\({1 \over x^3}=x^{-3}\)

\({2a^4 \over 7a^8}={2 \over 7}⋅{a^4 \over a^8}={2 \over 7}⋅a^{4-8}={2 \over 7}a^{-4}\)

\({a^8 \over a^{-4}}=a^{8--4}=a^{12}\)

\(p^2⋅p^{-4}=p^{2+-4}=p^{-2}\)

\((x^6)^{-2}=x^{6⋅-2}=x^{-12}\)

\(x^2⋅{1 \over x^5}=x^2⋅x^{-5}=x^{2+-5}=x^{-3}\)

\({a^0 \over a^5}=a^{0-5}=a^{-5}\)

\({9 \over p^2}\)

\((2a)^{-5}=2^{-5}⋅a^{-5}={1 \over 2^5}⋅{1 \over a^5}={1 \over 32a^5}\)

\(a^2⋅\sqrt[4]{a}=a^2⋅a^{\frac{1}{4}}=a^{2+\frac{1}{4}}=a^{2\frac{1}{4}}\)

\(x^4⋅\sqrt[9]{x^8}=x^4⋅x^{\frac{8}{9}}=x^{4+\frac{8}{9}}=x^{4\frac{8}{9}}\)

\({x^8 \over \sqrt[5]{x^4}}={x^8 \over x^{\frac{4}{5}}}=x^{8-\frac{4}{5}}=x^{7\frac{1}{5}}\)

\({1 \over p^9}⋅\sqrt[5]{p^4}=p^{-9}⋅p^{\frac{4}{5}}=p^{-9+\frac{4}{5}}=p^{-8\frac{1}{5}}\)

\({\sqrt[9]{a^8} \over \sqrt[4]{a^3}}={a^{\frac{8}{9}} \over a^{\frac{3}{4}}}=a^{\frac{8}{9}-\frac{3}{4}}=a^{\frac{5}{36}}\)

\(\sqrt[4]{x^{20}}=x^{\frac{20}{4}}=x^5\)

\({a^8 \over a^2⋅\sqrt[7]{a^3}}={a^8 \over a^2⋅a^{\frac{3}{7}}}={a^8 \over a^{2\frac{3}{7}}}=a^{8-2\frac{3}{7}}=a^{5\frac{4}{7}}\)

\(6x^{9\frac{5}{6}}=6⋅x^9⋅x^{\frac{5}{6}}=6x^9⋅\sqrt[6]{x^5}\)