Getal & Ruimte (13e editie) - 3 vwo
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({5 \over 3 a} + {2 \over 3 a}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({5 \over 3 a} + {2 \over 3 a} = {7 \over 3 a}\) 1p 1p b \({2 \over x} + {7 \over 4 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({2 \over x} + {7 \over 4 x} = {8 \over 4 x} + {7 \over 4 x} = {15 \over 4 x}\) 1p 1p c \({6 \over 9 p} - {4 \over 8 q}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({6 \over 9 p} - {4 \over 8 q} = {48 q \over 72 p q} - {36 p \over 72 p q} = {48 q - 36 p \over 72 p q} = {4 q - 3 p \over 6 p q}\) 1p 1p d \(5 + {6 \over 7 a}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(5 + {6 \over 7 a} = {5 \over 1} + {6 \over 7 a} = {35 a \over 7 a} + {6 \over 7 a} = {35 a + 6 \over 7 a}\) 1p opgave 2Herleid tot één breuk. 1p \({2 x \over y} + {8 \over 5 y}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({2 x \over y} + {8 \over 5 y} = {10 x \over 5 y} + {8 \over 5 y} = {10 x + 8 \over 5 y}\) 1p opgave 3Herleid. 1p a \({2 p \over p}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({2 p \over p} = {2 \over 1} = 2\) 1p 1p b \({x \over 3 x}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({x \over 3 x} = {1 \over 3}\) 1p 1p c \({8 a \over 20 a}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({8 a \over 20 a} = \frac{2}{5}\) 1p 1p d \({4 x \over -2 x}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({4 x \over -2 x} = -2\) 1p opgave 4Herleid. 1p a \({-10 a b \over -15 a c}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({-10 a b \over -15 a c} = {2 b \over 3 c}\) 1p 1p b \({-4 b \over 10 a b}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({-4 b \over 10 a b} = -{2 \over 5 a}\) 1p 1p c \({16 p q r \over -4 q r}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({16 p q r \over -4 q r} = -4 p\) 1p 1p d \({4 a b \over b} + {2 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({4 a b \over b} + {2 a c \over c} = 4 a + 2 a = 6 a\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(7 p - {2 \over 9 p}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(7 p - {2 \over 9 p} = {7 p \over 1} ⋅ {9 p \over 9 p} - {2 \over 9 p} = {63 p^{2} \over 9 p} - {2 \over 9 p} = {63 p^{2} - 2 \over 9 p}\) 1p 1p b \({3 y \over 6 x} - {7 x \over 8 y}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({3 y \over 6 x} - {7 x \over 8 y} = {12 y^{2} \over 24 x y} - {21 x^{2} \over 24 x y} = {-21 x^{2} + 12 y^{2} \over 24 x y} = {-7 x^{2} + 4 y^{2} \over 8 x y}\) 1p 1p c \({9 \over x} ⋅ -{8 \over y}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({9 \over x} ⋅ -{8 \over y} = -{72 \over x y}\) 1p 1p d \({a \over 6} ⋅ -{9 \over b}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({a \over 6} ⋅ -{9 \over b} = -{9 a \over 6 b} = -{3 a \over 2 b}\) 1p opgave 2Herleid tot één breuk. 1p a \({8 \over 5} ⋅ a\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \({8 \over 5} ⋅ a = {8 a \over 5}\) 1p 1p b \({2 y \over x} ⋅ {x + 7 \over 9}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({2 y \over x} ⋅ {x + 7 \over 9} = {2 y (x + 7) \over 9 x} = {2 x y + 14 y \over 9 x}\) 1p 1p c \({4 \over a} : {5 \over b}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({4 \over a} : {5 \over b} = {4 \over a} ⋅ {b \over 5} = {4 b \over 5 a}\) 1p 1p d \({4 \over 5} : x\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \({4 \over 5} : x = {4 \over 5} : {x \over 1} = {4 \over 5} ⋅ {1 \over x} = {4 \over 5 x}\) 1p opgave 3Herleid tot één breuk. 1p a \({4 \over 3} : {p + 2 q \over q}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \({4 \over 3} : {p + 2 q \over q} = {4 \over 3} ⋅ {q \over p + 2 q} = {4 q \over 3 (p + 2 q)} = {4 q \over 3 p + 6 q}\) 1p 1p b \({8 a \over 3} + {a + 1 \over 5}\) Optellen (8) 0098 - Breuken herleiden - basis - 0ms - dynamic variables b \({8 a \over 3} + {a + 1 \over 5} = {40 a \over 15} + {3 (a + 1) \over 15} = {40 a + 3 (a + 1) \over 15} = {43 a + 3 \over 15}\) 1p |
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| 3 vwo | 5.3 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({-5 a - 9 \over -7 a + 1} + 2\) Optellen (9) 00eh - Breuken herleiden - basis - 0ms - dynamic variables ○ \({-5 a - 9 \over -7 a + 1} + 2 = {-5 a - 9 \over -7 a + 1} - {-2 (-7 a + 1) \over -7 a + 1} = {-5 a - 9 + 2 (-7 a + 1) \over -7 a + 1} = {-5 a - 9 - 14 a + 2 \over -7 a + 1} = {-19 a - 7 \over -7 a + 1}\) 1p |