\({6 \over 8 x} + {2 \over 8 x} = {8 \over 8 x} = {1 \over x}\)

\({8 \over a} + {9 \over 5 a} = {40 \over 5 a} + {9 \over 5 a} = {49 \over 5 a}\)

\({5 \over 9 x} - {7 \over 8 y} = {40 y \over 72 x y} - {63 x \over 72 x y} = {40 y - 63 x \over 72 x y}\)

\(7 + {4 \over 9 a} = {7 \over 1} + {4 \over 9 a} = {63 a \over 9 a} + {4 \over 9 a} = {63 a + 4 \over 9 a}\)

\({3 p \over q} - {2 \over 8 q} = {24 p \over 8 q} - {2 \over 8 q} = {24 p - 2 \over 8 q} = {12 p - 1 \over 4 q}\)

\({7 a \over a} = {7 \over 1} = 7\)

\({a \over 6 a} = {1 \over 6}\)

\({20 p \over -25 p} = -\frac{4}{5}\)

\({25 x \over -5 x} = -5\)

\({20 x y \over -32 x z} = -{5 y \over 8 z}\)

\({-16 y \over 20 x y} = -{4 \over 5 x}\)

\({-25 a b c \over 5 b c} = -5 a\)

\({2 p q \over q} + {7 p r \over r} = 2 p + 7 p = 9 p\)

\(4 x - {3 \over 7 x} = {4 x \over 1} ⋅ {7 x \over 7 x} - {3 \over 7 x} = {28 x^{2} \over 7 x} - {3 \over 7 x} = {28 x^{2} - 3 \over 7 x}\)

\({3 b \over 2 a} - {4 a \over 7 b} = {21 b^{2} \over 14 a b} - {8 a^{2} \over 14 a b} = {-8 a^{2} + 21 b^{2} \over 14 a b}\)

\({2 \over p} ⋅ -{5 \over q} = -{10 \over p q}\)

\({a \over 7} ⋅ {4 \over b} = {4 a \over 7 b}\)

\({3 \over 5} ⋅ x = {3 x \over 5}\)

\({9 y \over x} ⋅ {x + 2 \over 8} = {9 y (x + 2) \over 8 x} = {9 x y + 18 y \over 8 x}\)

\({9 \over p} : {5 \over q} = {9 \over p} ⋅ {q \over 5} = {9 q \over 5 p}\)

\({9 \over 2} : x = {9 \over 2} : {x \over 1} = {9 \over 2} ⋅ {1 \over x} = {9 \over 2 x}\)

\({6 \over 5} : {a - 7 b \over b} = {6 \over 5} ⋅ {b \over a - 7 b} = {6 b \over 5 (a - 7 b)} = {6 b \over 5 a - 35 b}\)

\({3 a \over 4} + {a - 2 \over 7} = {21 a \over 28} + {4 (a - 2) \over 28} = {21 a + 4 (a - 2) \over 28} = {25 a - 8 \over 28}\)

\({4 a + 7 \over 2 a - 3} + 6 = {4 a + 7 \over 2 a - 3} + {6 (2 a - 3) \over 2 a - 3} = {4 a + 7 + 6 (2 a - 3) \over 2 a - 3} = {4 a + 7 + 12 a - 18 \over 2 a - 3} = {16 a - 11 \over 2 a - 3}\)

\({3 a^{2} - a + 20 \over a} = {3 a^{2} \over a} - {a \over a} + {20 \over a} = 3 a - 1 + {20 \over a}\)

\({4 x^{2} - 9 x + 3 \over 5 x^{2}} = {4 x^{2} \over 5 x^{2}} - {9 x \over 5 x^{2}} + {3 \over 5 x^{2}} = \frac{4}{5} - {9 \over 5 x} + {3 \over 5 x^{2}}\)