Stelling van Pythagoras
13 - 2 oefeningen
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Pythagoras (1)
007c - basis
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Getal & Ruimte (13e editie) - 2 havo/vwo - 6.2 Getal & Ruimte (13e editie) - 2 vwo - 6.2 |
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3p a Gegeven is \(\triangle PQR\) met \(PR=34\text{,}\) \(PQ=55\) en \(\angle P=90\degree\text{.}\) |
a Pythagoras in \(\triangle PQR\) geeft \(PR^2+PQ^2=QR^2\text{.}\) 1p \(QR^2=34^2+55^2=4\,181\text{.}\) 1p \(QR=\sqrt{4\,181}≈64{,}7\text{.}\) 1p |
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Pythagoras (2)
007d - basis
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Getal & Ruimte (13e editie) - 2 havo/vwo - 6.3 Getal & Ruimte (13e editie) - 2 vwo - 6.3 |
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3p a Gegeven is \(\triangle ABC\) met \(BC=36\text{,}\) \(AB=51\) en \(\angle C=90\degree\text{.}\) |
a Pythagoras in \(\triangle ABC\) geeft \(BC^2+AC^2=AB^2\) ofwel \(36^2+AC^2=51^2\text{.}\) 1p \(AC^2=51^2-36^2=1\,305\text{.}\) 1p \(AC=\sqrt{1\,305}≈36{,}1\text{.}\) 1p |