Getal & Ruimte (13e editie) - vwo wiskunde B

'Differentiëren'.

vwo wiskunde B 2.3 Limiet en afgeleide

Differentiëren (5)

opgave 1

Differentieer.

2p

a

\(f(a) = 2 a^{2} + 3 a + 7\)

Machtsfunctie (1)
009w - Differentiëren - basis - basis - 1ms - dynamic variables

a

\(f'(a) = 2 ⋅ 2 ⋅ a^{1} + 3 \text{.}\)

1p

\(f'(a) = 4 a + 3 \text{.}\)

1p

2p

b

\(f(a) = 7 a^{6} + 2 a - 1\)

Machtsfunctie (2)
009x - Differentiëren - basis - basis - 4ms - dynamic variables

b

\(f'(a) = 7 ⋅ 6 ⋅ a^{5} + 2 \text{.}\)

1p

\(f'(a) = 42 a^{5} + 2 \text{.}\)

1p

2p

c

\(f(p) = \frac{2}{5} p^{9} + 1\frac{1}{8} p^{5} + 1\frac{3}{4} p^{3} + 2 p\)

Machtsfunctie (3)
009y - Differentiëren - basis - basis - 0ms - dynamic variables

c

\(f'(p) = \frac{2}{5} ⋅ 9 ⋅ p^{8} + 1\frac{1}{8} ⋅ 5 ⋅ p^{4} + 1\frac{3}{4} ⋅ 3 ⋅ p^{2} + 2 \text{.}\)

1p

\(f'(p) = 3\frac{3}{5} p^{8} + 5\frac{5}{8} p^{4} + 5\frac{1}{4} p^{2} + 2 \text{.}\)

1p

2p

d

\(f(x) = (6 x^{4} + 5) (x + 7)\)

HaakjesUitwerken (1)
00df - Differentiëren - basis - eind - 1ms - dynamic variables

d

(Haakjes wegwerken)
\(f(x) = (6 x^{4} + 5) (x + 7) = 6 x^{5} + 42 x^{4} + 5 x + 35\)

1p

(Differentiëren)
\(f'(x) = 30 x^{4} + 168 x^{3} + 5 \text{.}\)

1p

opgave 2

Differentieer.

2p

\(f(x) = (3 x^{4} - 5)^{2}\)

HaakjesUitwerken (2)
00dg - Differentiëren - basis - eind - 1ms - dynamic variables

(Haakjes wegwerken)
\(f(x) = (3 x^{4} - 5)^{2} = 9 x^{8} - 30 x^{4} + 25\)

1p

(Differentiëren)
\(f'(x) = 72 x^{7} - 120 x^{3} \text{.}\)

1p

vwo wiskunde B 2.4 De productregel en de quotiëntregel

Differentiëren (4)

opgave 1

Differentieer met behulp van de productregel.

2p

a

\(f(x) = (4 x + 7) (x^{2} - 6 x)\)

Productregel (1)
009z - Differentiëren - basis - basis - 2ms - dynamic variables

a

(Productregel)
\(f'(x) = 4 (x^{2} - 6 x) + (4 x + 7) (2 x - 6) \text{.}\)

2p

2p

b

\(f(p) = (9 p^{2} + 7 p) (6 p^{2} + 3 p + 5)\)

Productregel (2)
00a0 - Differentiëren - basis - basis - 1ms - dynamic variables

b

(Productregel)
\(f'(p) = (18 p + 7) (6 p^{2} + 3 p + 5) + (9 p^{2} + 7 p) (12 p + 3) \text{.}\)

2p

opgave 2

Differentieer.

2p

a

\(f(a) = {-a - 8 \over -9 a + 8}\)

Quotientregel (1)
00a1 - Differentiëren - basis - eind - 1ms - dynamic variables

a

(Quotiëntregel)
\(f'(a) = {(-9 a + 8) ⋅ -1 - (-a - 8) ⋅ -9 \over (-9 a + 8)^{2}} \text{.}\)

1p

\(f'(a) = {(9 a - 8) - (9 a + 72) \over (-9 a + 8)^{2}} = {-80 \over (-9 a + 8)^{2}} \text{.}\)

1p

2p

b

\(f(a) = {-9 a^{2} \over -7 a + 4}\)

Quotientregel (2)
00a2 - Differentiëren - basis - eind - 1ms - dynamic variables

b

(Quotiëntregel)
\(f'(a) = {(-7 a + 4) ⋅ -18 a - -9 a^{2} ⋅ -7 \over (-7 a + 4)^{2}} \text{.}\)

1p

\(f'(a) = {(126 a^{2} - 72 a) - 63 a^{2} \over (-7 a + 4)^{2}} = {63 a^{2} - 72 a \over (-7 a + 4)^{2}} \text{.}\)

1p

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