Moderne Wiskunde (13e editie) - 2 vmbo gt(h)

'Rekenvolgorde'.

2 vmbo gt(h) 1.5 Rekenvolgorde

Rekenvolgorde (8)

opgave 1

Bereken.

1p

a

\(30 : 5 : 3\)

PositiefDrieDelen (1)
00ah - Rekenvolgorde - basis - 0ms

a

\(30 : 5 : 3 = 6 : 3 = 2 \text{.}\)

1p

1p

b

\(4 + 2 ⋅ 3\)

PositiefDrieDelen (2)
00ai - Rekenvolgorde - basis - 0ms

b

\(4 + 2 ⋅ 3 = 4 + 6 = 10 \text{.}\)

1p

1p

c

\((8 + 9) ⋅ 4\)

PositiefDrieDelen (3)
00aj - Rekenvolgorde - basis - 0ms

c

\((8 + 9) ⋅ 4 = 17 ⋅ 4 = 68 \text{.}\)

1p

1p

d

\(54 : 9 ⋅ 4\)

PositiefDrieDelen (4)
00ak - Rekenvolgorde - basis - 0ms

d

\(54 : 9 ⋅ 4 = 6 ⋅ 4 = 24 \text{.}\)

1p

opgave 2

Bereken.

1p

a

\(7 - 18 : 3\)

PositiefDrieDelen (5)
00al - Rekenvolgorde - basis - 0ms

a

\(7 - 18 : 3 = 7 - 6 = 1 \text{.}\)

1p

1p

b

\(8 + 3 ⋅ (6 + 5)\)

PositiefVierDelen (1)
00am - Rekenvolgorde - basis - 0ms

b

\(8 + 3 ⋅ (6 + 5) = 8 + 3 ⋅ 11 = 8 + 33 = 41 \text{.}\)

1p

1p

c

\((4 + 2) ⋅ (8 + 3)\)

PositiefVierDelen (2)
00an - Rekenvolgorde - basis - 0ms

c

\((4 + 2) ⋅ (8 + 3) = 6 ⋅ 11 = 66 \text{.}\)

1p

1p

d

\(28 - 4 ⋅ 5 + 9\)

PositiefVierDelen (3)
00ao - Rekenvolgorde - basis - 0ms

d

\(28 - 4 ⋅ 5 + 9 = 28 - 20 + 9 = 8 + 9 = 17 \text{.}\)

1p
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