Getal & Ruimte (13e editie) - havo wiskunde B
'Wortels vereenvoudigen'.
| 2 havo/vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 1p a \(\sqrt{63}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{63}=\sqrt{9}⋅\sqrt{7}=3\sqrt{7}\text{.}\) 1p 1p b \(-2\sqrt{500}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 1ms b \(-2\sqrt{500}=-2⋅\sqrt{100}⋅\sqrt{5}=-2⋅10⋅\sqrt{5}=-20\sqrt{5}\text{.}\) 1p 1p c \(\sqrt{\frac{9}{100}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 103ms c \(\sqrt{\frac{9}{100}}={\sqrt{9} \over \sqrt{100}}=\frac{3}{10}\text{.}\) 1p 1p d \({54\sqrt{168} \over 9\sqrt{6}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 16ms d \({54\sqrt{168} \over 9\sqrt{6}}={54 \over 9}⋅{\sqrt{168} \over \sqrt{6}}=6\sqrt{28}=6⋅\sqrt{4}⋅\sqrt{7}=6⋅2⋅\sqrt{7}=12\sqrt{7}\) 1p |
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| 3 havo | 5.4 Wortels herleiden |
opgave 1Herleid. 1p \(\sqrt{\frac{47}{49}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms ○ \(\sqrt{\frac{47}{49}}={\sqrt{47} \over \sqrt{49}}={\sqrt{47} \over 7}=\frac{1}{7}\sqrt{47}\text{.}\) 1p |
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| havo wiskunde B | 7.2 Afstanden bij punten en lijnen |
opgave 1Herleid. 2p a \(\sqrt{50}+\sqrt{200}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{50}+\sqrt{200}=\sqrt{25}⋅\sqrt{2}+\sqrt{100}⋅\sqrt{2}=5\sqrt{2}+10\sqrt{2}\text{.}\) 1p ○ \(5\sqrt{2}+10\sqrt{2}=15\sqrt{2}\text{.}\) 1p 2p b \(4\sqrt{27}+3\sqrt{300}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 1ms b \(4\sqrt{27}+3\sqrt{300}=4⋅\sqrt{9}⋅\sqrt{3}+3⋅\sqrt{100}⋅\sqrt{3}\text{.}\) 1p ○ \(4⋅3⋅\sqrt{3}+3⋅10⋅\sqrt{3}=12\sqrt{3}+30\sqrt{3}=42\sqrt{3}\text{.}\) 1p 1p c \({6 \over 5\sqrt{3}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 1ms c \({6 \over 5\sqrt{3}}={6 \over 5\sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={6\sqrt{3} \over 5⋅3}=\frac{2}{5}\sqrt{3}\text{.}\) 1p 1p d \(\sqrt{\frac{9}{76}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 1ms d \(\sqrt{\frac{9}{76}}={\sqrt{9} \over \sqrt{76}}={3 \over \sqrt{76}}⋅{\sqrt{76} \over \sqrt{76}}={3\sqrt{76} \over 76}=\frac{3}{76}\sqrt{76}=\frac{3}{76}⋅2⋅\sqrt{19}=\frac{3}{38}\sqrt{19}\text{.}\) 1p opgave 2Herleid. 1p a \(\sqrt{10\frac{2}{3}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 1ms a \(\sqrt{10\frac{2}{3}}=\sqrt{\frac{32}{3}}={\sqrt{32} \over \sqrt{3}}⋅{\sqrt{3} \over \sqrt{3}}={\sqrt{96} \over 3}=\frac{1}{3}\sqrt{96}=\frac{1}{3}⋅4⋅\sqrt{6}=1\frac{1}{3}\sqrt{6}\text{.}\) 1p 1p b \(2\sqrt{2}⋅4\sqrt{6}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 6ms - data pool: #22 (5ms) b \(2\sqrt{2}⋅4\sqrt{6}=8\sqrt{12}=8⋅\sqrt{4}⋅\sqrt{3}=8⋅2⋅\sqrt{3}=16\sqrt{3}\) 1p |