic variables c \(81 - 16 x^{2} = (9 - 4 x) (9 + 4 x)\) 1p 1p d \(81 p^{8} - 49\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 0ms - dynamic variables d \(81 p^{8} - 49 = (9 p^{4} - 7) (9 p^{4} + 7)\) 1p opgave 4Ontbind in factoren. 1p a \(75 a^{2} - 48\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 0ms - dynamic variables a \(75 a^{2} - 48 = 3 (25 a^{2} - 16) = 3 (5 a - 4) (5 a + 4)\) 1p 1p b \(5 a^{5} - 20 a^{3}\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 0ms - dynamic variables b \(5 a^{5} - 20 a^{3} = 5 a^{3} (a^{2} - 4) = 5 a^{3} (a - 2) (a + 2)\) 1p 1p c \(x^{4} - 16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{4} - 16 = (x^{2} - 4) (x^{2} + 4) = (x - 2) (x + 2) (x^{2} + 4)\) 1p 1p d \(x^{6} - x^{2}\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{6} - x^{2} = x^{2} (x^{4} - 1) = x^{2} (x^{2} - 1) (x^{2} + 1) = x^{2} (x - 1) (x + 1) (x^{2} + 1)\) 1p opgave 5Ontbind in factoren. 1p \(x^{6} y^{10} - 4 z^{8}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(x^{6} y^{10} - 4 z^{8} = (x^{3} y^{5} - 2 z^{4}) (x^{3} y^{5} + 2 z^{4})\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(a^{2} + 11 a + 18\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(a^{2} + 11 a + 18 = (a + 2) (a + 9)\) 1p 1p b \(p^{2} - 6 p - 7\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^{2} - 6 p - 7 = (p - 7) (p + 1)\) 1p 1p c \(a^{2} - 6 a + 8\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(a^{2} - 6 a + 8 = (a - 4) (a - 2)\) 1p 1p d \(x^{2} - 4 x + 4\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(x^{2} - 4 x + 4 = (x - 2) (x - 2)\) 1p opgave 2Ontbind in factoren. 1p a \(3 x^{4} + 36 x^{3} + 105 x^{2}\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 0ms - dynamic variables a \(3 x^{4} + 36 x^{3} + 105 x^{2} = 3 x^{2} (x^{2} + 12 x + 35) = 3 x^{2} (x + 5) (x + 7)\) 1p 1p b \(x^{6} + x^{3} - 6\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^{6} + x^{3} - 6 = (x^{3} - 2) (x^{3} + 3)\) 1p |