Getal & Ruimte (13e editie) - vwo wiskunde B
'Wortels vereenvoudigen'.
| 2 vwo | 5.3 Wortels herleiden |
opgave 1Herleid. 2p a \(\sqrt{32} + \sqrt{8}\) Optellen (5) 0085 - Wortels vereenvoudigen - basis - 0ms a \(\sqrt{32} + \sqrt{8} = \sqrt{16} ⋅ \sqrt{2} + \sqrt{4} ⋅ \sqrt{2} = 4 \sqrt{2} + 2 \sqrt{2} \text{.}\) 1p ○ \(4 \sqrt{2} + 2 \sqrt{2} = 6 \sqrt{2} \text{.}\) 1p 1p b \(\sqrt{63}\) FactorVoorWortelteken (1) 0086 - Wortels vereenvoudigen - basis - 0ms b \(\sqrt{63} = \sqrt{9} ⋅ \sqrt{7} = 3 \sqrt{7} \text{.}\) 1p 1p c \(-4 \sqrt{32}\) FactorVoorWortelteken (2) 0087 - Wortels vereenvoudigen - basis - 0ms c \(-4 \sqrt{32} = -4 ⋅ \sqrt{16} ⋅ \sqrt{2} = -4 ⋅ 4 ⋅ \sqrt{2} = -16 \sqrt{2} \text{.}\) 1p 2p d \(3 \sqrt{18} - 5 \sqrt{200}\) Optellen (6) 0088 - Wortels vereenvoudigen - basis - 0ms d \(3 \sqrt{18} - 5 \sqrt{200} = 3 ⋅ \sqrt{9} ⋅ \sqrt{2} - 5 ⋅ \sqrt{100} ⋅ \sqrt{2} \text{.}\) 1p ○ \(3 ⋅ 3 ⋅ \sqrt{2} - 5 ⋅ 10 ⋅ \sqrt{2} = 9 \sqrt{2} - 50 \sqrt{2} = -41 \sqrt{2} \text{.}\) 1p opgave 2Herleid. 1p \(\sqrt{5\frac{4}{9}}\) BreukInWortel (1) 008b - Wortels vereenvoudigen - basis - 25ms ○ \(\sqrt{5\frac{4}{9}} = \sqrt{\frac{49}{9}} = {\sqrt{49} \over \sqrt{9}} = \frac{7}{3} = 2\frac{1}{3} \text{.}\) 1p |
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| 3 vwo | 5.5 Wortels herleiden |
opgave 1Herleid. 1p a \({7 \over 6 \sqrt{5}}\) WortelInNoemer 0089 - Wortels vereenvoudigen - basis - 0ms a \({7 \over 6 \sqrt{5}} = {7 \over 6 \sqrt{5}} ⋅ {\sqrt{5} \over \sqrt{5}} = {7 \sqrt{5} \over 6 ⋅ 5} = \frac{7}{30} \sqrt{5} \text{.}\) 1p 1p b \(\sqrt{\frac{23}{81}}\) BreukInWortel (2) 008c - Wortels vereenvoudigen - basis - 1ms b \(\sqrt{\frac{23}{81}} = {\sqrt{23} \over \sqrt{81}} = {\sqrt{23} \over 9} = \frac{1}{9} \sqrt{23} \text{.}\) 1p 1p c \(\sqrt{1\frac{10}{71}}\) BreukInWortel (3) 008d - Wortels vereenvoudigen - basis - 0ms c \(\sqrt{1\frac{10}{71}} = \sqrt{\frac{81}{71}} = {\sqrt{81} \over \sqrt{71}} = {9 \over \sqrt{71}} ⋅ {\sqrt{71} \over \sqrt{71}} = {9 \sqrt{71} \over 71} = \frac{9}{71} \sqrt{71} \text{.}\) 1p 1p d \(\sqrt{\frac{2}{75}}\) BreukInWortel (4) 008e - Wortels vereenvoudigen - basis - 0ms d \(\sqrt{\frac{2}{75}} = {\sqrt{2} \over \sqrt{75}} ⋅ {\sqrt{75} \over \sqrt{75}} = {\sqrt{150} \over 75} = \frac{1}{75} \sqrt{150} = \frac{1}{75} ⋅ 5 ⋅ \sqrt{6} = \frac{1}{15} \sqrt{6} \text{.}\) 1p opgave 2Herleid. 1p a \({8 \sqrt{280} \over 2 \sqrt{10}}\) Delen (4) 00dc - Wortels vereenvoudigen - basis - 1ms a \({8 \sqrt{280} \over 2 \sqrt{10}} = {8 \over 2} ⋅ {\sqrt{280} \over \sqrt{10}} = 4 \sqrt{28} = 4 ⋅ \sqrt{4} ⋅ \sqrt{7} = 4 ⋅ 2 ⋅ \sqrt{7} = 8 \sqrt{7}\) 1p 1p b \(2 \sqrt{10} ⋅ 3 \sqrt{5}\) Vermenigvuldigen (5) 00dd - Wortels vereenvoudigen - basis - 2ms - data pool: #22 (2ms) b \(2 \sqrt{10} ⋅ 3 \sqrt{5} = 6 \sqrt{50} = 6 ⋅ \sqrt{25} ⋅ \sqrt{2} = 6 ⋅ 5 ⋅ \sqrt{2} = 30 \sqrt{2}\) 1p |
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| vwo wiskunde B | 3.3 Vergelijkingen in de meetkunde |
opgave 1Herleid. 1p a \({-2 \over 3 - \sqrt{5}}\) SomInNoemer (1) 00r3 - Wortels vereenvoudigen - basis - 0ms a \({-2 \over 3 - \sqrt{5}} = {-2 \over 3 - \sqrt{5}} ⋅ {3 + \sqrt{5} \over 3 + \sqrt{5}}\) 1p 1p b \({4 \sqrt{2} \over \sqrt{3} + \sqrt{5}}\) SomInNoemer (2) 00r4 - Wortels vereenvoudigen - basis - 0ms b \({4 \sqrt{2} \over \sqrt{3} + \sqrt{5}} = {4 \sqrt{2} \over \sqrt{3} + \sqrt{5}} ⋅ {\sqrt{3} - \sqrt{5} \over \sqrt{3} - \sqrt{5}}\) 1p |