Moderne Wiskunde (13e editie) - 2 vmbo gt(h)

'Rekenvolgorde'.

2 vmbo gt(h) 1.5 Rekenvolgorde

Rekenvolgorde (8)

opgave 1

Bereken.

1p

a

\(80 : 2 : 5\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(80 : 2 : 5 = 40 : 5 = 8 \text{.}\)

1p

1p

b

\(7 + 3 ⋅ 5\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(7 + 3 ⋅ 5 = 7 + 15 = 22 \text{.}\)

1p

1p

c

\((8 + 2) ⋅ 9\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((8 + 2) ⋅ 9 = 10 ⋅ 9 = 90 \text{.}\)

1p

1p

d

\(16 : 8 ⋅ 5\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(16 : 8 ⋅ 5 = 2 ⋅ 5 = 10 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(5 - 8 : 2\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(5 - 8 : 2 = 5 - 4 = 1 \text{.}\)

1p

1p

b

\(6 + 3 ⋅ (7 + 4)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(6 + 3 ⋅ (7 + 4) = 6 + 3 ⋅ 11 = 6 + 33 = 39 \text{.}\)

1p

1p

c

\((5 + 6) ⋅ (4 + 8)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((5 + 6) ⋅ (4 + 8) = 11 ⋅ 12 = 132 \text{.}\)

1p

1p

d

\(19 - 2 ⋅ 5 + 6\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(19 - 2 ⋅ 5 + 6 = 19 - 10 + 6 = 9 + 6 = 15 \text{.}\)

1p
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