\({6 \over 8 x} + {5 \over 8 x} = {11 \over 8 x}\)

\({3 \over a} + {7 \over 4 a} = {12 \over 4 a} + {7 \over 4 a} = {19 \over 4 a}\)

\({8 \over 3 x} - {7 \over 9 y} = {24 y \over 9 x y} - {7 x \over 9 x y} = {24 y - 7 x \over 9 x y}\)

\(9 - {8 \over 5 p} = {9 \over 1} - {8 \over 5 p} = {45 p \over 5 p} - {8 \over 5 p} = {45 p - 8 \over 5 p}\)

\({8 a \over b} - {4 \over 3 b} = {24 a \over 3 b} - {4 \over 3 b} = {24 a - 4 \over 3 b}\)

\({5 x \over x} = {5 \over 1} = 5\)

\({a \over 3 a} = {1 \over 3}\)

\({9 x \over -24 x} = -\frac{3}{8}\)

\({32 a \over -4 a} = -8\)

\({-6 p q \over -21 p r} = {2 q \over 7 r}\)

\({9 y \over -21 x y} = -{3 \over 7 x}\)

\({-40 a b c \over 5 b c} = -8 a\)

\({6 a b \over b} + {2 a c \over c} = 6 a + 2 a = 8 a\)

\(3 a - {5 \over 7 a} = {3 a \over 1} ⋅ {7 a \over 7 a} - {5 \over 7 a} = {21 a^{2} \over 7 a} - {5 \over 7 a} = {21 a^{2} - 5 \over 7 a}\)

\({9 y \over 8 x} + {5 x \over 7 y} = {63 y^{2} \over 56 x y} + {40 x^{2} \over 56 x y} = {40 x^{2} + 63 y^{2} \over 56 x y}\)

\({7 \over p} ⋅ {6 \over q} = {42 \over p q}\)

\({x \over 5} ⋅ {8 \over y} = {8 x \over 5 y}\)

\(-{8 \over 7} ⋅ a = -{8 a \over 7}\)

\({4 b \over a} ⋅ {a + 7 \over 2} = {4 b (a + 7) \over 2 a} = {2 b (a + 7) \over a} = {2 a b + 14 b \over a}\)

\({3 \over a} : {6 \over b} = {3 \over a} ⋅ {b \over 6} = {3 b \over 6 a} = {b \over 2 a}\)

\({4 \over 3} : p = {4 \over 3} : {p \over 1} = {4 \over 3} ⋅ {1 \over p} = {4 \over 3 p}\)

\({4 \over 9} : {x + 7 y \over y} = {4 \over 9} ⋅ {y \over x + 7 y} = {4 y \over 9 (x + 7 y)} = {4 y \over 9 x + 63 y}\)

\({x \over 9} + {x - 5 \over 4} = {4 x \over 36} + {9 (x - 5) \over 36} = {4 x + 9 (x - 5) \over 36} = {13 x - 45 \over 36}\)

\({2 a + 3 \over -5 a + 8} - 4 = {2 a + 3 \over -5 a + 8} + {-4 (-5 a + 8) \over -5 a + 8} = {2 a + 3 - 4 (-5 a + 8) \over -5 a + 8} = {2 a + 3 + 20 a - 32 \over -5 a + 8} = {22 a - 29 \over -5 a + 8}\)

\({4 x^{2} + 6 x + 20 \over 2 x} = {4 x^{2} \over 2 x} + {6 x \over 2 x} + {20 \over 2 x} = 2 x + 3 + {10 \over x}\)

\({7 x^{2} + x + 5 \over 2 x^{2}} = {7 x^{2} \over 2 x^{2}} + {x \over 2 x^{2}} + {5 \over 2 x^{2}} = 3\frac{1}{2} + {1 \over 2 x} + {5 \over 2 x^{2}}\)