\({5 \over 4x}-{8 \over 4x}=-{3 \over 4x}\)

\({6 \over a}-{5 \over 8a}={48 \over 8a}-{5 \over 8a}={43 \over 8a}\)

\({2 \over 3p}-{5 \over 6q}={4q \over 6pq}-{5p \over 6pq}={4q-5p \over 6pq}\)

\(6-{9 \over 8x}={6 \over 1}-{9 \over 8x}={48x \over 8x}-{9 \over 8x}={48x-9 \over 8x}\)

\(4a-{2 \over 7a}={4a \over 1}⋅{7a \over 7a}-{2 \over 7a}={28a^2 \over 7a}-{2 \over 7a}={28a^2-2 \over 7a}\)

\({5a \over b}+{8 \over 2b}={10a \over 2b}+{8 \over 2b}={10a+8 \over 2b}={5a+4 \over b}\)

\({2q \over 7p}+{9p \over 4q}={8q^2 \over 28pq}+{63p^2 \over 28pq}={63p^2+8q^2 \over 28pq}\)

\({4x \over x}={4 \over 1}=4\)

\({a \over 5a}={1 \over 5}\)

\({21x \over -24x}=-\frac{7}{8}\)

\({-16a \over 2a}=-8\)

\({28xy \over 32xz}={7y \over 8z}\)

\({10y \over 15xy}={2 \over 3x}\)

\({-28abc \over 4bc}=-7a\)

\({4pq \over q}+{5pr \over r}=4p+5p=9p\)

\({2 \over x}⋅{5 \over y}={10 \over xy}\)

\({a \over 3}⋅-{8 \over b}=-{8a \over 3b}\)

\(-{1 \over 5}⋅x=-{x \over 5}\)

\({8 \over p}:{2 \over q}={8 \over p}⋅{q \over 2}={8q \over 2p}={4q \over p}\)

\({5 \over 8}:a={5 \over 8}:{a \over 1}={5 \over 8}⋅{1 \over a}={5 \over 8a}\)

\({7x \over 6}+{x+2 \over 5}={35x \over 30}+{6(x+2) \over 30}={35x+6(x+2) \over 30}={41x+12 \over 30}\)