\({6 \over 3p}+{9 \over 3p}={15 \over 3p}={5 \over p}\)

\({3 \over a}+{9 \over 2a}={6 \over 2a}+{9 \over 2a}={15 \over 2a}\)

\({2 \over 3a}-{7 \over 4b}={8b \over 12ab}-{21a \over 12ab}={8b-21a \over 12ab}\)

\(5-{4 \over 7x}={5 \over 1}-{4 \over 7x}={35x \over 7x}-{4 \over 7x}={35x-4 \over 7x}\)

\({7x \over y}-{9 \over 6y}={42x \over 6y}-{9 \over 6y}={42x-9 \over 6y}={14x-3 \over 2y}\)

\({4a \over a}={4 \over 1}=4\)

\({p \over 7p}={1 \over 7}\)

\({-10x \over -16x}=\frac{5}{8}\)

\({15a \over -5a}=-3\)

\({6xy \over -10xz}=-{3y \over 5z}\)

\({-9b \over 24ab}=-{3 \over 8a}\)

\({24abc \over 3bc}=8a\)

\({6xy \over y}+{7xz \over z}=6x+7x=13x\)

\(6x-{5 \over 8x}={6x \over 1}⋅{8x \over 8x}-{5 \over 8x}={48x^2 \over 8x}-{5 \over 8x}={48x^2-5 \over 8x}\)

\({3y \over 6x}-{9x \over 8y}={12y^2 \over 24xy}-{27x^2 \over 24xy}={-27x^2+12y^2 \over 24xy}={-9x^2+4y^2 \over 8xy}\)

\({8 \over a}⋅-{5 \over b}=-{40 \over ab}\)

\({a \over 3}⋅-{6 \over b}=-{6a \over 3b}=-{2a \over b}\)

\(-{2 \over 9}⋅p=-{2p \over 9}\)

\({4y \over x}⋅{x-5 \over 2}={4y(x-5) \over 2x}={2y(x-5) \over x}={2xy-10y \over x}\)

\({2 \over a}:{5 \over b}={2 \over a}⋅{b \over 5}={2b \over 5a}\)

\(-{9 \over 2}:a=-{9 \over 2}:{a \over 1}=-{9 \over 2}⋅{1 \over a}=-{9 \over 2a}\)

\(-{3 \over 8}:{x-4y \over y}=-{3 \over 8}⋅{y \over x-4y}=-{3y \over 8(x-4y)}=-{3y \over 8x-32y}\)

\({6p \over 7}+{p+5 \over 8}={48p \over 56}+{7(p+5) \over 56}={48p+7(p+5) \over 56}={55p+35 \over 56}\)

\({-6a-8 \over 7a+2}-1={-6a-8 \over 7a+2}-{1(7a+2) \over 7a+2}={-6a-8-1(7a+2) \over 7a+2}={-6a-8-7a-2 \over 7a+2}={-13a-10 \over 7a+2}\)

\({2a^2-3a-10 \over a}={2a^2 \over a}-{3a \over a}-{10 \over a}=2a-3-{10 \over a}\)

\({3p^2-8p-7 \over 9p^2}={3p^2 \over 9p^2}-{8p \over 9p^2}-{7 \over 9p^2}=\frac{1}{3}-{8 \over 9p}-{7 \over 9p^2}\)