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a

\(\frac{4}{7}:\frac{3}{7}=\frac{4}{7}⋅\frac{7}{3}=\frac{28}{21}=\frac{4}{3}=1\frac{1}{3}\)

1p

a

\(-2\frac{2}{5}:\frac{1}{7}=-\frac{12}{5}:\frac{1}{7}=-\frac{12}{5}⋅\frac{7}{1}=-\frac{84}{5}=-16\frac{4}{5}\)

1p

a

\(-5\frac{1}{3}:-2\frac{1}{5}=-\frac{16}{3}:-\frac{11}{5}=-\frac{16}{3}⋅-\frac{5}{11}=\frac{80}{33}=2\frac{14}{33}\)

1p

a

\(-\frac{2}{7}:3=-\frac{2}{7}:\frac{3}{1}=-\frac{2}{7}⋅\frac{1}{3}=-\frac{2}{21}\)

1p

a

\(1\frac{1}{5}-3\frac{3}{5}=\frac{6}{5}-\frac{18}{5}=-\frac{12}{5}=-2\frac{2}{5}\)

1p

a

\(\frac{4}{7}-\frac{4}{5}={20 \over 35}-{28 \over 35}=-\frac{8}{35}\)

1p

a

\(-\frac{1}{6}+\frac{2}{3}={-1 \over 6}+{4 \over 6}=\frac{3}{6}=\frac{1}{2}\)

1p

a

\(-1\frac{1}{4}+2\frac{5}{6}=-\frac{5}{4}+\frac{17}{6}={-15 \over 12}+{34 \over 12}=\frac{19}{12}=1\frac{7}{12}\)

1p

a

\(\frac{1}{3}⋅-\frac{4}{9}=-\frac{4}{27}\)

1p

a

\(-4\frac{1}{3}⋅-\frac{1}{3}=-\frac{13}{3}⋅-\frac{1}{3}=\frac{13}{9}=1\frac{4}{9}\)

1p

a

\(-1\frac{3}{4}⋅1\frac{3}{5}=-\frac{7}{4}⋅\frac{8}{5}=-\frac{56}{20}=-\frac{14}{5}=-2\frac{4}{5}\)

1p

a

\(2⋅\frac{2}{5}=\frac{2}{1}⋅\frac{2}{5}=\frac{4}{5}\)

1p