Getal & Ruimte (13e editie) - havo wiskunde B

'Wortels vereenvoudigen'.

2 havo/vwo 5.3 Wortels herleiden

Wortels vereenvoudigen (4)

opgave 1

Herleid.

1p

a

\(\sqrt{63}\)

FactorVoorWortelteken (1)
0086 - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{63}=\sqrt{9}⋅\sqrt{7}=3\sqrt{7}\text{.}\)

1p

1p

b

\(-2\sqrt{500}\)

FactorVoorWortelteken (2)
0087 - Wortels vereenvoudigen - basis - 1ms

b

\(-2\sqrt{500}=-2⋅\sqrt{100}⋅\sqrt{5}=-2⋅10⋅\sqrt{5}=-20\sqrt{5}\text{.}\)

1p

1p

c

\(\sqrt{\frac{9}{100}}\)

BreukInWortel (1)
008b - Wortels vereenvoudigen - basis - 103ms

c

\(\sqrt{\frac{9}{100}}={\sqrt{9} \over \sqrt{100}}=\frac{3}{10}\text{.}\)

1p

1p

d

\({54\sqrt{168} \over 9\sqrt{6}}\)

Delen (4)
00dc - Wortels vereenvoudigen - basis - 16ms

d

\({54\sqrt{168} \over 9\sqrt{6}}={54 \over 9}⋅{\sqrt{168} \over \sqrt{6}}=6\sqrt{28}=6⋅\sqrt{4}⋅\sqrt{7}=6⋅2⋅\sqrt{7}=12\sqrt{7}\)

1p

3 havo 5.4 Wortels herleiden

Wortels vereenvoudigen (1)

opgave 1

Herleid.

1p

\(\sqrt{\frac{47}{49}}\)

BreukInWortel (2)
008c - Wortels vereenvoudigen - basis - 1ms

\(\sqrt{\frac{47}{49}}={\sqrt{47} \over \sqrt{49}}={\sqrt{47} \over 7}=\frac{1}{7}\sqrt{47}\text{.}\)

1p

havo wiskunde B 7.2 Afstanden bij punten en lijnen

Wortels vereenvoudigen (6)

opgave 1

Herleid.

2p

a

\(\sqrt{50}+\sqrt{200}\)

Optellen (5)
0085 - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{50}+\sqrt{200}=\sqrt{25}⋅\sqrt{2}+\sqrt{100}⋅\sqrt{2}=5\sqrt{2}+10\sqrt{2}\text{.}\)

1p

\(5\sqrt{2}+10\sqrt{2}=15\sqrt{2}\text{.}\)

1p

2p

b

\(4\sqrt{27}+3\sqrt{300}\)

Optellen (6)
0088 - Wortels vereenvoudigen - basis - 1ms

b

\(4\sqrt{27}+3\sqrt{300}=4⋅\sqrt{9}⋅\sqrt{3}+3⋅\sqrt{100}⋅\sqrt{3}\text{.}\)

1p

\(4⋅3⋅\sqrt{3}+3⋅10⋅\sqrt{3}=12\sqrt{3}+30\sqrt{3}=42\sqrt{3}\text{.}\)

1p

1p

c

\({6 \over 5\sqrt{3}}\)

WortelInNoemer
0089 - Wortels vereenvoudigen - basis - 1ms

c

\({6 \over 5\sqrt{3}}={6 \over 5\sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={6\sqrt{3} \over 5⋅3}=\frac{2}{5}\sqrt{3}\text{.}\)

1p

1p

d

\(\sqrt{\frac{9}{76}}\)

BreukInWortel (3)
008d - Wortels vereenvoudigen - basis - 1ms

d

\(\sqrt{\frac{9}{76}}={\sqrt{9} \over \sqrt{76}}={3 \over \sqrt{76}}⋅{\sqrt{76} \over \sqrt{76}}={3\sqrt{76} \over 76}=\frac{3}{76}\sqrt{76}=\frac{3}{76}⋅2⋅\sqrt{19}=\frac{3}{38}\sqrt{19}\text{.}\)

1p

opgave 2

Herleid.

1p

a

\(\sqrt{10\frac{2}{3}}\)

BreukInWortel (4)
008e - Wortels vereenvoudigen - basis - 1ms

a

\(\sqrt{10\frac{2}{3}}=\sqrt{\frac{32}{3}}={\sqrt{32} \over \sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={\sqrt{96} \over 3}=\frac{1}{3}\sqrt{96}=\frac{1}{3}⋅4⋅\sqrt{6}=1\frac{1}{3}\sqrt{6}\text{.}\)

1p

1p

b

\(2\sqrt{2}⋅4\sqrt{6}\)

Vermenigvuldigen (5)
00dd - Wortels vereenvoudigen - basis - 6ms - data pool: #22 (5ms)

b

\(2\sqrt{2}⋅4\sqrt{6}=8\sqrt{12}=8⋅\sqrt{4}⋅\sqrt{3}=8⋅2⋅\sqrt{3}=16\sqrt{3}\)

1p

"