Getal & Ruimte (13e editie) - vwo wiskunde C

'Breuken herleiden'.

1 vwo 6.6 Herleiden van breuken

Breuken herleiden (13)

opgave 1

Herleid tot één breuk.

1p

a

\({5 \over 8 x} + {2 \over 8 x}\)

Optellen (1)
008u - Breuken herleiden - basis - 0ms - dynamic variables

a

\({5 \over 8 x} + {2 \over 8 x} = {7 \over 8 x}\)

1p

1p

b

\({7 \over x} + {3 \over 6 x}\)

Optellen (2)
008v - Breuken herleiden - basis - 0ms - dynamic variables

b

\({7 \over x} + {3 \over 6 x} = {42 \over 6 x} + {3 \over 6 x} = {45 \over 6 x} = {15 \over 2 x}\)

1p

1p

c

\({8 \over 7 a} - {6 \over 4 b}\)

Optellen (3)
008w - Breuken herleiden - basis - 0ms - dynamic variables

c

\({8 \over 7 a} - {6 \over 4 b} = {32 b \over 28 a b} - {42 a \over 28 a b} = {32 b - 42 a \over 28 a b} = {16 b - 21 a \over 14 a b}\)

1p

1p

d

\(5 + {9 \over 8 p}\)

Optellen (4)
008x - Breuken herleiden - basis - 0ms - dynamic variables

d

\(5 + {9 \over 8 p} = {5 \over 1} + {9 \over 8 p} = {40 p \over 8 p} + {9 \over 8 p} = {40 p + 9 \over 8 p}\)

1p

opgave 2

Herleid tot één breuk.

1p

\({3 a \over b} - {2 \over 5 b}\)

Optellen (6)
008z - Breuken herleiden - basis - 0ms - dynamic variables

\({3 a \over b} - {2 \over 5 b} = {15 a \over 5 b} - {2 \over 5 b} = {15 a - 2 \over 5 b}\)

1p

opgave 3

Herleid.

1p

a

\({4 x \over x}\)

Vereenvoudigen (1)
00h5 - Breuken herleiden - basis - 0ms - dynamic variables

a

\({4 x \over x} = {4 \over 1} = 4\)

1p

1p

b

\({p \over 2 p}\)

Vereenvoudigen (2)
00h6 - Breuken herleiden - basis - 0ms - dynamic variables

b

\({p \over 2 p} = {1 \over 2}\)

1p

1p

c

\({-8 a \over -28 a}\)

Vereenvoudigen (3)
00h7 - Breuken herleiden - basis - 0ms - dynamic variables

c

\({-8 a \over -28 a} = \frac{2}{7}\)

1p

1p

d

\({-12 x \over 4 x}\)

Vereenvoudigen (4)
00h8 - Breuken herleiden - basis - 0ms - dynamic variables

d

\({-12 x \over 4 x} = -3\)

1p

opgave 4

Herleid.

1p

a

\({10 a b \over 25 a c}\)

Vereenvoudigen (5)
00h9 - Breuken herleiden - basis - 0ms - dynamic variables

a

\({10 a b \over 25 a c} = {2 b \over 5 c}\)

1p

1p

b

\({-32 y \over -36 x y}\)

Vereenvoudigen (6)
00ha - Breuken herleiden - basis - 0ms - dynamic variables

b

\({-32 y \over -36 x y} = {8 \over 9 x}\)

1p

1p

c

\({-32 x y z \over 4 y z}\)

Vereenvoudigen (7)
00hb - Breuken herleiden - basis - 0ms - dynamic variables

c

\({-32 x y z \over 4 y z} = -8 x\)

1p

1p

d

\({3 a b \over b} + {7 a c \over c}\)

Vereenvoudigen (8)
00hc - Breuken herleiden - basis - 0ms - dynamic variables

d

\({3 a b \over b} + {7 a c \over c} = 3 a + 7 a = 10 a\)

1p

2 vwo 1.2 Herleiden van breuken

Breuken herleiden (10)

opgave 1

Herleid tot één breuk.

