Getal & Ruimte (13e editie) - 3 havo
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C=47\text{,}\) \(\angle B=37\degree\) en \(\angle C=90\degree\text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle B)={A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\tan(37\degree)={A\kern{-.8pt}C \over 47}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C=47⋅\tan(37\degree)\text{.}\) 1p ○ Dus \(A\kern{-.8pt}C≈35{,}4\text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M=58\text{,}\) \(\angle L=33\degree\) en \(\angle M=90\degree\text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle L)={K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\tan(33\degree)={58 \over L\kern{-.8pt}M}\text{.}\) 1p ○ Hieruit volgt \(L\kern{-.8pt}M={58 \over \tan(33\degree)}\text{.}\) 1p ○ Dus \(L\kern{-.8pt}M≈89{,}3\text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C=29\text{,}\) \(A\kern{-.8pt}B=46\) en \(\angle A=90\degree\text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle C)={A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\tan(\angle C)={46 \over 29}\text{.}\) 1p ○ Hieruit volgt \(\angle C=\tan^{-1}({46 \over 29})\text{.}\) 1p ○ Dus \(\angle C≈57{,}8\degree\text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B=43\text{,}\) \(\angle B=34\degree\) en \(\angle C=90\degree\text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle B)={A\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\sin(34\degree)={A\kern{-.8pt}C \over 43}\text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C=43⋅\sin(34\degree)\text{.}\) 1p ○ Dus \(A\kern{-.8pt}C≈24{,}0\text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M=45\text{,}\) \(\angle K=54\degree\) en \(\angle L=90\degree\text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle K)={L\kern{-.8pt}M \over K\kern{-.8pt}M}\) ofwel \(\sin(54\degree)={45 \over K\kern{-.8pt}M}\text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M={45 \over \sin(54\degree)}\text{.}\) 1p ○ Dus \(K\kern{-.8pt}M≈55{,}6\text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=24\text{,}\) \(P\kern{-.8pt}Q=64\) en \(\angle R=90\degree\text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle Q)={P\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\sin(\angle Q)={24 \over 64}\text{.}\) 1p ○ Hieruit volgt \(\angle Q=\sin^{-1}({24 \over 64})\text{.}\) 1p ○ Dus \(\angle Q≈22{,}0\degree\text{.}\) 1p 3p d Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=75\text{,}\) \(\angle P=48\degree\) en \(\angle Q=90\degree\text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle P)={P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\cos(48\degree)={P\kern{-.8pt}Q \over 75}\text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}Q=75⋅\cos(48\degree)\text{.}\) 1p ○ Dus \(P\kern{-.8pt}Q≈50{,}2\text{.}\) 1p opgave 23p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R=51\text{,}\) \(\angle R=49\degree\) en \(\angle P=90\degree\text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle R)={P\kern{-.8pt}R \over Q\kern{-.8pt}R}\) ofwel \(\cos(49\degree)={51 \over Q\kern{-.8pt}R}\text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R={51 \over \cos(49\degree)}\text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R≈77{,}7\text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C=24\text{,}\) \(A\kern{-.8pt}B=48\) en \(\angle C=90\degree\text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 1ms b Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle B)={B\kern{-.8pt}C \over A\kern{-.8pt}B}\) ofwel \(\cos(\angle B)={24 \over 48}\text{.}\) 1p ○ Hieruit volgt \(\angle B=\cos^{-1}({24 \over 48})\text{.}\) 1p ○ Dus \(\angle B=60{,}0\degree\text{.}\) 1p |