\({6 \over 7 a} + {2 \over 7 a} = {8 \over 7 a}\)

\({9 \over a} - {8 \over 7 a} = {63 \over 7 a} - {8 \over 7 a} = {55 \over 7 a}\)

\({7 \over 4 p} - {9 \over 2 q} = {7 q \over 4 p q} - {18 p \over 4 p q} = {7 q - 18 p \over 4 p q}\)

\(2 - {5 \over 6 x} = {2 \over 1} - {5 \over 6 x} = {12 x \over 6 x} - {5 \over 6 x} = {12 x - 5 \over 6 x}\)

\({4 x \over y} - {3 \over 9 y} = {36 x \over 9 y} - {3 \over 9 y} = {36 x - 3 \over 9 y} = {12 x - 1 \over 3 y}\)

\({7 x \over x} = {7 \over 1} = 7\)

\({x \over 4 x} = {1 \over 4}\)

\({-15 a \over -18 a} = \frac{5}{6}\)

\({-30 a \over -5 a} = 6\)

\({-6 p q \over 21 p r} = -{2 q \over 7 r}\)

\({12 q \over -21 p q} = -{4 \over 7 p}\)

\({18 a b c \over 3 b c} = 6 a\)

\({2 x y \over y} - {7 x z \over z} = 2 x - 7 x = -5 x\)

\(5 x + {9 \over 2 x} = {5 x \over 1} ⋅ {2 x \over 2 x} + {9 \over 2 x} = {10 x^{2} \over 2 x} + {9 \over 2 x} = {10 x^{2} + 9 \over 2 x}\)

\({9 q \over 7 p} - {6 p \over 2 q} = {18 q^{2} \over 14 p q} - {42 p^{2} \over 14 p q} = {-42 p^{2} + 18 q^{2} \over 14 p q} = {-21 p^{2} + 9 q^{2} \over 7 p q}\)

\({9 \over x} ⋅ {5 \over y} = {45 \over x y}\)

\({a \over 4} ⋅ -{7 \over b} = -{7 a \over 4 b}\)

\(-{6 \over 7} ⋅ a = -{6 a \over 7}\)

\({3 y \over x} ⋅ {x - 9 \over 8} = {3 y (x - 9) \over 8 x} = {3 x y - 27 y \over 8 x}\)

\({9 \over p} : {5 \over q} = {9 \over p} ⋅ {q \over 5} = {9 q \over 5 p}\)

\({3 \over 7} : a = {3 \over 7} : {a \over 1} = {3 \over 7} ⋅ {1 \over a} = {3 \over 7 a}\)

\({5 \over 8} : {x + 9 y \over y} = {5 \over 8} ⋅ {y \over x + 9 y} = {5 y \over 8 (x + 9 y)} = {5 y \over 8 x + 72 y}\)

\({3 a \over 5} + {a + 2 \over 4} = {12 a \over 20} + {5 (a + 2) \over 20} = {12 a + 5 (a + 2) \over 20} = {17 a + 10 \over 20}\)

\({6 a - 2 \over -7 a - 5} - 4 = {6 a - 2 \over -7 a - 5} + {-4 (-7 a - 5) \over -7 a - 5} = {6 a - 2 - 4 (-7 a - 5) \over -7 a - 5} = {6 a - 2 + 28 a + 20 \over -7 a - 5} = {34 a + 18 \over -7 a - 5}\)

\({2 x^{2} + 4 x - 60 \over 2 x} = {2 x^{2} \over 2 x} + {4 x \over 2 x} - {60 \over 2 x} = x + 2 - {30 \over x}\)

\({5 a^{2} + 8 a - 7 \over 9 a^{2}} = {5 a^{2} \over 9 a^{2}} + {8 a \over 9 a^{2}} - {7 \over 9 a^{2}} = \frac{5}{9} + {8 \over 9 a} - {7 \over 9 a^{2}}\)