Getal & Ruimte (13e editie) - vwo wiskunde C
'Breuken herleiden'.
| 1 vwo | 6.6 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \({5 \over 8 x} + {2 \over 8 x}\) Optellen (1) 008u - Breuken herleiden - basis - 0ms - dynamic variables a \({5 \over 8 x} + {2 \over 8 x} = {7 \over 8 x}\) 1p 1p b \({7 \over x} + {3 \over 6 x}\) Optellen (2) 008v - Breuken herleiden - basis - 0ms - dynamic variables b \({7 \over x} + {3 \over 6 x} = {42 \over 6 x} + {3 \over 6 x} = {45 \over 6 x} = {15 \over 2 x}\) 1p 1p c \({8 \over 7 a} - {6 \over 4 b}\) Optellen (3) 008w - Breuken herleiden - basis - 0ms - dynamic variables c \({8 \over 7 a} - {6 \over 4 b} = {32 b \over 28 a b} - {42 a \over 28 a b} = {32 b - 42 a \over 28 a b} = {16 b - 21 a \over 14 a b}\) 1p 1p d \(5 + {9 \over 8 p}\) Optellen (4) 008x - Breuken herleiden - basis - 0ms - dynamic variables d \(5 + {9 \over 8 p} = {5 \over 1} + {9 \over 8 p} = {40 p \over 8 p} + {9 \over 8 p} = {40 p + 9 \over 8 p}\) 1p opgave 2Herleid tot één breuk. 1p \({3 a \over b} - {2 \over 5 b}\) Optellen (6) 008z - Breuken herleiden - basis - 0ms - dynamic variables ○ \({3 a \over b} - {2 \over 5 b} = {15 a \over 5 b} - {2 \over 5 b} = {15 a - 2 \over 5 b}\) 1p opgave 3Herleid. 1p a \({4 x \over x}\) Vereenvoudigen (1) 00h5 - Breuken herleiden - basis - 0ms - dynamic variables a \({4 x \over x} = {4 \over 1} = 4\) 1p 1p b \({p \over 2 p}\) Vereenvoudigen (2) 00h6 - Breuken herleiden - basis - 0ms - dynamic variables b \({p \over 2 p} = {1 \over 2}\) 1p 1p c \({-8 a \over -28 a}\) Vereenvoudigen (3) 00h7 - Breuken herleiden - basis - 0ms - dynamic variables c \({-8 a \over -28 a} = \frac{2}{7}\) 1p 1p d \({-12 x \over 4 x}\) Vereenvoudigen (4) 00h8 - Breuken herleiden - basis - 0ms - dynamic variables d \({-12 x \over 4 x} = -3\) 1p opgave 4Herleid. 1p a \({10 a b \over 25 a c}\) Vereenvoudigen (5) 00h9 - Breuken herleiden - basis - 0ms - dynamic variables a \({10 a b \over 25 a c} = {2 b \over 5 c}\) 1p 1p b \({-32 y \over -36 x y}\) Vereenvoudigen (6) 00ha - Breuken herleiden - basis - 0ms - dynamic variables b \({-32 y \over -36 x y} = {8 \over 9 x}\) 1p 1p c \({-32 x y z \over 4 y z}\) Vereenvoudigen (7) 00hb - Breuken herleiden - basis - 0ms - dynamic variables c \({-32 x y z \over 4 y z} = -8 x\) 1p 1p d \({3 a b \over b} + {7 a c \over c}\) Vereenvoudigen (8) 00hc - Breuken herleiden - basis - 0ms - dynamic variables d \({3 a b \over b} + {7 a c \over c} = 3 a + 7 a = 10 a\) 1p |
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| 2 vwo | 1.2 Herleiden van breuken |
