\({3 \over 6 x} - {2 \over 6 x} = {1 \over 6 x}\)

\({3 \over a} - {9 \over 8 a} = {24 \over 8 a} - {9 \over 8 a} = {15 \over 8 a}\)

\({7 \over 9 x} - {3 \over 2 y} = {14 y \over 18 x y} - {27 x \over 18 x y} = {14 y - 27 x \over 18 x y}\)

\(2 + {7 \over 6 p} = {2 \over 1} + {7 \over 6 p} = {12 p \over 6 p} + {7 \over 6 p} = {12 p + 7 \over 6 p}\)

\({8 a \over b} + {9 \over 6 b} = {48 a \over 6 b} + {9 \over 6 b} = {48 a + 9 \over 6 b} = {16 a + 3 \over 2 b}\)

\({4 a \over a} = {4 \over 1} = 4\)

\({p \over 3 p} = {1 \over 3}\)

\({10 x \over 16 x} = \frac{5}{8}\)

\({-10 a \over 5 a} = -2\)

\({-10 x y \over -45 x z} = {2 y \over 9 z}\)

\({14 b \over 18 a b} = {7 \over 9 a}\)

\({18 a b c \over 3 b c} = 6 a\)

\({6 x y \over y} + {4 x z \over z} = 6 x + 4 x = 10 x\)

\(5 p - {7 \over 6 p} = {5 p \over 1} ⋅ {6 p \over 6 p} - {7 \over 6 p} = {30 p^{2} \over 6 p} - {7 \over 6 p} = {30 p^{2} - 7 \over 6 p}\)

\({9 y \over 5 x} + {8 x \over 6 y} = {54 y^{2} \over 30 x y} + {40 x^{2} \over 30 x y} = {40 x^{2} + 54 y^{2} \over 30 x y} = {20 x^{2} + 27 y^{2} \over 15 x y}\)

\({6 \over x} ⋅ {9 \over y} = {54 \over x y}\)

\({a \over 6} ⋅ -{7 \over b} = -{7 a \over 6 b}\)

\(-{2 \over 3} ⋅ a = -{2 a \over 3}\)

\({2 b \over a} ⋅ {a + 9 \over 6} = {2 b (a + 9) \over 6 a} = {b (a + 9) \over 3 a} = {a b + 9 b \over 3 a}\)

\({7 \over x} : {8 \over y} = {7 \over x} ⋅ {y \over 8} = {7 y \over 8 x}\)

\(-{3 \over 8} : x = -{3 \over 8} : {x \over 1} = -{3 \over 8} ⋅ {1 \over x} = -{3 \over 8 x}\)

\(-{4 \over 9} : {p + q \over q} = -{4 \over 9} ⋅ {q \over p + q} = -{4 q \over 9 (p + q)} = -{4 q \over 9 p + 9 q}\)

\({3 a \over 5} + {a + 8 \over 9} = {27 a \over 45} + {5 (a + 8) \over 45} = {27 a + 5 (a + 8) \over 45} = {32 a + 40 \over 45}\)

\({-4 x - 5 \over -7 x - 8} + 6 = {-4 x - 5 \over -7 x - 8} - {-6 (-7 x - 8) \over -7 x - 8} = {-4 x - 5 + 6 (-7 x - 8) \over -7 x - 8} = {-4 x - 5 - 42 x - 48 \over -7 x - 8} = {-46 x - 53 \over -7 x - 8}\)

\({a^{2} - 3 a - 20 \over a} = {a^{2} \over a} - {3 a \over a} - {20 \over a} = a - 3 - {20 \over a}\)

\({7 x^{2} + 3 x - 2 \over x^{2}} = {7 x^{2} \over x^{2}} + {3 x \over x^{2}} - {2 \over x^{2}} = 7 + {3 \over x} - {2 \over x^{2}}\)