\({3 \over 2a}+{8 \over 2a}={11 \over 2a}\)

\({3 \over x}-{7 \over 5x}={15 \over 5x}-{7 \over 5x}={8 \over 5x}\)

\({7 \over 2a}+{6 \over 8b}={28b \over 8ab}+{6a \over 8ab}={28b+6a \over 8ab}={14b+3a \over 4ab}\)

\(6-{4 \over 5p}={6 \over 1}-{4 \over 5p}={30p \over 5p}-{4 \over 5p}={30p-4 \over 5p}\)

\(6x-{5 \over 7x}={6x \over 1}⋅{7x \over 7x}-{5 \over 7x}={42x^2 \over 7x}-{5 \over 7x}={42x^2-5 \over 7x}\)

\({6x \over y}+{2 \over 4y}={24x \over 4y}+{2 \over 4y}={24x+2 \over 4y}={12x+1 \over 2y}\)

\({9q \over 3p}-{6p \over 8q}={72q^2 \over 24pq}-{18p^2 \over 24pq}={-18p^2+72q^2 \over 24pq}={-3p^2+12q^2 \over 4pq}\)

\({7x \over x}={7 \over 1}=7\)

\({a \over 9a}={1 \over 9}\)

\({-18a \over -21a}=\frac{6}{7}\)

\({40x \over 5x}=8\)

\({12ab \over -15ac}=-{4b \over 5c}\)

\({6y \over 16xy}={3 \over 8x}\)

\({-30pqr \over 5qr}=-6p\)

\({7ab \over b}+{6ac \over c}=7a+6a=13a\)

\({4 \over x}⋅-{2 \over y}=-{8 \over xy}\)

\({x \over 3}⋅{7 \over y}={7x \over 3y}\)

\({6 \over 7}⋅a={6a \over 7}\)

\({2 \over a}:{5 \over b}={2 \over a}⋅{b \over 5}={2b \over 5a}\)

\(-{6 \over 7}:p=-{6 \over 7}:{p \over 1}=-{6 \over 7}⋅{1 \over p}=-{6 \over 7p}\)

\({7x \over 5}+{x+2 \over 6}={42x \over 30}+{5(x+2) \over 30}={42x+5(x+2) \over 30}={47x+10 \over 30}\)