Getal & Ruimte (13e editie) - havo wiskunde B
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M = 26 \text{,}\) \(\angle M = 37\degree\) en \(\angle K = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle M) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\tan(37\degree) = {K\kern{-.8pt}L \over 26} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L = 26 ⋅ \tan(37\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}L ≈ 19{,}6 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 57 \text{,}\) \(\angle R = 34\degree\) en \(\angle P = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(34\degree) = {57 \over P\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R = {57 \over \tan(34\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}R ≈ 84{,}5 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 59 \text{,}\) \(P\kern{-.8pt}Q = 49\) en \(\angle P = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(\angle R) = {49 \over 59} \text{.}\) 1p ○ Hieruit volgt \(\angle R = \tan^{-1}({49 \over 59}) \text{.}\) 1p ○ Dus \(\angle R ≈ 39{,}7\degree \text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 80 \text{,}\) \(\angle L = 46\degree\) en \(\angle M = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle L) = {K\kern{-.8pt}M \over K\kern{-.8pt}L}\) ofwel \(\sin(46\degree) = {K\kern{-.8pt}M \over 80} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = 80 ⋅ \sin(46\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 57{,}5 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 60 \text{,}\) \(\angle C = 52\degree\) en \(\angle A = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle C) = {A\kern{-.8pt}B \over B\kern{-.8pt}C}\) ofwel \(\sin(52\degree) = {60 \over B\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C = {60 \over \sin(52\degree)} \text{.}\) 1p ○ Dus \(B\kern{-.8pt}C ≈ 76{,}1 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(Q\kern{-.8pt}R = 29 \text{,}\) \(P\kern{-.8pt}R = 40\) en \(\angle Q = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}R}\) ofwel \(\sin(\angle P) = {29 \over 40} \text{.}\) 1p ○ Hieruit volgt \(\angle P = \sin^{-1}({29 \over 40}) \text{.}\) 1p ○ Dus \(\angle P ≈ 46{,}5\degree \text{.}\) 1p 3p d Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 42 \text{,}\) \(\angle C = 52\degree\) en \(\angle A = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle C) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\cos(52\degree) = {A\kern{-.8pt}C \over 42} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C = 42 ⋅ \cos(52\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}C ≈ 25{,}9 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 34 \text{,}\) \(\angle A = 57\degree\) en \(\angle B = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle A) = {A\kern{-.8pt}B \over A\kern{-.8pt}C}\) ofwel \(\cos(57\degree) = {34 \over A\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}C = {34 \over \cos(57\degree)} \text{.}\) 1p ○ Dus \(A\kern{-.8pt}C ≈ 62{,}4 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 42 \text{,}\) \(P\kern{-.8pt}R = 55\) en \(\angle Q = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle P) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\cos(\angle P) = {42 \over 55} \text{.}\) 1p ○ Hieruit volgt \(\angle P = \cos^{-1}({42 \over 55}) \text{.}\) 1p ○ Dus \(\angle P ≈ 40{,}2\degree \text{.}\) 1p |