opgave 1Herleid tot één breuk. 1p a \(8 p + {3 \over 4 p}\) Optellen (5) 008y - Breuken herleiden - basis - 0ms - dynamic variables a \(8 p + {3 \over 4 p} = {8 p \over 1} ⋅ {4 p \over 4 p} + {3 \over 4 p} = {32 p^{2} \over 4 p} + {3 \over 4 p} = {32 p^{2} + 3 \over 4 p}\) 1p 1p b \({8 y \over 9 x} + {7 x \over 5 y}\) Optellen (7) 0090 - Breuken herleiden - basis - 0ms - dynamic variables b \({8 y \over 9 x} + {7 x \over 5 y} = {40 y^{2} \over 45 x y} + {63 x^{2} \over 45 x y} = {63 x^{2} + 40 y^{2} \over 45 x y}\) 1p 1p c \({5 \over a} ⋅ -{7 \over b}\) Vermenigvuldiging (1) 0091 - Breuken herleiden - basis - 0ms - dynamic variables c \({5 \over a} ⋅ -{7 \over b} = -{35 \over a b}\) 1p 1p d \({a \over 6} ⋅ {2 \over b}\) Vermenigvuldiging (2) 0092 - Breuken herleiden - basis - 0ms - dynamic variables d \({a \over 6} ⋅ {2 \over b} = {2 a \over 6 b} = {a \over 3 b}\) 1p opgave 2Herleid tot één breuk. 1p a \(-{3 \over 5} ⋅ x\) Vermenigvuldiging (3) 0093 - Breuken herleiden - basis - 0ms - dynamic variables a \(-{3 \over 5} ⋅ x = -{3 x \over 5}\) 1p 1p b \({5 y \over x} ⋅ {x - 8 \over 7}\) Vermenigvuldiging (4) 0094 - Breuken herleiden - basis - 0ms - dynamic variables b \({5 y \over x} ⋅ {x - 8 \over 7} = {5 y (x - 8) \over 7 x} = {5 x y - 40 y \over 7 x}\) 1p 1p c \({3 \over p} : {7 \over q}\) Deling (1) 0095 - Breuken herleiden - basis - 0ms - dynamic variables c \({3 \over p} : {7 \over q} = {3 \over p} ⋅ {q \over 7} = {3 q \over 7 p}\) 1p 1p d \(-{6 \over 7} : a\) Deling (2) 0096 - Breuken herleiden - basis - 0ms - dynamic variables d \(-{6 \over 7} : a = -{6 \over 7} : {a \over 1} = -{6 \over 7} ⋅ {1 \over a} = -{6 \over 7 a}\) 1p opgave 3Herleid tot één breuk. 1p a \({1 \over 7} : {x + 6 y \over y}\) Deling (3) 0097 - Breuken herleiden - basis - 0ms - dynamic variables a \({1 \over 7} : {x + 6 y \over y} = {1 \over 7} ⋅ {y \over x + 6 y} = {y \over 7 (x + 6 y)} = {y \over 7 x + 42 y}\) 1p 1p b \({7 a \over 3} + {a + 9 \over 8}\) Optellen (8) 0098 - Breuken herleiden - basis - 1ms - dynamic variables b \({7 a \over 3} + {a + 9 \over 8} = {56 a \over 24} + {3 (a + 9) \over 24} = {56 a + 3 (a + 9) \over 24} = {59 a + 27 \over 24}\) 1p |
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| 3 vwo | 5.3 Breuken met letters herleiden |
opgave 1Herleid tot één breuk. 1p \({-6 a + 1 \over 9 a + 4} + 5\) Optellen (9) 00eh - Breuken herleiden - basis - 1ms - dynamic variables ○ \({-6 a + 1 \over 9 a + 4} + 5 = {-6 a + 1 \over 9 a + 4} + {5 (9 a + 4) \over 9 a + 4} = {-6 a + 1 + 5 (9 a + 4) \over 9 a + 4} = {-6 a + 1 + 45 a + 20 \over 9 a + 4} = {39 a + 21 \over 9 a + 4}\) 1p |
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| vwo wiskunde A | 3.1 Breuken en verhoudingen |
opgave 1Deel uit. 1p a \({4 p^{2} - 2 p - 60 \over 2 p}\) Uitdelen (1) 00ei - Breuken herleiden - basis - 0ms - dynamic variables a \({4 p^{2} - 2 p - 60 \over 2 p} = {4 p^{2} \over 2 p} - {2 p \over 2 p} - {60 \over 2 p} = 2 p - 1 - {30 \over p}\) 1p 1p b \({7 x^{2} - 9 x + 8 \over 4 x^{2}}\) Uitdelen (2) 00ej - Breuken herleiden - basis - 0ms - dynamic variables b \({7 x^{2} - 9 x + 8 \over 4 x^{2}} = {7 x^{2} \over 4 x^{2}} - {9 x \over 4 x^{2}} + {8 \over 4 x^{2}} = 1\frac{3}{4} - {9 \over 4 x} + {2 \over x^{2}}\) 1p |