\({6 \over 4x}-{2 \over 4x}={4 \over 4x}={1 \over x}\)

\({4 \over p}+{3 \over 7p}={28 \over 7p}+{3 \over 7p}={31 \over 7p}\)

\({9 \over 6x}+{7 \over 5y}={45y \over 30xy}+{42x \over 30xy}={45y+42x \over 30xy}={15y+14x \over 10xy}\)

\(7+{9 \over 2a}={7 \over 1}+{9 \over 2a}={14a \over 2a}+{9 \over 2a}={14a+9 \over 2a}\)

\({5a \over b}-{7 \over 8b}={40a \over 8b}-{7 \over 8b}={40a-7 \over 8b}\)

\({5a \over a}={5 \over 1}=5\)

\({a \over 6a}={1 \over 6}\)

\({28x \over 32x}=\frac{7}{8}\)

\({-45x \over 5x}=-9\)

\({10pq \over 16pr}={5q \over 8r}\)

\({-6y \over 21xy}=-{2 \over 7x}\)

\({-12xyz \over 4yz}=-3x\)

\({2ab \over b}-{5ac \over c}=2a-5a=-3a\)

\(4p-{7 \over 8p}={4p \over 1}⋅{8p \over 8p}-{7 \over 8p}={32p^2 \over 8p}-{7 \over 8p}={32p^2-7 \over 8p}\)

\({3y \over 6x}+{2x \over 8y}={12y^2 \over 24xy}+{6x^2 \over 24xy}={6x^2+12y^2 \over 24xy}={x^2+2y^2 \over 4xy}\)

\({4 \over x}⋅-{2 \over y}=-{8 \over xy}\)

\({a \over 2}⋅-{3 \over b}=-{3a \over 2b}\)

\({5 \over 6}⋅a={5a \over 6}\)

\({4q \over p}⋅{p-2 \over 5}={4q(p-2) \over 5p}={4pq-8q \over 5p}\)

\({9 \over a}:{3 \over b}={9 \over a}⋅{b \over 3}={9b \over 3a}={3b \over a}\)

\(-{5 \over 4}:x=-{5 \over 4}:{x \over 1}=-{5 \over 4}⋅{1 \over x}=-{5 \over 4x}\)

\({7 \over 5}:{x+3y \over y}={7 \over 5}⋅{y \over x+3y}={7y \over 5(x+3y)}={7y \over 5x+15y}\)

\({5a \over 3}+{a-9 \over 8}={40a \over 24}+{3(a-9) \over 24}={40a+3(a-9) \over 24}={43a-27 \over 24}\)

\({5a+1 \over 6a+9}-8={5a+1 \over 6a+9}-{8(6a+9) \over 6a+9}={5a+1-8(6a+9) \over 6a+9}={5a+1-48a-72 \over 6a+9}={-43a-71 \over 6a+9}\)

\({p^2-2p+30 \over p}={p^2 \over p}-{2p \over p}+{30 \over p}=p-2+{30 \over p}\)

\({5x^2-4x-8 \over 3x^2}={5x^2 \over 3x^2}-{4x \over 3x^2}-{8 \over 3x^2}=1\frac{2}{3}-{4 \over 3x}-{8 \over 3x^2}\)