Getal & Ruimte (13e editie) - vwo wiskunde B

'Differentiëren'.

vwo wiskunde B 2.3 Limiet en afgeleide

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = 6 a^{2} + 3\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(a) = 6 ⋅ 2 ⋅ a^{1} \text{.}\)

1p

○

\(f'(a) = 12 a \text{.}\)

1p

2p

b

\(f(a) = 6 a^{3} - 2 a^{2} - 8 a\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 2ms - dynamic variables

b

\(f'(a) = 6 ⋅ 3 ⋅ a^{2} - 2 ⋅ 2 ⋅ a^{1} - 8 \text{.}\)

1p

○

\(f'(a) = 18 a^{2} - 4 a - 8 \text{.}\)

1p

2p

c

\(f(p) = \frac{1}{5} p^{9} + \frac{2}{3} p^{5} + 1\frac{1}{7} p\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 0ms - dynamic variables

c

\(f'(p) = \frac{1}{5} ⋅ 9 ⋅ p^{8} + \frac{2}{3} ⋅ 5 ⋅ p^{4} + 1\frac{1}{7} \text{.}\)

1p

○

\(f'(p) = 1\frac{4}{5} p^{8} + 3\frac{1}{3} p^{4} + 1\frac{1}{7} \text{.}\)

1p

2p

d

\(f(x) = (9 x^{3} - 7) (x - 2)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 0ms - dynamic variables

d

(Haakjes wegwerken)
\(f(x) = (9 x^{3} - 7) (x - 2) = 9 x^{4} - 18 x^{3} - 7 x + 14\)

1p

○

(Differentiëren)
\(f'(x) = 36 x^{3} - 54 x^{2} - 7 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(x) = (3 x^{5} + 2)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 0ms - dynamic variables

○

(Haakjes wegwerken)
\(f(x) = (3 x^{5} + 2)^{2} = 9 x^{10} + 12 x^{5} + 4\)

1p

○

(Differentiëren)
\(f'(x) = 90 x^{9} + 60 x^{4} \text{.}\)

1p

vwo wiskunde B 2.4 De productregel en de quotiëntregel

Differentiëren (4)

opgave 1

Differentieer met behulp van de productregel.

2p

a

\(f(x) = (-5 x + 4) (-9 x^{2} + 9 x)\)

Productregel (1)
009z - Differentiëren - basis - basis - 1ms - dynamic variables

a

(Productregel)
\(f'(x) = -5 (-9 x^{2} + 9 x) + (-5 x + 4) (-18 x + 9) \text{.}\)

2p

2p

b

\(f(a) = (-6 a^{2} - 3 a) (9 a^{2} + a - 8)\)

Productregel (2)
00a0 - Differentiëren - basis - basis - 0ms - dynamic variables

b

(Productregel)
\(f'(a) = (-12 a - 3) (9 a^{2} + a - 8) + (-6 a^{2} - 3 a) (18 a + 1) \text{.}\)

2p

opgave 2

Differentieer.

2p

a

\(f(a) = {-2 a - 3 \over 2 a - 9}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(a) = {(2 a - 9) ⋅ -2 - (-2 a - 3) ⋅ 2 \over (2 a - 9)^{2}} \text{.}\)

1p

○

\(f'(a) = {(-4 a + 18) - (-4 a - 6) \over (2 a - 9)^{2}} = {24 \over (2 a - 9)^{2}} \text{.}\)

1p

2p

b

\(f(p) = {-8 p^{2} \over -2 p - 7}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 0ms - dynamic variables

b

(Quotiëntregel)
\(f'(p) = {(-2 p - 7) ⋅ -16 p - -8 p^{2} ⋅ -2 \over (-2 p - 7)^{2}} \text{.}\)

1p

○

\(f'(p) = {(32 p^{2} + 112 p) - 16 p^{2} \over (-2 p - 7)^{2}} = {16 p^{2} + 112 p \over (-2 p - 7)^{2}} \text{.}\)

1p

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