1p

a

\(8 p + {3 \over 4 p}\)

Optellen (5)
008y - Breuken herleiden - basis - 0ms - dynamic variables

a

\(8 p + {3 \over 4 p} = {8 p \over 1} ⋅ {4 p \over 4 p} + {3 \over 4 p} = {32 p^{2} \over 4 p} + {3 \over 4 p} = {32 p^{2} + 3 \over 4 p}\)

1p

1p

b

\({8 y \over 9 x} + {7 x \over 5 y}\)

Optellen (7)
0090 - Breuken herleiden - basis - 0ms - dynamic variables

b

\({8 y \over 9 x} + {7 x \over 5 y} = {40 y^{2} \over 45 x y} + {63 x^{2} \over 45 x y} = {63 x^{2} + 40 y^{2} \over 45 x y}\)

1p

1p

c

\({5 \over a} ⋅ -{7 \over b}\)

Vermenigvuldiging (1)
0091 - Breuken herleiden - basis - 0ms - dynamic variables

c

\({5 \over a} ⋅ -{7 \over b} = -{35 \over a b}\)

1p

1p

d

\({a \over 6} ⋅ {2 \over b}\)

Vermenigvuldiging (2)
0092 - Breuken herleiden - basis - 0ms - dynamic variables

d

\({a \over 6} ⋅ {2 \over b} = {2 a \over 6 b} = {a \over 3 b}\)

1p

opgave 2

Herleid tot één breuk.

1p

a

\(-{3 \over 5} ⋅ x\)

Vermenigvuldiging (3)
0093 - Breuken herleiden - basis - 0ms - dynamic variables

a

\(-{3 \over 5} ⋅ x = -{3 x \over 5}\)

1p

1p

b

\({5 y \over x} ⋅ {x - 8 \over 7}\)

Vermenigvuldiging (4)
0094 - Breuken herleiden - basis - 0ms - dynamic variables

b

\({5 y \over x} ⋅ {x - 8 \over 7} = {5 y (x - 8) \over 7 x} = {5 x y - 40 y \over 7 x}\)

1p

1p

c

\({3 \over p} : {7 \over q}\)

Deling (1)
0095 - Breuken herleiden - basis - 0ms - dynamic variables

c

\({3 \over p} : {7 \over q} = {3 \over p} ⋅ {q \over 7} = {3 q \over 7 p}\)

1p

1p

d

\(-{6 \over 7} : a\)

Deling (2)
0096 - Breuken herleiden - basis - 0ms - dynamic variables

d

\(-{6 \over 7} : a = -{6 \over 7} : {a \over 1} = -{6 \over 7} ⋅ {1 \over a} = -{6 \over 7 a}\)

1p

opgave 3

Herleid tot één breuk.

1p

a

\({1 \over 7} : {x + 6 y \over y}\)

Deling (3)
0097 - Breuken herleiden - basis - 0ms - dynamic variables

a

\({1 \over 7} : {x + 6 y \over y} = {1 \over 7} ⋅ {y \over x + 6 y} = {y \over 7 (x + 6 y)} = {y \over 7 x + 42 y}\)

1p

1p

b

\({7 a \over 3} + {a + 9 \over 8}\)

Optellen (8)
0098 - Breuken herleiden - basis - 1ms - dynamic variables

b

\({7 a \over 3} + {a + 9 \over 8} = {56 a \over 24} + {3 (a + 9) \over 24} = {56 a + 3 (a + 9) \over 24} = {59 a + 27 \over 24}\)

1p

3 vwo 5.3 Breuken met letters herleiden

Breuken herleiden (1)

opgave 1

Herleid tot één breuk.

1p

\({-6 a + 1 \over 9 a + 4} + 5\)

Optellen (9)
00eh - Breuken herleiden - basis - 1ms - dynamic variables

\({-6 a + 1 \over 9 a + 4} + 5 = {-6 a + 1 \over 9 a + 4} + {5 (9 a + 4) \over 9 a + 4} = {-6 a + 1 + 5 (9 a + 4) \over 9 a + 4} = {-6 a + 1 + 45 a + 20 \over 9 a + 4} = {39 a + 21 \over 9 a + 4}\)

1p

vwo wiskunde A 3.1 Breuken en verhoudingen

Breuken herleiden (2)

opgave 1

Deel uit.

1p

a

\({4 p^{2} - 2 p - 60 \over 2 p}\)

Uitdelen (1)
00ei - Breuken herleiden - basis - 0ms - dynamic variables

a

\({4 p^{2} - 2 p - 60 \over 2 p} = {4 p^{2} \over 2 p} - {2 p \over 2 p} - {60 \over 2 p} = 2 p - 1 - {30 \over p}\)

1p

1p

b

\({7 x^{2} - 9 x + 8 \over 4 x^{2}}\)

Uitdelen (2)
00ej - Breuken herleiden - basis - 0ms - dynamic variables

b

\({7 x^{2} - 9 x + 8 \over 4 x^{2}} = {7 x^{2} \over 4 x^{2}} - {9 x \over 4 x^{2}} + {8 \over 4 x^{2}} = 1\frac{3}{4} - {9 \over 4 x} + {2 \over x^{2}}\)

1p

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