\(x^{3} - 22 x^{2} + 33 x = -2 x^{2} - 3 x\)
\(x^{3} - 20 x^{2} + 36 x = 0\)
\(x (x^{2} - 20 x + 36) = 0\)

\(x (x - 2) (x - 18) = 0\)
\(x = 0 ∨ x = 2 ∨ x = 18\)

\(f(x) < g(x)\) geeft \(x < 0 ∨ 2 < x < 18 \text{.}\)

\(f(-6) = 3 \text{.}\)

\(-2 x - 3 ≥ 0\)
\(-2 x ≥ 3\)
\(x ≤ -1\frac{1}{2}\)
Dus het randpunt is \((-1\frac{1}{2} , -3) \text{.}\)

\(x ≥ -6\) geeft \(-3 ≤ f(x) ≤ 3 \text{.}\)

\(4 - 5 \sqrt{-4 x - 4} = -6\)
\(-5 \sqrt{-4 x - 4} = -10\)
\(\sqrt{-4 x - 4} = 2\)
\(-4 x - 4 = 4\)
\(-4 x = 8\)
\(x = -2 \text{.}\)

\(-4 x - 4 ≥ 0\)
\(-4 x ≥ 4\)
\(x ≤ -1\)
Dus het randpunt is \((-1 , 4) \text{.}\)

\(f(x) > -6\) geeft \(-2 < x ≤ -1 \text{.}\)

\(f(x) = 26\)
\(5 ⋅ {}^{2}\!\log(3 x + 4) + 6 = 26\)
\(5 ⋅ {}^{2}\!\log(3 x + 4) = 20\)
\({}^{2}\!\log(3 x + 4) = 4\)
\(3 x + 4 = 2^{4} = 16\)
\(3 x = 12\)
\(x = 4\)

Bereking van het domein geeft
\(3 x + 4 > 0\)
\(3 x > -4\)
\(x > -1\frac{1}{3}\)
Dus de verticale asymptoot is de lijn \(x = -1\frac{1}{3} \text{.}\)

\(f(x) ≤ 26\) geeft \(-1\frac{1}{3} < x ≤ 4 \text{.}\)