\({4 \over 7 x} + {2 \over 7 x} = {6 \over 7 x}\)

\({2 \over a} + {7 \over 6 a} = {12 \over 6 a} + {7 \over 6 a} = {19 \over 6 a}\)

\({6 \over 2 p} - {8 \over 5 q} = {30 q \over 10 p q} - {16 p \over 10 p q} = {30 q - 16 p \over 10 p q} = {15 q - 8 p \over 5 p q}\)

\(4 + {5 \over 3 x} = {4 \over 1} + {5 \over 3 x} = {12 x \over 3 x} + {5 \over 3 x} = {12 x + 5 \over 3 x}\)

\({8 a \over b} + {3 \over 5 b} = {40 a \over 5 b} + {3 \over 5 b} = {40 a + 3 \over 5 b}\)

\({9 x \over x} = {9 \over 1} = 9\)

\({p \over 9 p} = {1 \over 9}\)

\({-10 a \over 45 a} = -\frac{2}{9}\)

\({-24 a \over 3 a} = -8\)

\({6 x y \over 14 x z} = {3 y \over 7 z}\)

\({8 b \over 36 a b} = {2 \over 9 a}\)

\({12 a b c \over 2 b c} = 6 a\)

\({2 x y \over y} + {6 x z \over z} = 2 x + 6 x = 8 x\)

\(6 x - {4 \over 9 x} = {6 x \over 1} ⋅ {9 x \over 9 x} - {4 \over 9 x} = {54 x^{2} \over 9 x} - {4 \over 9 x} = {54 x^{2} - 4 \over 9 x}\)

\({7 b \over 8 a} + {9 a \over 3 b} = {21 b^{2} \over 24 a b} + {72 a^{2} \over 24 a b} = {72 a^{2} + 21 b^{2} \over 24 a b} = {24 a^{2} + 7 b^{2} \over 8 a b}\)

\({9 \over p} ⋅ -{6 \over q} = -{54 \over p q}\)

\({a \over 2} ⋅ {3 \over b} = {3 a \over 2 b}\)

\(-{4 \over 3} ⋅ x = -{4 x \over 3}\)

\({2 b \over a} ⋅ {a + 5 \over 4} = {2 b (a + 5) \over 4 a} = {b (a + 5) \over 2 a} = {a b + 5 b \over 2 a}\)

\({4 \over a} : {5 \over b} = {4 \over a} ⋅ {b \over 5} = {4 b \over 5 a}\)

\({8 \over 5} : p = {8 \over 5} : {p \over 1} = {8 \over 5} ⋅ {1 \over p} = {8 \over 5 p}\)

\({7 \over 6} : {x - 5 y \over y} = {7 \over 6} ⋅ {y \over x - 5 y} = {7 y \over 6 (x - 5 y)} = {7 y \over 6 x - 30 y}\)

\({8 x \over 5} + {x - 7 \over 4} = {32 x \over 20} + {5 (x - 7) \over 20} = {32 x + 5 (x - 7) \over 20} = {37 x - 35 \over 20}\)

\({-8 x - 5 \over 3 x - 1} + 4 = {-8 x - 5 \over 3 x - 1} + {4 (3 x - 1) \over 3 x - 1} = {-8 x - 5 + 4 (3 x - 1) \over 3 x - 1} = {-8 x - 5 + 12 x - 4 \over 3 x - 1} = {4 x - 9 \over 3 x - 1}\)

\({3 x^{2} + 6 x - 90 \over 3 x} = {3 x^{2} \over 3 x} + {6 x \over 3 x} - {90 \over 3 x} = x + 2 - {30 \over x}\)

\({9 x^{2} - 6 x - 7 \over 2 x^{2}} = {9 x^{2} \over 2 x^{2}} - {6 x \over 2 x^{2}} - {7 \over 2 x^{2}} = 4\frac{1}{2} - {3 \over x} - {7 \over 2 x^{2}}\)