Getal & Ruimte (13e editie) - 3 vwo
'Sinus, cosinus en tangens'.
| 3 vwo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 60 \text{,}\) \(\angle B = 43\degree\) en \(\angle C = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle B) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\tan(43\degree) = {A\kern{-.8pt}C \over 60} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C = 60 ⋅ \tan(43\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}C ≈ 56{,}0 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 24 \text{,}\) \(\angle P = 37\degree\) en \(\angle Q = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\tan(37\degree) = {24 \over P\kern{-.8pt}Q} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}Q = {24 \over \tan(37\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}Q ≈ 31{,}8 \text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 34 \text{,}\) \(A\kern{-.8pt}B = 34\) en \(\angle A = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle C) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\tan(\angle C) = {34 \over 34} \text{.}\) 1p ○ Hieruit volgt \(\angle C = \tan^{-1}({34 \over 34}) \text{.}\) 1p ○ Dus \(\angle C = 45{,}0\degree \text{.}\) 1p |
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| 3 vwo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 58 \text{,}\) \(\angle M = 51\degree\) en \(\angle K = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle M) = {K\kern{-.8pt}L \over L\kern{-.8pt}M}\) ofwel \(\sin(51\degree) = {K\kern{-.8pt}L \over 58} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L = 58 ⋅ \sin(51\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}L ≈ 45{,}1 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 52 \text{,}\) \(\angle C = 32\degree\) en \(\angle A = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle C) = {A\kern{-.8pt}B \over B\kern{-.8pt}C}\) ofwel \(\sin(32\degree) = {52 \over B\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C = {52 \over \sin(32\degree)} \text{.}\) 1p ○ Dus \(B\kern{-.8pt}C ≈ 98{,}1 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 37 \text{,}\) \(P\kern{-.8pt}R = 44\) en \(\angle Q = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}R}\) ofwel \(\sin(\angle P) = {37 \over 44} \text{.}\) 1p ○ Hieruit volgt \(\angle P = \sin^{-1}({37 \over 44}) \text{.}\) 1p ○ Dus \(\angle P ≈ 57{,}2\degree \text{.}\) 1p 3p d Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 69 \text{,}\) \(\angle A = 48\degree\) en \(\angle B = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(48\degree) = {A\kern{-.8pt}B \over 69} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = 69 ⋅ \cos(48\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 46{,}2 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 47 \text{,}\) \(\angle K = 48\degree\) en \(\angle L = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(48\degree) = {47 \over K\kern{-.8pt}M} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = {47 \over \cos(48\degree)} \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 70{,}2 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 41 \text{,}\) \(Q\kern{-.8pt}R = 70\) en \(\angle P = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle R) = {P\kern{-.8pt}R \over Q\kern{-.8pt}R}\) ofwel \(\cos(\angle R) = {41 \over 70} \text{.}\) 1p ○ Hieruit volgt \(\angle R = \cos^{-1}({41 \over 70}) \text{.}\) 1p ○ Dus \(\angle R ≈ 54{,}1\degree \text{.}\) 1p |