\({5 \over 4a}+{7 \over 4a}={12 \over 4a}={3 \over a}\)

\({9 \over p}-{4 \over 5p}={45 \over 5p}-{4 \over 5p}={41 \over 5p}\)

\({5 \over 6a}-{2 \over 8b}={20b \over 24ab}-{6a \over 24ab}={20b-6a \over 24ab}={10b-3a \over 12ab}\)

\(8+{4 \over 5x}={8 \over 1}+{4 \over 5x}={40x \over 5x}+{4 \over 5x}={40x+4 \over 5x}\)

\({6x \over y}+{4 \over 8y}={48x \over 8y}+{4 \over 8y}={48x+4 \over 8y}={12x+1 \over 2y}\)

\({2p \over p}={2 \over 1}=2\)

\({a \over 4a}={1 \over 4}\)

\({9a \over -24a}=-\frac{3}{8}\)

\({-20x \over -5x}=4\)

\({-9xy \over 12xz}=-{3y \over 4z}\)

\({40q \over 45pq}={8 \over 9p}\)

\({10abc \over 2bc}=5a\)

\({7ab \over b}-{3ac \over c}=7a-3a=4a\)

\(8a-{2 \over 9a}={8a \over 1}⋅{9a \over 9a}-{2 \over 9a}={72a^2 \over 9a}-{2 \over 9a}={72a^2-2 \over 9a}\)

\({5q \over 7p}+{3p \over 8q}={40q^2 \over 56pq}+{21p^2 \over 56pq}={21p^2+40q^2 \over 56pq}\)

\({2 \over x}⋅-{4 \over y}=-{8 \over xy}\)

\({a \over 4}⋅-{9 \over b}=-{9a \over 4b}\)

\({7 \over 9}⋅x={7x \over 9}\)

\({5y \over x}⋅{x-6 \over 3}={5y(x-6) \over 3x}={5xy-30y \over 3x}\)

\({9 \over p}:{5 \over q}={9 \over p}⋅{q \over 5}={9q \over 5p}\)

\(-{5 \over 7}:a=-{5 \over 7}:{a \over 1}=-{5 \over 7}⋅{1 \over a}=-{5 \over 7a}\)

\({3 \over 5}:{a+9b \over b}={3 \over 5}⋅{b \over a+9b}={3b \over 5(a+9b)}={3b \over 5a+45b}\)

\({8x \over 7}+{x-9 \over 4}={32x \over 28}+{7(x-9) \over 28}={32x+7(x-9) \over 28}={39x-63 \over 28}\)

\({-9x+1 \over 3x+8}-2={-9x+1 \over 3x+8}-{2(3x+8) \over 3x+8}={-9x+1-2(3x+8) \over 3x+8}={-9x+1-6x-16 \over 3x+8}={-15x-15 \over 3x+8}\)

\({9a^2-3a+60 \over 3a}={9a^2 \over 3a}-{3a \over 3a}+{60 \over 3a}=3a-1+{20 \over a}\)

\({a^2-9a-3 \over 2a^2}={a^2 \over 2a^2}-{9a \over 2a^2}-{3 \over 2a^2}=\frac{1}{2}-{9 \over 2a}-{3 \over 2a^2}\)