Getal & Ruimte (13e editie) - havo wiskunde B
'Wortels vereenvoudigen'.
| 2 havo/vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{500}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{500} = \sqrt{100} ⋅ \sqrt{5} = 10 \sqrt{5} \text{.}\) 1p 1p b \(-5 \sqrt{50}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms b \(-5 \sqrt{50} = -5 ⋅ \sqrt{25} ⋅ \sqrt{2} = -5 ⋅ 5 ⋅ \sqrt{2} = -25 \sqrt{2} \text{.}\) 1p 1p c \(\sqrt{\frac{1}{100}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 47ms c \(\sqrt{\frac{1}{100}} = {\sqrt{1} \over \sqrt{100}} = \frac{1}{10} \text{.}\) 1p 1p d \({36 \sqrt{120} \over 4 \sqrt{6}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 9ms d \({36 \sqrt{120} \over 4 \sqrt{6}} = {36 \over 4} ⋅ {\sqrt{120} \over \sqrt{6}} = 9 \sqrt{20} = 9 ⋅ \sqrt{4} ⋅ \sqrt{5} = 9 ⋅ 2 ⋅ \sqrt{5} = 18 \sqrt{5}\) 1p |
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| 3 havo | 5.4 Wortels herleiden |
opgave 1Herleid. 1p \(\sqrt{5\frac{13}{16}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{5\frac{13}{16}} = \sqrt{\frac{93}{16}} = {\sqrt{93} \over \sqrt{16}} = {\sqrt{93} \over 4} = \frac{1}{4} \sqrt{93} \text{.}\) 1p |
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| havo wiskunde B | 7.2 Afstanden bij punten en lijnen |
opgave 1Herleid. 2p a \(\sqrt{20} + \sqrt{125}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{20} + \sqrt{125} = \sqrt{4} ⋅ \sqrt{5} + \sqrt{25} ⋅ \sqrt{5} = 2 \sqrt{5} + 5 \sqrt{5} \text{.}\) 1p ○ \(2 \sqrt{5} + 5 \sqrt{5} = 7 \sqrt{5} \text{.}\) 1p 2p b \(7 \sqrt{80} - 4 \sqrt{20}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 0ms b \(7 \sqrt{80} - 4 \sqrt{20} = 7 ⋅ \sqrt{16} ⋅ \sqrt{5} - 4 ⋅ \sqrt{4} ⋅ \sqrt{5} \text{.}\) 1p ○ \(7 ⋅ 4 ⋅ \sqrt{5} - 4 ⋅ 2 ⋅ \sqrt{5} = 28 \sqrt{5} - 8 \sqrt{5} = 20 \sqrt{5} \text{.}\) 1p 1p c \({8 \over 7 \sqrt{7}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms c \({8 \over 7 \sqrt{7}} = {8 \over 7 \sqrt{7}} ⋅ {\sqrt{7} \over \sqrt{7}} = {8 \sqrt{7} \over 7 ⋅ 7} = \frac{8}{49} \sqrt{7} \text{.}\) 1p 1p d \(\sqrt{3\frac{4}{15}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{3\frac{4}{15}} = \sqrt{\frac{49}{15}} = {\sqrt{49} \over \sqrt{15}} = {7 \over \sqrt{15}} ⋅ {\sqrt{15} \over \sqrt{15}} = {7 \sqrt{15} \over 15} = \frac{7}{15} \sqrt{15} \text{.}\) 1p opgave 2Herleid. 1p a \(\sqrt{\frac{3}{13}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{\frac{3}{13}} = {\sqrt{3} \over \sqrt{13}} ⋅ {\sqrt{13} \over \sqrt{13}} = {\sqrt{39} \over 13} = \frac{1}{13} \sqrt{39} \text{.}\) 1p 1p b \(2 \sqrt{2} ⋅ 5 \sqrt{14}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 3ms - data pool: #22 (2ms) b \(2 \sqrt{2} ⋅ 5 \sqrt{14} = 10 \sqrt{28} = 10 ⋅ \sqrt{4} ⋅ \sqrt{7} = 10 ⋅ 2 ⋅ \sqrt{7} = 20 \sqrt{7}\) 1p |