Getal & Ruimte (13e editie) - havo wiskunde B
'Rekenen met logaritmen'.
| havo wiskunde B | 5.5 Logaritmen |
opgave 1Bereken. 1p a \({}^{2}\!\log(16)\) Logaritme (1) 00fi - Rekenen met logaritmen - basis - 0ms a \({}^{2}\!\log(16)={}^{2}\!\log(2^4)=4\) 1p 1p b \({}^{9}\!\log(1)\) Logaritme (2) 00fj - Rekenen met logaritmen - basis - 0ms b \({}^{9}\!\log(1)={}^{9}\!\log(9^0)=0\) 1p 1p c \({}^{3}\!\log(\frac{1}{27})\) Logaritme (4) 00fl - Rekenen met logaritmen - basis - 0ms c \({}^{3}\!\log(\frac{1}{27})={}^{3}\!\log(3^{-3})=-3\) 1p 1p d \({}^{\frac{1}{10}}\!\log(\frac{1}{100})\) Logaritme (5) 00fm - Rekenen met logaritmen - basis - 1ms d \({}^{\frac{1}{10}}\!\log(\frac{1}{100})={}^{\frac{1}{10}}\!\log(\frac{1}{10}^2)=2\) 1p opgave 2Bereken. 1p a \({}^{\frac{1}{2}}\!\log(8)\) Logaritme (6) 00fn - Rekenen met logaritmen - basis - 0ms a \({}^{\frac{1}{2}}\!\log({}^{\frac{1}{2}}\!\log(8))={}^{\frac{1}{2}}\!\log(\frac{1}{2}^{-3})=-3\) 1p 1p b \({}^{2}\!\log(64\sqrt{2})\) Logaritme (7) 00fo - Rekenen met logaritmen - basis - 0ms b \({}^{2}\!\log(64\sqrt{2})={}^{2}\!\log(2^6⋅2^{\frac{1}{2}})={}^{2}\!\log(2^{6\frac{1}{2}})=6\frac{1}{2}\) 1p 1p c \({}^{5}\!\log(5^{5{,}6})\) Logaritme (8) 00fp - Rekenen met logaritmen - basis - 0ms c \({}^{5}\!\log(5^{5{,}6})=5{,}6\) 1p |