Getal & Ruimte (13e editie) - 3 vwo

'Wortels vereenvoudigen'.

2 vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (5)

opgave 1

Herleid.

2p

a

\(\sqrt{80}+\sqrt{45}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 0ms

a

\(\sqrt{80}+\sqrt{45}=\sqrt{16}⋅\sqrt{5}+\sqrt{9}⋅\sqrt{5}=4\sqrt{5}+3\sqrt{5}\text{.}\)

1p

\(4\sqrt{5}+3\sqrt{5}=7\sqrt{5}\text{.}\)

1p

1p

b

\(\sqrt{28}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 0ms

b

\(\sqrt{28}=\sqrt{4}⋅\sqrt{7}=2\sqrt{7}\text{.}\)

1p

1p

c

\(-6\sqrt{200}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 0ms

c

\(-6\sqrt{200}=-6⋅\sqrt{100}⋅\sqrt{2}=-6⋅10⋅\sqrt{2}=-60\sqrt{2}\text{.}\)

1p

2p

d

\(4\sqrt{27}+6\sqrt{75}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 0ms

d

\(4\sqrt{27}+6\sqrt{75}=4⋅\sqrt{9}⋅\sqrt{3}+6⋅\sqrt{25}⋅\sqrt{3}\text{.}\)

1p

\(4⋅3⋅\sqrt{3}+6⋅5⋅\sqrt{3}=12\sqrt{3}+30\sqrt{3}=42\sqrt{3}\text{.}\)

1p

opgave 2

Herleid.

1p

\(\sqrt{1\frac{7}{9}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 56ms

\(\sqrt{1\frac{7}{9}}=\sqrt{\frac{16}{9}}={\sqrt{16} \over \sqrt{9}}=\frac{4}{3}=1\frac{1}{3}\text{.}\)

1p

3 vwo 5.5 Wortels herleiden

Wortels vereenvoudigen (6)

opgave 1

Herleid.

1p

a

\({7 \over 5\sqrt{5}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

a

\({7 \over 5\sqrt{5}}={7 \over 5\sqrt{5}}⋅{\sqrt{5} \over \sqrt{5}}={7\sqrt{5} \over 5⋅5}=\frac{7}{25}\sqrt{5}\text{.}\)

1p

1p

b

\(\sqrt{\frac{41}{100}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

b

\(\sqrt{\frac{41}{100}}={\sqrt{41} \over \sqrt{100}}={\sqrt{41} \over 10}=\frac{1}{10}\sqrt{41}\text{.}\)

1p

1p

c

\(\sqrt{1\frac{25}{39}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

c

\(\sqrt{1\frac{25}{39}}=\sqrt{\frac{64}{39}}={\sqrt{64} \over \sqrt{39}}={8 \over \sqrt{39}}⋅{\sqrt{39} \over \sqrt{39}}={8\sqrt{39} \over 39}=\frac{8}{39}\sqrt{39}\text{.}\)

1p

1p

d

\(\sqrt{\frac{7}{8}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{\frac{7}{8}}={\sqrt{7} \over \sqrt{8}}⋅{\sqrt{8} \over \sqrt{8}}={\sqrt{56} \over 8}=\frac{1}{8}\sqrt{56}=\frac{1}{8}⋅2⋅\sqrt{14}=\frac{1}{4}\sqrt{14}\text{.}\)

1p

opgave 2

Herleid.

1p

a

\({6\sqrt{196} \over 2\sqrt{7}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 9ms

a

\({6\sqrt{196} \over 2\sqrt{7}}={6 \over 2}⋅{\sqrt{196} \over \sqrt{7}}=3\sqrt{28}=3⋅\sqrt{4}⋅\sqrt{7}=3⋅2⋅\sqrt{7}=6\sqrt{7}\)

1p

1p

b

\(2\sqrt{15}⋅3\sqrt{3}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (3ms)

b

\(2\sqrt{15}⋅3\sqrt{3}=6\sqrt{45}=6⋅\sqrt{9}⋅\sqrt{5}=6⋅3⋅\sqrt{5}=18\sqrt{5}\)

1p

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