Getal & Ruimte (13e editie) - vwo wiskunde B
'Sinus, cosinus en tangens'.
| 3 vwo | 6.3 Berekeningen met de tangens |
opgave 13p a Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}R = 43 \text{,}\) \(\angle R = 56\degree\) en \(\angle P = 90\degree \text{.}\) Tangens (1) 007m - Sinus, cosinus en tangens - basis - 0ms a Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle R) = {P\kern{-.8pt}Q \over P\kern{-.8pt}R}\) ofwel \(\tan(56\degree) = {P\kern{-.8pt}Q \over 43} \text{.}\) 1p ○ Hieruit volgt \(P\kern{-.8pt}Q = 43 ⋅ \tan(56\degree) \text{.}\) 1p ○ Dus \(P\kern{-.8pt}Q ≈ 63{,}8 \text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}M = 27 \text{,}\) \(\angle L = 39\degree\) en \(\angle M = 90\degree \text{.}\) Tangens (2) 007n - Sinus, cosinus en tangens - basis - 0ms b Tangens in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\tan(\angle L) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\tan(39\degree) = {27 \over L\kern{-.8pt}M} \text{.}\) 1p ○ Hieruit volgt \(L\kern{-.8pt}M = {27 \over \tan(39\degree)} \text{.}\) 1p ○ Dus \(L\kern{-.8pt}M ≈ 33{,}3 \text{.}\) 1p 3p c Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 57 \text{,}\) \(Q\kern{-.8pt}R = 49\) en \(\angle Q = 90\degree \text{.}\) Tangens (3) 007o - Sinus, cosinus en tangens - basis - 0ms c Tangens in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\tan(\angle P) = {Q\kern{-.8pt}R \over P\kern{-.8pt}Q}\) ofwel \(\tan(\angle P) = {49 \over 57} \text{.}\) 1p ○ Hieruit volgt \(\angle P = \tan^{-1}({49 \over 57}) \text{.}\) 1p ○ Dus \(\angle P ≈ 40{,}7\degree \text{.}\) 1p |
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| 3 vwo | 6.4 De sinus en de cosinus |
opgave 13p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 72 \text{,}\) \(\angle C = 59\degree\) en \(\angle A = 90\degree \text{.}\) Sinus (1) 007g - Sinus, cosinus en tangens - basis - 0ms a Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle C) = {A\kern{-.8pt}B \over B\kern{-.8pt}C}\) ofwel \(\sin(59\degree) = {A\kern{-.8pt}B \over 72} \text{.}\) 1p ○ Hieruit volgt \(A\kern{-.8pt}B = 72 ⋅ \sin(59\degree) \text{.}\) 1p ○ Dus \(A\kern{-.8pt}B ≈ 61{,}7 \text{.}\) 1p 3p b Gegeven is \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) met \(P\kern{-.8pt}Q = 37 \text{,}\) \(\angle R = 41\degree\) en \(\angle P = 90\degree \text{.}\) Sinus (2) 007h - Sinus, cosinus en tangens - basis - 0ms b Sinus in \(\triangle P\kern{-.8pt}Q\kern{-.8pt}R\) geeft \(\sin(\angle R) = {P\kern{-.8pt}Q \over Q\kern{-.8pt}R}\) ofwel \(\sin(41\degree) = {37 \over Q\kern{-.8pt}R} \text{.}\) 1p ○ Hieruit volgt \(Q\kern{-.8pt}R = {37 \over \sin(41\degree)} \text{.}\) 1p ○ Dus \(Q\kern{-.8pt}R ≈ 56{,}4 \text{.}\) 1p 3p c Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(B\kern{-.8pt}C = 27 \text{,}\) \(A\kern{-.8pt}C = 46\) en \(\angle B = 90\degree \text{.}\) Sinus (3) 007i - Sinus, cosinus en tangens - basis - 0ms c Sinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\sin(\angle A) = {B\kern{-.8pt}C \over A\kern{-.8pt}C}\) ofwel \(\sin(\angle A) = {27 \over 46} \text{.}\) 1p ○ Hieruit volgt \(\angle A = \sin^{-1}({27 \over 46}) \text{.}\) 1p ○ Dus \(\angle A ≈ 35{,}9\degree \text{.}\) 1p 3p d Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(L\kern{-.8pt}M = 63 \text{,}\) \(\angle M = 44\degree\) en \(\angle K = 90\degree \text{.}\) Cosinus (1) 007j - Sinus, cosinus en tangens - basis - 0ms d Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle M) = {K\kern{-.8pt}M \over L\kern{-.8pt}M}\) ofwel \(\cos(44\degree) = {K\kern{-.8pt}M \over 63} \text{.}\) 1p ○ Hieruit volgt \(K\kern{-.8pt}M = 63 ⋅ \cos(44\degree) \text{.}\) 1p ○ Dus \(K\kern{-.8pt}M ≈ 45{,}3 \text{.}\) 1p opgave 23p a Gegeven is \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) met \(A\kern{-.8pt}C = 38 \text{,}\) \(\angle C = 56\degree\) en \(\angle A = 90\degree \text{.}\) Cosinus (2) 007k - Sinus, cosinus en tangens - basis - 0ms a Cosinus in \(\triangle A\kern{-.8pt}B\kern{-.8pt}C\) geeft \(\cos(\angle C) = {A\kern{-.8pt}C \over B\kern{-.8pt}C}\) ofwel \(\cos(56\degree) = {38 \over B\kern{-.8pt}C} \text{.}\) 1p ○ Hieruit volgt \(B\kern{-.8pt}C = {38 \over \cos(56\degree)} \text{.}\) 1p ○ Dus \(B\kern{-.8pt}C ≈ 68{,}0 \text{.}\) 1p 3p b Gegeven is \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) met \(K\kern{-.8pt}L = 39 \text{,}\) \(K\kern{-.8pt}M = 50\) en \(\angle L = 90\degree \text{.}\) Cosinus (3) 007l - Sinus, cosinus en tangens - basis - 0ms b Cosinus in \(\triangle K\kern{-.8pt}L\kern{-.8pt}M\) geeft \(\cos(\angle K) = {K\kern{-.8pt}L \over K\kern{-.8pt}M}\) ofwel \(\cos(\angle K) = {39 \over 50} \text{.}\) 1p ○ Hieruit volgt \(\angle K = \cos^{-1}({39 \over 50}) \text{.}\) 1p ○ Dus \(\angle K ≈ 38{,}7\degree \text{.}\) 1p |