Getal & Ruimte (13e editie) - havo wiskunde B
'Sinus, cosinus en tangens'.
| 3 havo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 25 \text{,}\) \(\angle L = 41\degree\) en \(\angle M = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle L) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\tan(41\degree) = {K\kern{-.8pt}M \over 25} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = 25 ⋅ \tan(41\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 21{,}7 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 47 \text{,}\) \(\angle B = 37\degree\) en \(\angle C = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle B) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\tan(37\degree) = {47 \over B\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C = {47 \over \tan(37\degree)} \text{.}\) 1p ○ Dus \(B\kern{-.8pt}C ≈ 62{,}4 \text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 38 \text{,}\) \(A\kern{-.8pt}C = 24\) en \(\angle C = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\tan(\angle B) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\tan(\angle B) = {24 \over 38} \text{.}\) 1p ○ Hieruit volgt \(\angle B = \tan^{-1}({24 \over 38}) \text{.}\) 1p ○ Dus \(\angle B ≈ 32{,}3\degree \text{.}\) 1p |
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| 3 havo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 43 \text{,}\) \(\angle M = 38\degree\) en \(\angle K = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\sin(\angle M) = {K\kern{-.8pt}L \over L\kern{-.8pt}M}\) ofwel \(\sin(38\degree) = {K\kern{-.8pt}L \over 43} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}L = 43 ⋅ \sin(38\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}L ≈ 26{,}5 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}B = 28 \text{,}\) \(\angle C = 38\degree\) en \(\angle A = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle C) = {A\kern{-.8pt}B \over B\kern{-.8pt}C}\) ofwel \(\sin(38\degree) = {28 \over B\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C = {28 \over \sin(38\degree)} \text{.}\) 1p ○ Dus \(B\kern{-.8pt}C ≈ 45{,}5 \text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 43 \text{,}\) \(A\kern{-.8pt}C = 48\) en \(\angle B = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}C}\) ofwel \(\sin(\angle A) = {43 \over 48} \text{.}\) 1p ○ Hieruit volgt \(\angle A = \sin^{-1}({43 \over 48}) \text{.}\) 1p ○ Dus \(\angle A ≈ 63{,}6\degree \text{.}\) 1p 3p d Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 74 \text{,}\) \(\angle Q = 49\degree\) en \(\angle R = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle Q) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\cos(49\degree) = {Q\kern{-.8pt}R \over 74} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = 74 ⋅ \cos(49\degree) \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 48{,}5 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 43 \text{,}\) \(\angle P = 42\degree\) en \(\angle Q = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\cos(\angle P) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\cos(42\degree) = {43 \over P\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}R = {43 \over \cos(42\degree)} \text{.}\) 1p ○ Dus \(P\kern{-.8pt}R ≈ 57{,}9 \text{.}\) 1p 3p b Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 54 \text{,}\) \(B\kern{-.8pt}C = 69\) en \(\angle A = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle C) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\cos(\angle C) = {54 \over 69} \text{.}\) 1p ○ Hieruit volgt \(\angle C = \cos^{-1}({54 \over 69}) \text{.}\) 1p ○ Dus \(\angle C ≈ 38{,}5\degree \text{.}\) 1p |