Moderne Wiskunde (13e editie) - 2 vmbo gt(h)
'Rekenvolgorde'.
| 2 vmbo gt(h) | 1.5 Rekenvolgorde |
opgave 1Bereken. 1p a \(56 : 4 : 2\) PositiefDrieDelen (1) 00ah - Rekenvolgorde - basis - 1ms a \(56 : 4 : 2 = 14 : 2 = 7 \text{.}\) 1p 1p b \(5 + 3 ⋅ 4\) PositiefDrieDelen (2) 00ai - Rekenvolgorde - basis - 1ms b \(5 + 3 ⋅ 4 = 5 + 12 = 17 \text{.}\) 1p 1p c \((6 + 3) ⋅ 7\) PositiefDrieDelen (3) 00aj - Rekenvolgorde - basis - 0ms c \((6 + 3) ⋅ 7 = 9 ⋅ 7 = 63 \text{.}\) 1p 1p d \(15 : 5 ⋅ 9\) PositiefDrieDelen (4) 00ak - Rekenvolgorde - basis - 0ms d \(15 : 5 ⋅ 9 = 3 ⋅ 9 = 27 \text{.}\) 1p opgave 2Bereken. 1p a \(9 - 30 : 5\) PositiefDrieDelen (5) 00al - Rekenvolgorde - basis - 0ms a \(9 - 30 : 5 = 9 - 6 = 3 \text{.}\) 1p 1p b \(2 + 3 ⋅ (7 + 6)\) PositiefVierDelen (1) 00am - Rekenvolgorde - basis - 0ms b \(2 + 3 ⋅ (7 + 6) = 2 + 3 ⋅ 13 = 2 + 39 = 41 \text{.}\) 1p 1p c \((2 + 8) ⋅ (7 + 4)\) PositiefVierDelen (2) 00an - Rekenvolgorde - basis - 0ms c \((2 + 8) ⋅ (7 + 4) = 10 ⋅ 11 = 110 \text{.}\) 1p 1p d \(26 - 3 ⋅ 6 + 7\) PositiefVierDelen (3) 00ao - Rekenvolgorde - basis - 0ms d \(26 - 3 ⋅ 6 + 7 = 26 - 18 + 7 = 8 + 7 = 15 \text{.}\) 1p |