Getal & Ruimte (13e editie) - 3 vwo
'Ontbinden in factoren'.
| 2 vwo | 7.1 Buiten haakjes brengen |
opgave 1Ontbind in factoren. 1p a \(x^2+5x\) BuitenHaakjes (1) 00hd - Ontbinden in factoren - basis - 0ms - dynamic variables a \(x^2+5x=x(x+5)\) 1p 1p b \(6a^2-27a\) BuitenHaakjes (2) 00he - Ontbinden in factoren - basis - 0ms - dynamic variables b \(6a^2-27a=3a(2a-9)\) 1p 1p c \(12ab+27a\) BuitenHaakjes (3) 00hf - Ontbinden in factoren - basis - 0ms - dynamic variables c \(12ab+27a=3a(4b+9)\) 1p 1p d \(6xy+8xz\) BuitenHaakjes (4) 00hg - Ontbinden in factoren - basis - 0ms - dynamic variables d \(6xy+8xz=2x(3y+4z)\) 1p opgave 2Ontbind in factoren. 1p a \(8pqr+36pq\) BuitenHaakjes (5) 00hh - Ontbinden in factoren - basis - 0ms - dynamic variables a \(8pqr+36pq=4pq(2r+9)\) 1p 1p b \(10x^3+45x^4\) BuitenHaakjes (6) 00hi - Ontbinden in factoren - basis - 0ms - dynamic variables b \(10x^3+45x^4=5x^3(2+9x)\) 1p 1p c \(4x-5x^3+x^6\) BuitenHaakjes (7) 00hj - Ontbinden in factoren - basis - 0ms - dynamic variables c \(4x-5x^3+x^6=x(4-5x^2+x^5)\) 1p 1p d \(20a^4b^2+24a^5b^3\) BuitenHaakjes (8) 00hk - Ontbinden in factoren - basis - 0ms - dynamic variables d \(20a^4b^2+24a^5b^3=4a^4b^2(5+6ab)\) 1p opgave 3Ontbind in factoren. 1p a \(p^2-49\) Verschil2Kwadraten (1) 00hl - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^2-49=(p-7)(p+7)\) 1p 1p b \(49a^2-121\) Verschil2Kwadraten (2) 00hm - Ontbinden in factoren - basis - 1ms - dynamic variables b \(49a^2-121=(7a-11)(7a+11)\) 1p 1p c \(9-16p^2\) Verschil2Kwadraten (3) 00hs - Ontbinden in factoren - basis - 1ms - dynamic variables c \(9-16p^2=(3-4p)(3+4p)\) 1p 1p d \(9a^4-121\) Verschil2Kwadraten (4) 00ht - Ontbinden in factoren - basis - 1ms - dynamic variables d \(9a^4-121=(3a^2-11)(3a^2+11)\) 1p opgave 4Ontbind in factoren. 1p a \(50a^2-2\) Verschil2Kwadraten (5) 00hu - Ontbinden in factoren - basis - 1ms - dynamic variables a \(50a^2-2=2(25a^2-1)=2(5a-1)(5a+1)\) 1p 1p b \(50x^3-2x\) Verschil2Kwadraten (6) 00hv - Ontbinden in factoren - basis - 1ms - dynamic variables b \(50x^3-2x=2x(25x^2-1)=2x(5x-1)(5x+1)\) 1p 1p c \(x^{12}-16\) Verschil2Kwadraten (7) 00hw - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^{12}-16=(x^6-4)(x^6+4)=(x^3-2)(x^3+2)(x^6+4)\) 1p 1p d \(3a^6-243a^2\) Verschil2Kwadraten (8) 00hx - Ontbinden in factoren - basis - 1ms - dynamic variables d \(3a^6-243a^2=3a^2(a^4-81)=3a^2(a^2-9)(a^2+9)=3a^2(a-3)(a+3)(a^2+9)\) 1p opgave 5Ontbind in factoren. 1p \(a^{10}b^2-64c^{10}\) Verschil2Kwadraten (9) 00hz - Ontbinden in factoren - basis - 0ms - dynamic variables ○ \(a^{10}b^2-64c^{10}=(a^5b-8c^5)(a^5b+8c^5)\) 1p |
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| 2 vwo | 7.2 De product-som methode |
opgave 1Ontbind in factoren. 1p a \(p^2+11p+24\) SomProductmethode (1) 00hn - Ontbinden in factoren - basis - 0ms - dynamic variables a \(p^2+11p+24=(p+8)(p+3)\) 1p 1p b \(x^2+3x-10\) SomProductmethode (2) 00ho - Ontbinden in factoren - basis - 0ms - dynamic variables b \(x^2+3x-10=(x+5)(x-2)\) 1p 1p c \(x^2-12x+32\) SomProductmethode (3) 00hp - Ontbinden in factoren - basis - 0ms - dynamic variables c \(x^2-12x+32=(x-8)(x-4)\) 1p 1p d \(a^2+14a+49\) SomProductmethode (4) 00hq - Ontbinden in factoren - basis - 0ms - dynamic variables d \(a^2+14a+49=(a+7)(a+7)\) 1p opgave 2Ontbind in factoren. 1p a \(a^4+a^3-2a^2\) SomProductmethode (5) 00hr - Ontbinden in factoren - basis - 1ms - dynamic variables a \(a^4+a^3-2a^2=a^2(a^2+a-2)=a^2(a+2)(a-1)\) 1p 1p b \(p^8-8p^4+7\) SomProductmethode (6) 00hy - Ontbinden in factoren - basis - 0ms - dynamic variables b \(p^8-8p^4+7=(p^4-1)(p^4-7)\) 1p |
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| 3 vwo | 5.2 Kwadraatafsplitsen |
opgave 1Splits het kwadraat af. 1p a \(x^2-8x\) KwadraatAfsplitsen (1) 00r8 - Ontbinden in factoren - basis - 0ms a \(x^2-8x=(x-4)^2-16\) 1p 2p b \(x^2-19x+20\) KwadraatAfsplitsen (2) 00r9 - Ontbinden in factoren - basis - 0ms b \(x^2-19x+20=(x-9\frac{1}{2})^2-90\frac{1}{4}+20\) 1p ○ \(\text{}=(x-9\frac{1}{2})^2-70\frac{1}{4}\) 1p 3p c \(-5x^2-10x-11\) KwadraatAfsplitsen (3) 00ra - Ontbinden in factoren - basis - 0ms c \(-5x^2-10x-11=-5(x^2+2x)-11\) 1p ○ \(\text{}=-5((x+1)^2-1)-11\) 1p ○ \(\text{}=-5(x+1)^2+5-11\) 1p |