\(\sqrt{112}=\sqrt{16}⋅\sqrt{7}=4\sqrt{7}\text{.}\)

\(-2\sqrt{175}=-2⋅\sqrt{25}⋅\sqrt{7}=-2⋅5⋅\sqrt{7}=-10\sqrt{7}\text{.}\)

\(\sqrt{\frac{9}{64}}={\sqrt{9} \over \sqrt{64}}=\frac{3}{8}\text{.}\)

\(\sqrt{1\frac{5}{9}}=\sqrt{\frac{14}{9}}={\sqrt{14} \over \sqrt{9}}={\sqrt{14} \over 3}=\frac{1}{3}\sqrt{14}\text{.}\)